anonymous
  • anonymous
In triangle FGH, FH=7feet FG=12feet and measurement F=70 degrees. Find measurement G round to the nearest tenth
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@wolf1728 @Astrophysics
wolf1728
  • wolf1728
Hello !!! I got "bumped" and I entered this topic!!!
anonymous
  • anonymous
|dw:1433834150459:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
yay and did I do that correctly?
wolf1728
  • wolf1728
I guess you did (and good diagram)
anonymous
  • anonymous
Thats what I meant *did i do the diagram correctly*
wolf1728
  • wolf1728
Yes you did!!
wolf1728
  • wolf1728
Where's Astro?
anonymous
  • anonymous
@Astrophysics
anonymous
  • anonymous
not sure
anonymous
  • anonymous
can you help me get it started and i do it and you tell me if im doing it wrong or not
anonymous
  • anonymous
you guys there?
wolf1728
  • wolf1728
Two sides and included angle, we use Law of Cosines
1 Attachment
Astrophysics
  • Astrophysics
This should not be a right triangle
Astrophysics
  • Astrophysics
Otherwise we could just say it's 20 degrees ;)
wolf1728
  • wolf1728
b=7 c =12 Angle A=70 degrees a^2 = (b^2 + c^2) -(2*b*c * cos(A))
Astrophysics
  • Astrophysics
You can use the sine law
anonymous
  • anonymous
So one side should be longer...i was thinking the same! but 20 isnt a answer choice!
Astrophysics
  • Astrophysics
That would be a whole lot easier
anonymous
  • anonymous
that is what wolf included correct
Astrophysics
  • Astrophysics
Not quite, he is using cosine law
Astrophysics
  • Astrophysics
But, I will let wolf continue :)
anonymous
  • anonymous
does it matter which one is used or?
wolf1728
  • wolf1728
a^2 = 7^2 + 12^2 -(2*7*12*cos(70) a^2 = 49 + 144 - (108*.34202) a^2 = 193 -36.93816 a^2 = 156.06184 a = sq root(156.06184) a = 12.49
anonymous
  • anonymous
I dont think thats correct its not a choice I have maybe we have to use Cos*b*
anonymous
  • anonymous
hold on im looking
wolf1728
  • wolf1728
How about 11.642 ?
anonymous
  • anonymous
how did you get that
anonymous
  • anonymous
its one of the answers but I am trying to learn
Astrophysics
  • Astrophysics
Well lets redraw the triangle and put everything in place, and continue from there |dw:1433835265958:dw|
Astrophysics
  • Astrophysics
Oh I guess wolf already did it xD
anonymous
  • anonymous
Ok I was just a little off on the graph
wolf1728
  • wolf1728
a^2 = 49 + 144 - (168*.34202) a^2 = 193 - (57.45936) a^2=135.54064 a = 11.6421922334 ARRGGGHHHH !!!!!!!!!!! The other time I made an arithmetic mistake.
Astrophysics
  • Astrophysics
I try not to make right triangles, but always end up doing so haha, and good job wolf I believe in you! :P
wolf1728
  • wolf1728
was 11.642 an answer?
anonymous
  • anonymous
11.6 yes
wolf1728
  • wolf1728
all right !!!!!!!!!!!!!!!!
Astrophysics
  • Astrophysics
Alright cool! :)
Astrophysics
  • Astrophysics
Did you understand everything, sorry about the first question it was a bit messy, I'll go look at it again later...
anonymous
  • anonymous
wait dont go anywhere I am gonna show you the work for a problem and I just would like for you to check
anonymous
  • anonymous
slowly but surely I know a lot more than I did before I came here
wolf1728
  • wolf1728
all right !!
anonymous
  • anonymous
Okay so Im finding the area of a triangle and it looks like
anonymous
  • anonymous
|dw:1433835840125:dw|
anonymous
  • anonymous
so I did 12^2-7^2=b and got 144-49=95
wolf1728
  • wolf1728
There is a side angle side formula for triangle area Area = (1/2) * side 1 * sine (included angle) * side 2
anonymous
  • anonymous
then i did sin*40*95 and got 61.6 and divided it by 2 and got 30.53
wolf1728
  • wolf1728
Using side angle side formula I get 26.997
anonymous
  • anonymous
that was my second choice, when my calculator was on rads i got a different answer than I did when it was on degrees I just didn't know which I should have been on
wolf1728
  • wolf1728
You were using the formula?
