A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Does anyone know how to add and subtract rational expressions? help very last assignment D:
anonymous
 one year ago
Does anyone know how to add and subtract rational expressions? help very last assignment D:

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its an assignment I have to do, but its all about adding and subtracting rational expression, only 5 problems

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it ok if i do one problem and show you to make sure im not doing anything wrong?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5I think the other user is afk or something

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ill draw a picture of it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433843733453:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5hmmm... they share a common denominator so all we have to do is to combine like terms in the numerator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How would we do that? would we add 2x to x and 1 to the other 1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would the numerator come out like this = 2x^2+2 or 3x+2

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5it would be 3x+2. because 2x+x = 3x 1 + 1 =2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok! thanks, can you help with four more adding/subracting q's?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thankyou so much! so the next question basically wants me to use the answer we just got (3x+2/2x) subtracted by x/x+3, but it also says to * identify any possible restrictions that exist with (or in) the resulting rational expression*

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\frac{3x+2}{2x}\frac{x}{x+3}\] it said any possible restrictions... so I"m not sure what that means 100% maybe what value makes the result undefined ?>! Not sure.. any way our lcd = (2x)(x+3) so we multiply x+3 on the first fraction and multiply 2x on the second fraction

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so like cross multiplying?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5umm... similar but instead we need to find the least common denominator see example 3 on the cliffnotes site... noticed how they took the lcd of that problem?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It looks kinda confusing sine the problem big :x

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\frac{3x+2}{2x} \times \frac{x+3}{x+3}\frac{x}{x+3} \times \frac{2x}{2x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok that makes alot more since lol

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5example 3 on cliffnotes from Nurali was just x and y as the denominators. it was the later examples that I didn't choose because I knew it would be too much

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would we just times the bottom demonitaers togethor? like 2x(x+3)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\frac{(3x+2)(x+3)2x^2}{2x(x+3)}\] we have to remember that whenever we have a  sign on the right side of the equation, we need to distribute that sign all over

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[x(2x) \rightarrow 2x^2\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5and we need to use FOIL method to expand the left side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know how to do that cx ill show you after im done foiling it c:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would we do the distributive property to the denomater? or does that stay the same

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5umm I think it depends on the numerator... because we wouldn't want to combine the denominator and end up that we can cancel something out...taking a step backwards

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i foiled the top but didn't add up yet, is this correct so far? 4x+9x+2x+6

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[(3x+2)(x+3) 2x^2 = 3x^2+9x+2x+6 = 3x^2+11x+6 2x^2 = x^2+11x+6\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5remember \[(x)(x) \rightarrow (x^1)(x^1) \rightarrow x^{1+1} \rightarrow x^2\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5so... \[(3x)(x) \rightarrow 3x^{1+1} \rightarrow 3x^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohhh ok, so now i have x^2+11x6/2x(x+3)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would we cancel our the 6 from 3?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5I don't think this can be factored... the only pairs for 6 is 6 x 1 1 x 6 2 x 3 3 x2 that's 6+1 =7 3+2 = 5 and subtracting will make it worse

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0maybe thats the restrictions they talk about?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\frac{x^2+11x6}{2x(x+3)}\] maybe I wish it was more specific.. there is also what values of x makes this undefined too

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.52x(x+3) = 0 split into 2 problems 2x=0 x+3=0 solving x ... X = 0,3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0those are probably the restrictions Cx , i think it does mean undifined

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so the next question wants me to do this dw:1433845443996:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\frac{x^2+11x6}{2x(x+3)} \times \frac{x+3}{x+1}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5we can cancel out the x+3... it's in the numerator and denominator \[\frac{x^2+11x6}{2x(x+3)} \times \frac{x+3}{x1}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh true! so they would disapear?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes! the easiest step on here lol cx so then the problem would be x^2+116/2 times x1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0*divided by 2x not 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how would that work? since the second one isnt a denominater nor a numerator?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\frac{x^2+11x6}{2x} \times \frac{1}{x1} \rightarrow \frac{x^2+11x6}{2x(x1)}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5huh?! ok wait I just latex the fractions without x+3 because the numerator had one and the denominator had one .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh ok i remebr learning that step now, so it would stay like that? :o

