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anonymous
 one year ago
A rectangular field is enclosed by afence and divided into two smaller plots by a fence parallel to one of the sides. find the dimensions of the largest such field 1200m of fencing is avable
anonymous
 one year ago
A rectangular field is enclosed by afence and divided into two smaller plots by a fence parallel to one of the sides. find the dimensions of the largest such field 1200m of fencing is avable

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@sasogeek @whpalmer4

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433831834735:dwHere is an illustration of what is being described.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1We are given a constraint on the `perimeter`, amount of fencing. Err I guess perimeter is usually regarded as the distance around the outside. So we're talking about the perimeter plus this inner separator as well :p whatev \[\Large\rm P=3\ell + 2w\]That gives us our perimeter, ya? The constraint they gave us is that we have only 1200m of fencing to work with.\[\Large\rm 1200=3\ell + 2w\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Use your constraint to write \(\Large\rm w\) in terms of \(\Large\rm \ell\), (or the other way around if you like). Then realize what you're trying to maximize, area. Area of this rectangle is going to be simply:\[\Large\rm A=\ell\cdot w\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Using your constraint, replace your \(\Large\rm w\) in the area formula with some \(\Large\rm \ell\) stuff. From that point, since you now have your area function in terms of `one variable`, you can differentiate and look for critical points.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Hmm you've gone offline, hopefully that will help you get started at least :)
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