anonymous
  • anonymous
I had seen another question similar to this and I was following along but with my question instead
wolf1728
  • wolf1728
You can find a side angle side triangle area calculator here http://www.1728.org/triang.htm (It's my own website)
anonymous
  • anonymous
Really???!!! thats so cool! I'm gonna check it out! and If you dont mind checking 2 more questions with me
wolf1728
  • wolf1728
Wow - two more?? Well I'll try - go ahead
anonymous
  • anonymous
im sorry I just want to understand it and the calculator isnt working....ill add more to your testimonial
wolf1728
  • wolf1728
okay - by the way my site has got about 250 pages I'd say half the pages are all kinds of calculators
anonymous
  • anonymous
\[\sin ^{2} \Theta \over 1- \cos \theta \]
anonymous
  • anonymous
have to simplify it
anonymous
  • anonymous
I am going to keep that site itll help me a lot
wolf1728
  • wolf1728
Hmmmm that's probably a trigonometric identity. (I'm glad you like my site).
anonymous
  • anonymous
can you help?
anonymous
  • anonymous
I have answer choices if its easier
wolf1728
  • wolf1728
I was just doing a web search for trig identities. Maybe I can solve it myself.
anonymous
  • anonymous
I belive you can youve been doing great i feel im in comfortable hands
wolf1728
  • wolf1728
sine(angle) = y/hypotenuse cosine = x/hyp
anonymous
  • anonymous
theres no triangle its just says to simplify the trigonomic equation
anonymous
  • anonymous
im looking up trig identies
wolf1728
  • wolf1728
Okay and I made a quick graphic
1 Attachment
anonymous
  • anonymous
\[http://www.math.com/tables/trig/identities.htm would this help\]
wolf1728
  • wolf1728
okay let me see that page in the meantime, I started with this sine^2 = (y^2 / hyp^2) 1 - cos = (1 -x/hyp)
anonymous
  • anonymous
does it help?
wolf1728
  • wolf1728
Yes I think I found something
anonymous
  • anonymous
where at
anonymous
  • anonymous
I might have found something too
wolf1728
  • wolf1728
Almost at the top of the page they state: sin^2(x) + cos^2(x) = 1 and you have to simplify sin^2(Θ) / (1−cos(θ))
anonymous
  • anonymous
like this sin^2 (a) * (1 + cos(a)) / (1 - cos^2 (a)) = 1 + cos(a
wolf1728
  • wolf1728
sin^2(x) + cos^2(x) = 1 Therefore, sin^2(x) = 1 -cos^2(x) SO, we can say sin^2(Θ) / (1−cos(θ)) equals (1 -cos^2(x)) / (1 - cos(x))
wolf1728
  • wolf1728
Hmmm now to simplify that
anonymous
  • anonymous
which seems tricky
anonymous
  • anonymous
the -cos 2 and the cos would leave one -cos right?
wolf1728
  • wolf1728
I don't know - that would be considered "cancelling terms" which should NOT be done. I got: (1 -cos^2(x)) / (1 - cos(x)) = (1 - (cos(x) * cos(x))) / (1 -cos(x))
anonymous
  • anonymous
theres a discrepancy here somewhere
anonymous
  • anonymous
Ill keep looking at it and I will message you if there was something wrong with the question...youve helped me a lot I dont want you to feel like im over doing it
anonymous
  • anonymous
whats your name btw?
wolf1728
  • wolf1728
I'm thinking of trying one more thing - actuallly calculating values of sine and cosine My name is Robert - but wolf is okay too
anonymous
  • anonymous
Mucho Gusto! and how are you going to do that? im summer and sorry my computer froze up
wolf1728
  • wolf1728
Okay I looked up sine 35 degrees 0.57358 squaring that we get 0.3289940164 cosine 35 degrees = 0.81915 1 minus that = 0.18085 sine 45 degrees 0.70711 squaring that 0.5000045521 cosine 45 degrees 0.70711 1 minus that = 0.29289 Well, that doesn't show much does it? Maybe it's time to quit.
anonymous
  • anonymous
lol maybe our brains are fried!
wolf1728
  • wolf1728
Yes, we've been doing this stuff for about 2 hours?
anonymous
  • anonymous
roughly yes lol...are you tired?
wolf1728
  • wolf1728
Yes I am tired - think I'll call it a night.
wolf1728
  • wolf1728
whoops - just got "bumped" from openstudy
anonymous
  • anonymous
Alright goodnight and ill let my mom know you helped me im sure shell do a better testimonial
anonymous
  • anonymous
what does that mean
wolf1728
  • wolf1728
that's okay - and thanks. Might as well get going. It was good meeting you SweetiePie
wolf1728
  • wolf1728
"bumped" means getting tossed off openstudy
anonymous
  • anonymous
oh im sorry i hope it wasnt my fault
wolf1728
  • wolf1728
no - sometimes it just happens
anonymous
  • anonymous
sweetie pies daughter
anonymous
  • anonymous
welll im gonna let you go i really appreciate all the help night
wolf1728
  • wolf1728
Thank you and I was glad to help - see you later
anonymous
  • anonymous
:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.