Write an equation of a line that passes through the point (2, 3) and is parallel to the line y = 2/3 x + 5.

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Write an equation of a line that passes through the point (2, 3) and is parallel to the line y = 2/3 x + 5.

Mathematics
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y = -2/3 x y =-2/3 x − 7 y = 3/2 x y = 3/2 x + 7
My sis told me u need help
yeah could you help me this question

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y = 2 3x + 5 Is this the equation of the line?
i do not know
What is the first equation the question gives you : ) Sorry, it is a bit hard to interpret your question ><
Write an equation of a line that passes through the point (2, 3) and is parallel to the line y = 2/3 x + 5. this is the question so i think the first equation would be y=2/3x+5
Okay, so your previous working out, involves making y the subject, is correct notice how the coefficient in front of x is the gradient
So from: y = 3/2 x + 7 m = 3 /2 With this passing through the point (2,3) remember your point-gradient formula y - y1 = m (x -x1)
what is y and what is x?
wait is the answer y+3/2 x + 7?
x1 and y1 are from your point (2,1) where 2 represents the x value and 1 is the y value
I haven't worked it out, give me a moment
  • rvc
to revise : Basic Straight Lines http://openstudy.com/study#/updates/554cca3ee4b075612122616a go to the above link :)
I got y = 3x - 4 2
A: y = -2/3 x B:y =-2/3 x − 7 C:y = 3/2 x D:y = 3/2 x + 7 these are the answer choices
I think we may have misinterpreted out gradient value of 3/2, I rechecked it again an i got 2/3 through working out, my outcome was: y = 2x -1 3
thank you
Alright no worries

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