## anonymous one year ago Simplify: ((4y^2 - 13y + 3) / (2y^2 - 5y - 12)) * ((2y^2 + 9y + 9) / (16y^2 - 1)) * ((y^2 + 3y - 28) / (y^2 - 9))

1. Nnesha

waooo

2. anonymous
3. anonymous

thats for a picture of it

4. Nnesha

factor everything !!

5. anonymous

it is to be simplified, not factored.

6. Nnesha

$\large\rm \frac{ 4y^2-13y+3 }{ 2y^2-5y-12 } \times \frac{ 2y^2+9y+9 }{ 16y^2-1 } \times \frac{ y^2+3y-28 }{ y^2-9 }$

7. Nnesha

yes but you have to factor all quadratic equations

8. anonymous

it has been awhile since i have last did some math, or even used math in my daily life. I sadly also have a horrible memory, so i cant remember how to do this. thankfully though, i am a fast learner.

9. Nnesha

alight 4y^2 -13y +3 there are 3+ ways to factor quadratic equations easy one is to find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term

10. Nnesha

abc values are $\large\rm Ax^2+Bx+C=0$

11. anonymous

hmmmm

12. anonymous

maybe it is just me, but. . . i dont see how this can apply to the current equation, because the equation i posted has 3 fractions multiplying with eachother, and from what you posted. . . it is a single line with a equal sign.

13. Nnesha

okay let's do this one together $\large\rm 4y^2 -13y +3$$\large\rm Ax^2+Bx+C$ A=4 C =3 multiply AC= 12 now find two number if you multiply them you should get 12 and if you add or subtract them then you should get -13

14. Nnesha

i know we have to factor all quadratic equation one by one 4y^2 -13y +3 ^^so that equation is at the numerator of first fraction

15. anonymous

how does A=4 and C=3?

16. Nnesha

Quadratic equation Ax^2+Bx+C A is the leading coefficient and C is the constant term b = middle term

17. Nnesha

4y^2 -13y +3 so what is leading coefficient here and what is constant term ?

18. anonymous

A= 4 B=-13 c= 3?

19. Nnesha

yes that's right

20. Nnesha

multiply AC= 4 times 3 = 12 B=-13 now find two number if you multiply them you should get 12 and if you add or subtract them then you should get middle term which is -13

21. anonymous

sorry, my computer died. lol

22. anonymous

what do you mean by "find two number"?

23. Nnesha

what method did you learn 'n school ?

24. anonymous

i cant remember, it has been some time now... like 3-10 weeks

25. Nnesha

what two number you should multiply to get =12 1st number TIMES 2nd number = 12 what are the numbers ?

26. anonymous

3 & 4

27. Nnesha

yep 3 times 4 = 12 but 3+4 = -13 ?? 2 times 6 = 12 but 2 +6 isn't equal to -13 -12 times -1 = 12 correct -12 -1 = -13 ? right two numbers are -12 aand -1 when you multiply them you will get 12 and when you add them u will get -13 correct thats what we need

28. Nnesha

|dw:1433868376914:dw| carry down first and last term write those two number in middle now apply group method

29. anonymous

so i have to find what A equals and what C equals, and multiply them together. once that is done, i have to figure out what two numbers added together equal the number that A times C equaled. then if that works, i continue to try to subtract my new founded numbers and see if they equal B?

30. anonymous

then i get the first and last term, then get the new founded numbers and put them in the center to make an equation?

31. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @YouDontKnowMeOo so i have to find what A equals and what C equals, and multiply them together. once that is done, i have to figure out what two numbers added together equal the number that A times C equaled. then if that works, i continue to try to subtract my new founded numbers and see if they equal B? $$\color{blue}{\text{End of Quote}}$$ product of two numbers equal to AC and when you add or subtract them then you should get MIDDLE TERM

32. Nnesha
33. anonymous

whats the picture for?

34. Nnesha

there is a mistake * have to figure out what two numbers added together equal the number that A times C equaled. ** so i mentioned that

35. anonymous

ah

36. Nnesha

alright familiar wit the group method ?

37. anonymous

not really

38. Nnesha

mhm that's why we should take notest so we can goover all stuff after 3 weeks or after one year :-)

39. Nnesha

notes**

40. Nnesha

|dw:1433869235616:dw| now make a group of two terms now find common factor of first box and 2nd box

41. anonymous

i am not a fan of notes nor am i a fan of studying.

42. anonymous

although, now that you point it out. i remember grouping.

43. Nnesha

nobody likes *STUDYING* but we HAVE to...

44. Nnesha

good

45. anonymous

i never had to study

46. Nnesha

what grade are you in?

47. anonymous

4y and 1 are the common factor i am pretty sure. and i am in 11th grade going to 12th grade.

48. Nnesha

great! :-)|dw:1433869627754:dw| 2nd parentheses -1 is common both parentheses should be the same divide both terms by common factor write that in the parentheses that's how i got y -3

49. Nnesha

|dw:1433869771424:dw| write outside terms in one parentheses and (y-3) is a common factor just write it one time so factor of 4y^2-13y +3 are (y-3) and (4y-1)