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anonymous
 one year ago
FAN AND MEDAL
anonymous
 one year ago
FAN AND MEDAL

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sherwin throws a dart at this squareshaped target: Part A: Is the probability of hitting the black circle inside the target closer to 0 or 1? Why? Part B: Is the probability of hitting the white portion of the target closer to 0 or 1? Why?

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.2found the related picture online http://gyazo.com/bc22b4046e9fe6d9616d8ca7a02df86c

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433864652697:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0more of the white i dont know how to explain it

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.2so the area of the circle and the area of the square must be found. The diameter of the circle is 4 so to find the area we will do A=pir^2 which is A=pi(2)^2 so A=4pi now we have to take the area of the square which is 22^2= 484 so the probability is 4pi/484

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.24pi/484 comes out to .026 which is far closer to 0 than it is to 1

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.2Now for the second part

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.2The probability of hitting the white part is 4844pi/484 =

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.2this is equivalent to .97 which is far closer to 1 than it is to 0.

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.2So the probability of hitting the black part is close to 0 and the probability of hitting the white part is close to 1.
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