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anonymous
 one year ago
In triangle FGH, FH=7feet FG=12feet and measurement F=70 degrees. Find measurement G round to the nearest tenth
anonymous
 one year ago
In triangle FGH, FH=7feet FG=12feet and measurement F=70 degrees. Find measurement G round to the nearest tenth

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@wolf1728 @Astrophysics

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2Hello !!! I got "bumped" and I entered this topic!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433834150459:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay and did I do that correctly?

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2I guess you did (and good diagram)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thats what I meant *did i do the diagram correctly*

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you help me get it started and i do it and you tell me if im doing it wrong or not

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2Two sides and included angle, we use Law of Cosines

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0This should not be a right triangle

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Otherwise we could just say it's 20 degrees ;)

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2b=7 c =12 Angle A=70 degrees a^2 = (b^2 + c^2) (2*b*c * cos(A))

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0You can use the sine law

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So one side should be longer...i was thinking the same! but 20 isnt a answer choice!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0That would be a whole lot easier

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is what wolf included correct

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Not quite, he is using cosine law

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0But, I will let wolf continue :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0does it matter which one is used or?

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2a^2 = 7^2 + 12^2 (2*7*12*cos(70) a^2 = 49 + 144  (108*.34202) a^2 = 193 36.93816 a^2 = 156.06184 a = sq root(156.06184) a = 12.49

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I dont think thats correct its not a choice I have maybe we have to use Cos*b*

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how did you get that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its one of the answers but I am trying to learn

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Well lets redraw the triangle and put everything in place, and continue from there dw:1433835265958:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Oh I guess wolf already did it xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok I was just a little off on the graph

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2a^2 = 49 + 144  (168*.34202) a^2 = 193  (57.45936) a^2=135.54064 a = 11.6421922334 ARRGGGHHHH !!!!!!!!!!! The other time I made an arithmetic mistake.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0I try not to make right triangles, but always end up doing so haha, and good job wolf I believe in you! :P

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2was 11.642 an answer?

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2all right !!!!!!!!!!!!!!!!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Did you understand everything, sorry about the first question it was a bit messy, I'll go look at it again later...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait dont go anywhere I am gonna show you the work for a problem and I just would like for you to check

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0slowly but surely I know a lot more than I did before I came here

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so Im finding the area of a triangle and it looks like

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433835840125:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I did 12^27^2=b and got 14449=95

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2There is a side angle side formula for triangle area Area = (1/2) * side 1 * sine (included angle) * side 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then i did sin*40*95 and got 61.6 and divided it by 2 and got 30.53

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2Using side angle side formula I get 26.997

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that was my second choice, when my calculator was on rads i got a different answer than I did when it was on degrees I just didn't know which I should have been on

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2You were using the formula?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I had seen another question similar to this and I was following along but with my question instead

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2You can find a side angle side triangle area calculator here http://www.1728.org/triang.htm (It's my own website)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Really???!!! thats so cool! I'm gonna check it out! and If you dont mind checking 2 more questions with me

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2Wow  two more?? Well I'll try  go ahead

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im sorry I just want to understand it and the calculator isnt working....ill add more to your testimonial

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2okay  by the way my site has got about 250 pages I'd say half the pages are all kinds of calculators

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sin ^{2} \Theta \over 1 \cos \theta \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am going to keep that site itll help me a lot

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2Hmmmm that's probably a trigonometric identity. (I'm glad you like my site).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have answer choices if its easier

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2I was just doing a web search for trig identities. Maybe I can solve it myself.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I belive you can youve been doing great i feel im in comfortable hands

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2sine(angle) = y/hypotenuse cosine = x/hyp

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0theres no triangle its just says to simplify the trigonomic equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im looking up trig identies

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2Okay and I made a quick graphic

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[ http://www.math.com/tables/trig/identities.htm would this help\]

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2okay let me see that page in the meantime, I started with this sine^2 = (y^2 / hyp^2) 1  cos = (1 x/hyp)

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2Yes I think I found something

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I might have found something too

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2Almost at the top of the page they state: sin^2(x) + cos^2(x) = 1 and you have to simplify sin^2(Θ) / (1−cos(θ))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0like this sin^2 (a) * (1 + cos(a)) / (1  cos^2 (a)) = 1 + cos(a

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2sin^2(x) + cos^2(x) = 1 Therefore, sin^2(x) = 1 cos^2(x) SO, we can say sin^2(Θ) / (1−cos(θ)) equals (1 cos^2(x)) / (1  cos(x))

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2Hmmm now to simplify that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the cos 2 and the cos would leave one cos right?

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2I don't know  that would be considered "cancelling terms" which should NOT be done. I got: (1 cos^2(x)) / (1  cos(x)) = (1  (cos(x) * cos(x))) / (1 cos(x))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0theres a discrepancy here somewhere

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ill keep looking at it and I will message you if there was something wrong with the question...youve helped me a lot I dont want you to feel like im over doing it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whats your name btw?

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2I'm thinking of trying one more thing  actuallly calculating values of sine and cosine My name is Robert  but wolf is okay too

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Mucho Gusto! and how are you going to do that? im summer and sorry my computer froze up

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2Okay I looked up sine 35 degrees 0.57358 squaring that we get 0.3289940164 cosine 35 degrees = 0.81915 1 minus that = 0.18085 sine 45 degrees 0.70711 squaring that 0.5000045521 cosine 45 degrees 0.70711 1 minus that = 0.29289 Well, that doesn't show much does it? Maybe it's time to quit.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol maybe our brains are fried!

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2Yes, we've been doing this stuff for about 2 hours?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0roughly yes lol...are you tired?

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2Yes I am tired  think I'll call it a night.

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2whoops  just got "bumped" from openstudy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright goodnight and ill let my mom know you helped me im sure shell do a better testimonial

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2that's okay  and thanks. Might as well get going. It was good meeting you SweetiePie

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2"bumped" means getting tossed off openstudy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh im sorry i hope it wasnt my fault

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2no  sometimes it just happens

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sweetie pies daughter

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0welll im gonna let you go i really appreciate all the help night

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.2Thank you and I was glad to help  see you later
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