A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

Find the 6th term of a geometric sequence with t1 = 7 and t9 = 45,927.

  • This Question is Closed
  1. kropot72
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    The formula for the n-th term of a geometric sequence is given by: \[\large ar^{n-1}\] where a is the first term and r is the common difference. When we plug in the given values, and knowing the value of the ninth term, we can write: \[\large 45927=7r^{9-1}...........(1)\] Now you need to solve equation (1) to find the value of r, the common difference.

  2. kropot72
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Rearranging equation (1) gives: \[\large r^{8}=6561\] and the value of r is given by: \[\large r=\sqrt[8]{6561}\]

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.