## anonymous one year ago If each resistor in the circuit drawn inside is 5.0 ohms and the battery is 12.0 V, what does the second ammeter (A_2) read? A. 0.48 A B. 0.24 A C. 0.96 A D. 0.12 A

1. anonymous

|dw:1433869889424:dw|

2. Michele_Laino

your circuit is equivalent to this one: |dw:1433869974738:dw| the voltage drop across A and B is ${V_{AB}} = \frac{{12}}{{5 + 2.5 + 5}} \times 2.5 = ...volts$

3. anonymous

ok! so we get 2.4> wjhat happens next?

4. Michele_Laino

it is simple, since the requested current is: I_2= 2.4/5=...amperes |dw:1433870275658:dw|

5. anonymous

oh! so 0.48, choice A is our solution?

6. Michele_Laino

that's right!

7. anonymous

yay! thanks!:)

8. Michele_Laino

:)