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5what is the next question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you said they cancled eachother out cx, and now i have to divide that equation by 6/x1, but it also says to (Discuss why the degree of the resulting denominator did not change from your expression’s degree)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\frac{x^2+11x6}{2x(x1)} \] divided by \[\frac{6}{x1}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5if you flip the second fraction... surprise x1 gets canceled out too.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\frac{x^2+11x6}{2x(x1)} \times \frac{x1}{6}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh and it turns into a mutplication by flipping?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5when dividing fractions... you flip the second fraction... in the end you're multiplying

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh ok, that makes it easier cx

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\frac{x^2+11x6}{2x} \times \frac{1}{6} \rightarrow \frac{x^2+11x6}{12x}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5I think it's safe now to combine the denominator...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh yeah i keep forget that the single number would be on bottom and the 1 on top, and yea it does xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so then i would have to explain *Discuss why the degree of the resulting denominator did not change from your expression’s degree*

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what the flip does it mean by that lol :x

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.512x that's first degree isn't it?! awww c*** I haven't dealt with these questions in a while. pure math doesn't have this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well we got the retrictions Q , and i just wanna finish this one assignemnt thingy lol, you look like your doing it right! cx its just these wierd Q's

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5how did it not change from the expression's degree? could it be referring to the original question?!

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5the first question you had ... contained 2x our fourth question had the denominator 2x(6) > 12x I think they are the same first degree. That's just a guess ..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0maybe they mean degree by like * x, x^2, x^3

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5yeah I'm thinking that we compare the last answer we have to the first question? hmmmmmmmm?! the degrees are the same if we look at it that way?!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha yea, ill just say, i shouldnt get that many points taken off since were doing the rest right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, so thats our final answer for Q 4, now we just have one left!

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5oo I thought that was the final one?!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no this one is the final one lol,

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its the very last one, please helpp :3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433847285555:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5ok first combine the second and third fraction

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1433847473742:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5x + x = 2x .. the denominator stays the same..... OMG EVEN I DID +6 #FAIL

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Idw:1433847507052:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol its, its late at night lol xD

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\frac{x^2+11x6}{12x} + \frac{2x}{x+1}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5now use the least common denominator which is 12x(x+1)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so we would do that whole timezing the first by the equation and the second by the second one?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5but only multiply what is misssing for the first fraction we have 12x.. x+1 is missing so multiply x+1/x+1

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\frac{x^2+11x6}{12x} \times \frac{x+1}{x+1} + \frac{2x}{x+1} \times\frac{2x}{2x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait, so why did we mutiply 2x instead of 12?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\frac{x^2+11x6}{12x} \times \frac{x+1}{x+1} + \frac{2x}{x+1} \times\frac{12x}{12x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok lol, and for example on the first bottom ones we would do (12x)(x+1) ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5numerator on the left is going to be a bit tough though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok :x ill do the denomnaters and show u

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433847901459:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1433847957533:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[(x^2+11x6)(x+1) = x^3+11x^26x+x^2+11x6 = x^3+12x^2+5x6\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[x^3+12x^2+5x6+24x^2 = x^3+36x^2+5x6\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\frac{x^3+36x^2+5x6}{12x(x+1)}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is that the end point? xO

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or do we do stuff with the denomatr to the numerator now?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5hmmm... I think that's it?!

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5we can't use factor by grouping with the numerator

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5not a perfect cube either

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea, it should be lol i cant belive 4 problems took an hour :X, and thank you soOO much! i've asked this Q many times on here and noone has helped me like you have! and yea it doesnt look like a perfect cube

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5I think it was due to my latex writing too.. that takes a bit of time and thinking xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont think so cx these types of Q's look like theyd take forever lol, and we were moving pretty fast cx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0again thank you so muccccch! very appreciated that you helped me cx
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.