## anonymous one year ago Need Help Given 21x^3-3x^2=0 , which values of x will satisfy the equation? (Hint: Factor the polynomial into two terms, and find the values of x that will make each term 0.) A. x = 0 and x = –7 B. x = 0 and x = 7 C. x=0 and x=-1/7 D. x=0 and x=1/7

The two terms of this equation, $$21x^3$$ and $$3x^2$$, have common factors. If you factor each term first, you can see all the common factors: $$21x^3=3\cdot7\cdot x \cdot x\cdot x$$ $$3x^2=3 \cdot x \cdot x$$. You can factor out the common factors (which are 3, x and x, obviously). Now you have $$3x^2(7x-1)=0$$. The equation now consists of two FACTORS and not terms btw. So solve $$3x^2=0$$ and $$7x-1=0$$ to find the right answer...