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anonymous
 one year ago
Simplify: ((4y^2  13y + 3) / (2y^2  5y  12)) * ((2y^2 + 9y + 9) / (16y^2  1)) * ((y^2 + 3y  28) / (y^2  9))
anonymous
 one year ago
Simplify: ((4y^2  13y + 3) / (2y^2  5y  12)) * ((2y^2 + 9y + 9) / (16y^2  1)) * ((y^2 + 3y  28) / (y^2  9))

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats for a picture of it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is to be simplified, not factored.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm \frac{ 4y^213y+3 }{ 2y^25y12 } \times \frac{ 2y^2+9y+9 }{ 16y^21 } \times \frac{ y^2+3y28 }{ y^29 }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes but you have to factor all quadratic equations

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it has been awhile since i have last did some math, or even used math in my daily life. I sadly also have a horrible memory, so i cant remember how to do this. thankfully though, i am a fast learner.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alight 4y^2 13y +3 there are 3+ ways to factor quadratic equations easy one is to find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1abc values are \[\large\rm Ax^2+Bx+C=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0maybe it is just me, but. . . i dont see how this can apply to the current equation, because the equation i posted has 3 fractions multiplying with eachother, and from what you posted. . . it is a single line with a equal sign.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1okay let's do this one together \[\large\rm 4y^2 13y +3 \]\[\large\rm Ax^2+Bx+C \] A=4 C =3 multiply AC= 12 now find two number if you multiply them you should get 12 and if you add or subtract them then you should get 13

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1i know we have to factor all quadratic equation one by one 4y^2 13y +3 ^^so that equation is at the numerator of first fraction

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how does A=4 and C=3?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1Quadratic equation Ax^2+Bx+C A is the leading coefficient and C is the constant term b = middle term

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.14y^2 13y +3 so what is leading coefficient here and what is constant term ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1multiply AC= 4 times 3 = 12 B=13 now find two number if you multiply them you should get 12 and if you add or subtract them then you should get middle term which is 13

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry, my computer died. lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what do you mean by "find two number"?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1what method did you learn 'n school ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i cant remember, it has been some time now... like 310 weeks

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1what two number you should multiply to get =12 1st number TIMES 2nd number = 12 what are the numbers ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yep 3 times 4 = 12 but 3+4 = 13 ?? 2 times 6 = 12 but 2 +6 isn't equal to 13 12 times 1 = 12 correct 12 1 = 13 ? right two numbers are 12 aand 1 when you multiply them you will get 12 and when you add them u will get 13 correct thats what we need

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433868376914:dw carry down first and last term write those two number in middle now apply group method

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i have to find what A equals and what C equals, and multiply them together. once that is done, i have to figure out what two numbers added together equal the number that A times C equaled. then if that works, i continue to try to subtract my new founded numbers and see if they equal B?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then i get the first and last term, then get the new founded numbers and put them in the center to make an equation?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @YouDontKnowMeOo so i have to find what A equals and what C equals, and multiply them together. once that is done, i have to figure out what two numbers added together equal the number that A times C equaled. then if that works, i continue to try to subtract my new founded numbers and see if they equal B? \(\color{blue}{\text{End of Quote}}\) product of two numbers equal to AC and when you add or subtract them then you should get MIDDLE TERM

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whats the picture for?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1there is a mistake * have to figure out what two numbers added together equal the number that A times C equaled. ** so i mentioned that

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright familiar wit the group method ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1mhm that's why we should take notest so we can goover all stuff after 3 weeks or after one year :)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433869235616:dw now make a group of two terms now find common factor of first box and 2nd box

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i am not a fan of notes nor am i a fan of studying.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0although, now that you point it out. i remember grouping.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1nobody likes *STUDYING* but we HAVE to...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i never had to study

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04y and 1 are the common factor i am pretty sure. and i am in 11th grade going to 12th grade.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1great! :)dw:1433869627754:dw 2nd parentheses 1 is common both parentheses should be the same divide both terms by common factor write that in the parentheses that's how i got y 3

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433869771424:dw write outside terms in one parentheses and (y3) is a common factor just write it one time so factor of 4y^213y +3 are (y3) and (4y1)