Quadrilateral ABCD is located at A (−2, 2), B (−2, 4), C (2, 4), and D (2, 2). The quadrilateral is then transformed using the rule (x−3, y+4) to form the image A'B'C'D'. What are the new coordinates of A', B', C', and D'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.

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Quadrilateral ABCD is located at A (−2, 2), B (−2, 4), C (2, 4), and D (2, 2). The quadrilateral is then transformed using the rule (x−3, y+4) to form the image A'B'C'D'. What are the new coordinates of A', B', C', and D'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.

Mathematics
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To get the coordinates of transformed image, `subtract 3 from each x coordinate` and `add 4 to each y coordinate`
A = (−2, 2) becomes A' = (−2\(\color{Red}{-3}\), 2\(\color{Red}{+4}\)) = (-5, 6)

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similarly see if you can find the new coordinates of remaining vertices
oh ok so for A=(-5,6) B= (-5,0) C=(5,0) D=(5,6)
doesn't look correct try again
keep in mind, the transformation is \((x-3, y+4)\) so you need to subtract 3 from x coordinate and add 4 to y coordinate
oh ok A= (-5,6) B= (-1,8) C= (1,8) D=(1,6 @ganeshie8 im to sure if this is right sorry im trying my best
I dont know if I did It right or not
@ganeshie8 please please help me
Hey sry im back still here ?
yea im still here
you should get A' = (-5, 6) B' = (-5, 8) C' = (-1, 8) D' = (-1, 6)
oh ok thank you so much im really sorry for all the trouble, but I have one last question can you Describe what characteristics you would find if the corresponding vertices were connected with line segments.
The line segments formed by joining corresponding vertices will be parallel because they all will be having the same slopes
What are you having trouble with he seems that he helped you

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