anonymous
  • anonymous
If each resistor in the circuit drawn inside is 5.0 ohms and the battery is 12.0 V, what does the second ammeter (A_2) read? A. 0.48 A B. 0.24 A C. 0.96 A D. 0.12 A
Physics
chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1433869889424:dw|
Michele_Laino
  • Michele_Laino
your circuit is equivalent to this one: |dw:1433869974738:dw| the voltage drop across A and B is \[{V_{AB}} = \frac{{12}}{{5 + 2.5 + 5}} \times 2.5 = ...volts\]
anonymous
  • anonymous
ok! so we get 2.4> wjhat happens next?

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Michele_Laino
  • Michele_Laino
it is simple, since the requested current is: I_2= 2.4/5=...amperes |dw:1433870275658:dw|
anonymous
  • anonymous
oh! so 0.48, choice A is our solution?
Michele_Laino
  • Michele_Laino
that's right!
anonymous
  • anonymous
yay! thanks!:)
Michele_Laino
  • Michele_Laino
:)

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