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anonymous

  • one year ago

Simplify: ((4y^2 - 13y + 3) / (2y^2 - 5y - 12)) * ((2y^2 + 9y + 9) / (16y^2 - 1)) * ((y^2 + 3y - 28) / (y^2 - 9))

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  1. Nnesha
    • one year ago
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    waooo

  2. anonymous
    • one year ago
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    thats for a picture of it

  3. Nnesha
    • one year ago
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    factor everything !!

  4. anonymous
    • one year ago
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    it is to be simplified, not factored.

  5. Nnesha
    • one year ago
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    \[\large\rm \frac{ 4y^2-13y+3 }{ 2y^2-5y-12 } \times \frac{ 2y^2+9y+9 }{ 16y^2-1 } \times \frac{ y^2+3y-28 }{ y^2-9 }\]

  6. Nnesha
    • one year ago
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    yes but you have to factor all quadratic equations

  7. anonymous
    • one year ago
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    it has been awhile since i have last did some math, or even used math in my daily life. I sadly also have a horrible memory, so i cant remember how to do this. thankfully though, i am a fast learner.

  8. Nnesha
    • one year ago
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    alight 4y^2 -13y +3 there are 3+ ways to factor quadratic equations easy one is to find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term

  9. Nnesha
    • one year ago
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    abc values are \[\large\rm Ax^2+Bx+C=0\]

  10. anonymous
    • one year ago
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    hmmmm

  11. anonymous
    • one year ago
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    maybe it is just me, but. . . i dont see how this can apply to the current equation, because the equation i posted has 3 fractions multiplying with eachother, and from what you posted. . . it is a single line with a equal sign.

  12. Nnesha
    • one year ago
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    okay let's do this one together \[\large\rm 4y^2 -13y +3 \]\[\large\rm Ax^2+Bx+C \] A=4 C =3 multiply AC= 12 now find two number if you multiply them you should get 12 and if you add or subtract them then you should get -13

  13. Nnesha
    • one year ago
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    i know we have to factor all quadratic equation one by one 4y^2 -13y +3 ^^so that equation is at the numerator of first fraction

  14. anonymous
    • one year ago
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    how does A=4 and C=3?

  15. Nnesha
    • one year ago
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    Quadratic equation Ax^2+Bx+C A is the leading coefficient and C is the constant term b = middle term

  16. Nnesha
    • one year ago
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    4y^2 -13y +3 so what is leading coefficient here and what is constant term ?

  17. anonymous
    • one year ago
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    A= 4 B=-13 c= 3?

  18. Nnesha
    • one year ago
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    yes that's right

  19. Nnesha
    • one year ago
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    multiply AC= 4 times 3 = 12 B=-13 now find two number if you multiply them you should get 12 and if you add or subtract them then you should get middle term which is -13

  20. anonymous
    • one year ago
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    sorry, my computer died. lol

  21. anonymous
    • one year ago
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    what do you mean by "find two number"?

  22. Nnesha
    • one year ago
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    what method did you learn 'n school ?

  23. anonymous
    • one year ago
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    i cant remember, it has been some time now... like 3-10 weeks

  24. Nnesha
    • one year ago
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    what two number you should multiply to get =12 1st number TIMES 2nd number = 12 what are the numbers ?

  25. anonymous
    • one year ago
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    3 & 4

  26. Nnesha
    • one year ago
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    yep 3 times 4 = 12 but 3+4 = -13 ?? 2 times 6 = 12 but 2 +6 isn't equal to -13 -12 times -1 = 12 correct -12 -1 = -13 ? right two numbers are -12 aand -1 when you multiply them you will get 12 and when you add them u will get -13 correct thats what we need

  27. Nnesha
    • one year ago
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    |dw:1433868376914:dw| carry down first and last term write those two number in middle now apply group method

  28. anonymous
    • one year ago
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    so i have to find what A equals and what C equals, and multiply them together. once that is done, i have to figure out what two numbers added together equal the number that A times C equaled. then if that works, i continue to try to subtract my new founded numbers and see if they equal B?

  29. anonymous
    • one year ago
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    then i get the first and last term, then get the new founded numbers and put them in the center to make an equation?

  30. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @YouDontKnowMeOo so i have to find what A equals and what C equals, and multiply them together. once that is done, i have to figure out what two numbers added together equal the number that A times C equaled. then if that works, i continue to try to subtract my new founded numbers and see if they equal B? \(\color{blue}{\text{End of Quote}}\) product of two numbers equal to AC and when you add or subtract them then you should get MIDDLE TERM

  31. Nnesha
    • one year ago
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    http://prntscr.com/7f0861

  32. anonymous
    • one year ago
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    whats the picture for?

  33. Nnesha
    • one year ago
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    there is a mistake * have to figure out what two numbers added together equal the number that A times C equaled. ** so i mentioned that

  34. anonymous
    • one year ago
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    ah

  35. Nnesha
    • one year ago
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    alright familiar wit the group method ?

  36. anonymous
    • one year ago
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    not really

  37. Nnesha
    • one year ago
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    mhm that's why we should take notest so we can goover all stuff after 3 weeks or after one year :-)

  38. Nnesha
    • one year ago
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    notes**

  39. Nnesha
    • one year ago
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    |dw:1433869235616:dw| now make a group of two terms now find common factor of first box and 2nd box

  40. anonymous
    • one year ago
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    i am not a fan of notes nor am i a fan of studying.

  41. anonymous
    • one year ago
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    although, now that you point it out. i remember grouping.

  42. Nnesha
    • one year ago
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    nobody likes *STUDYING* but we HAVE to...

  43. Nnesha
    • one year ago
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    good

  44. anonymous
    • one year ago
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    i never had to study

  45. Nnesha
    • one year ago
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    what grade are you in?

  46. anonymous
    • one year ago
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    4y and 1 are the common factor i am pretty sure. and i am in 11th grade going to 12th grade.

  47. Nnesha
    • one year ago
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    great! :-)|dw:1433869627754:dw| 2nd parentheses -1 is common both parentheses should be the same divide both terms by common factor write that in the parentheses that's how i got y -3

  48. Nnesha
    • one year ago
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    |dw:1433869771424:dw| write outside terms in one parentheses and (y-3) is a common factor just write it one time so factor of 4y^2-13y +3 are (y-3) and (4y-1)