anonymous
  • anonymous
Simplify: ((4y^2 - 13y + 3) / (2y^2 - 5y - 12)) * ((2y^2 + 9y + 9) / (16y^2 - 1)) * ((y^2 + 3y - 28) / (y^2 - 9))
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Nnesha
  • Nnesha
waooo
anonymous
  • anonymous
http://www4b.wolframalpha.com/Calculate/MSP/MSP1621d4g3f0h53dg61d800001i71ii6e2i6c9b7d?MSPStoreType=image/gif&s=41&w=307.&h=43.
anonymous
  • anonymous
thats for a picture of it

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Nnesha
  • Nnesha
factor everything !!
anonymous
  • anonymous
it is to be simplified, not factored.
Nnesha
  • Nnesha
\[\large\rm \frac{ 4y^2-13y+3 }{ 2y^2-5y-12 } \times \frac{ 2y^2+9y+9 }{ 16y^2-1 } \times \frac{ y^2+3y-28 }{ y^2-9 }\]
Nnesha
  • Nnesha
yes but you have to factor all quadratic equations
anonymous
  • anonymous
it has been awhile since i have last did some math, or even used math in my daily life. I sadly also have a horrible memory, so i cant remember how to do this. thankfully though, i am a fast learner.
Nnesha
  • Nnesha
alight 4y^2 -13y +3 there are 3+ ways to factor quadratic equations easy one is to find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term
Nnesha
  • Nnesha
abc values are \[\large\rm Ax^2+Bx+C=0\]
anonymous
  • anonymous
hmmmm
anonymous
  • anonymous
maybe it is just me, but. . . i dont see how this can apply to the current equation, because the equation i posted has 3 fractions multiplying with eachother, and from what you posted. . . it is a single line with a equal sign.
Nnesha
  • Nnesha
okay let's do this one together \[\large\rm 4y^2 -13y +3 \]\[\large\rm Ax^2+Bx+C \] A=4 C =3 multiply AC= 12 now find two number if you multiply them you should get 12 and if you add or subtract them then you should get -13
Nnesha
  • Nnesha
i know we have to factor all quadratic equation one by one 4y^2 -13y +3 ^^so that equation is at the numerator of first fraction
anonymous
  • anonymous
how does A=4 and C=3?
Nnesha
  • Nnesha
Quadratic equation Ax^2+Bx+C A is the leading coefficient and C is the constant term b = middle term
Nnesha
  • Nnesha
4y^2 -13y +3 so what is leading coefficient here and what is constant term ?
anonymous
  • anonymous
A= 4 B=-13 c= 3?
Nnesha
  • Nnesha
yes that's right
Nnesha
  • Nnesha
multiply AC= 4 times 3 = 12 B=-13 now find two number if you multiply them you should get 12 and if you add or subtract them then you should get middle term which is -13
anonymous
  • anonymous
sorry, my computer died. lol
anonymous
  • anonymous
what do you mean by "find two number"?
Nnesha
  • Nnesha
what method did you learn 'n school ?
anonymous
  • anonymous
i cant remember, it has been some time now... like 3-10 weeks
Nnesha
  • Nnesha
what two number you should multiply to get =12 1st number TIMES 2nd number = 12 what are the numbers ?
anonymous
  • anonymous
3 & 4
Nnesha
  • Nnesha
yep 3 times 4 = 12 but 3+4 = -13 ?? 2 times 6 = 12 but 2 +6 isn't equal to -13 -12 times -1 = 12 correct -12 -1 = -13 ? right two numbers are -12 aand -1 when you multiply them you will get 12 and when you add them u will get -13 correct thats what we need
Nnesha
  • Nnesha
|dw:1433868376914:dw| carry down first and last term write those two number in middle now apply group method
anonymous
  • anonymous
so i have to find what A equals and what C equals, and multiply them together. once that is done, i have to figure out what two numbers added together equal the number that A times C equaled. then if that works, i continue to try to subtract my new founded numbers and see if they equal B?
anonymous
  • anonymous
then i get the first and last term, then get the new founded numbers and put them in the center to make an equation?
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @YouDontKnowMeOo so i have to find what A equals and what C equals, and multiply them together. once that is done, i have to figure out what two numbers added together equal the number that A times C equaled. then if that works, i continue to try to subtract my new founded numbers and see if they equal B? \(\color{blue}{\text{End of Quote}}\) product of two numbers equal to AC and when you add or subtract them then you should get MIDDLE TERM
Nnesha
  • Nnesha
http://prntscr.com/7f0861
anonymous
  • anonymous
whats the picture for?
Nnesha
  • Nnesha
there is a mistake * have to figure out what two numbers added together equal the number that A times C equaled. ** so i mentioned that
anonymous
  • anonymous
ah
Nnesha
  • Nnesha
alright familiar wit the group method ?
anonymous
  • anonymous
not really
Nnesha
  • Nnesha
mhm that's why we should take notest so we can goover all stuff after 3 weeks or after one year :-)
Nnesha
  • Nnesha
notes**
Nnesha
  • Nnesha
|dw:1433869235616:dw| now make a group of two terms now find common factor of first box and 2nd box
anonymous
  • anonymous
i am not a fan of notes nor am i a fan of studying.
anonymous
  • anonymous
although, now that you point it out. i remember grouping.
Nnesha
  • Nnesha
nobody likes *STUDYING* but we HAVE to...
Nnesha
  • Nnesha
good
anonymous
  • anonymous
i never had to study
Nnesha
  • Nnesha
what grade are you in?
anonymous
  • anonymous
4y and 1 are the common factor i am pretty sure. and i am in 11th grade going to 12th grade.
Nnesha
  • Nnesha
great! :-)|dw:1433869627754:dw| 2nd parentheses -1 is common both parentheses should be the same divide both terms by common factor write that in the parentheses that's how i got y -3
Nnesha
  • Nnesha
|dw:1433869771424:dw| write outside terms in one parentheses and (y-3) is a common factor just write it one time so factor of 4y^2-13y +3 are (y-3) and (4y-1)