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anonymous

  • one year ago

If each resistor in the circuit drawn inside is 5.0 Ω and the battery is 12.0 V, what does the second voltmeter (V_2) read? A. 0.96 V B. 0.35 V C. 4.8 V D. 2.4 V

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  1. anonymous
    • one year ago
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    |dw:1433867393099:dw|

  2. anonymous
    • one year ago
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    i think it got cut off, but that last part just is labeled R3!

  3. Michele_Laino
    • one year ago
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    we have to compute the equivalent resistance, frst

  4. Michele_Laino
    • one year ago
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    |dw:1433867505494:dw|

  5. Michele_Laino
    • one year ago
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    so equivalent resistance is: R_eq= 5+2.5+5=...

  6. anonymous
    • one year ago
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    12.5!

  7. Michele_Laino
    • one year ago
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    ok!

  8. Michele_Laino
    • one year ago
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    now the current through R_4, which is the current of the circuit, is: I=V/R_eq= 12/2.5=...

  9. anonymous
    • one year ago
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    we get 4.8! so does that mean choice C is our solution?

  10. Michele_Laino
    • one year ago
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    no, since we have to compute the voltage drop across R_4, which is: V_2=4.8*5=...volts

  11. anonymous
    • one year ago
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    ohh and then we get 24!

  12. anonymous
    • one year ago
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    what happens next?

  13. Michele_Laino
    • one year ago
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    sorry, the current is: 12/12.5=...amperes

  14. anonymous
    • one year ago
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    0.96? so choice A is our solution?

  15. Michele_Laino
    • one year ago
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    ok! now the requested volatge drop is: 0.96*5=...volts

  16. anonymous
    • one year ago
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    4.8! so it is choice C?

  17. Michele_Laino
    • one year ago
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    yes!

  18. anonymous
    • one year ago
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    yay!! thanks!! :) onto the next! :P

  19. Michele_Laino
    • one year ago
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    ok! :)

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