A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • one year ago

Need Help Given 21x^3-3x^2=0 , which values of x will satisfy the equation? (Hint: Factor the polynomial into two terms, and find the values of x that will make each term 0.) A. x = 0 and x = –7 B. x = 0 and x = 7 C. x=0 and x=-1/7 D. x=0 and x=1/7

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The two terms of this equation, \(21x^3\) and \(3x^2\), have common factors. If you factor each term first, you can see all the common factors: \(21x^3=3\cdot7\cdot x \cdot x\cdot x\) \(3x^2=3 \cdot x \cdot x\). You can factor out the common factors (which are 3, x and x, obviously). Now you have \(3x^2(7x-1)=0\). The equation now consists of two FACTORS and not terms btw. So solve \(3x^2=0\) and \(7x-1=0\) to find the right answer...

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.