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anonymous
 one year ago
If each resistor in the circuit drawn inside is 5.0 ohms and the battery is 12.0 V, what does the second ammeter (A_2) read?
A. 0.48 A
B. 0.24 A
C. 0.96 A
D. 0.12 A
anonymous
 one year ago
If each resistor in the circuit drawn inside is 5.0 ohms and the battery is 12.0 V, what does the second ammeter (A_2) read? A. 0.48 A B. 0.24 A C. 0.96 A D. 0.12 A

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433869889424:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2your circuit is equivalent to this one: dw:1433869974738:dw the voltage drop across A and B is \[{V_{AB}} = \frac{{12}}{{5 + 2.5 + 5}} \times 2.5 = ...volts\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok! so we get 2.4> wjhat happens next?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2it is simple, since the requested current is: I_2= 2.4/5=...amperes dw:1433870275658:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh! so 0.48, choice A is our solution?
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