anonymous
  • anonymous
The equation x2 + y2 − 2x + 2y − 1 = 0 is the general form of the equation of a circle. What is the standard form of the equation? (x − 1)2 − (y − 1)2 = 1 (x − 1)2 + (y + 1)2 = 3 (x + 1)2 + (y − 1)2 = 1 (x − 1)2 + (y + 1)2 = 1
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

foreverandalways13
  • foreverandalways13
anonymous
  • anonymous
geerky42
  • geerky42
Arrange equation: \[x^2 - 2x + y^2 + 2y = 1\] Now we need to insert something here: \[(x^2 - 2x + \underline{\text{ ? }} )+ (y^2 + 2y + \underline{\text{ ? }}) = 1\] So we can complete the square it. Any idea?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

geerky42
  • geerky42
Saying we have something like \(a^2 + b~a\). To complete the square, we should add \(\left(\frac{b}{2}\right)^2\) to both sides, so we have \(a^2 + b~a+\left(\frac{b}{2}\right)^2 \Rightarrow\left(a+\frac{b}{2} \right)^2\)
anonymous
  • anonymous
anonymous
  • anonymous

Looking for something else?

Not the answer you are looking for? Search for more explanations.