anonymous
  • anonymous
You plug a string of 100 lights in series into a 120 V power outlet, and each light has a resistance of 3.00 Ω. If each light has a power rating of 0.50 W, what will happen? A. All the lights will go out. B. Only one light will go out. C. The string will remain lit. D. You cannot predict what will happen.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Michele_Laino
  • Michele_Laino
the total resistance is: 3*100=...ohms
anonymous
  • anonymous
300!
Michele_Laino
  • Michele_Laino
ok! so the current is: I=120/300=...amperes

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anonymous
  • anonymous
0.4!
Michele_Laino
  • Michele_Laino
ok!
Michele_Laino
  • Michele_Laino
now the maximum current which can flow into each of the bulbs, is: I=W/R^2= 0.5/9=...amperes
anonymous
  • anonymous
0.0555555...
anonymous
  • anonymous
what does that mean? the lights will remain lit? :/
Michele_Laino
  • Michele_Laino
so, since 0.4>0.055, namely the current provided by the battery is greater than the maximum current which can flow into each bulb, wha can you conclude?
anonymous
  • anonymous
ermm the string of lights will remain lit?
anonymous
  • anonymous
choiceA?
Michele_Laino
  • Michele_Laino
sorry, I have made an error, the maximum current which can flow into each of the bulbs, is: \[I = \sqrt {\frac{W}{R}} = \sqrt {\frac{{0.5}}{3}} = ...\]
anonymous
  • anonymous
0.408?
Michele_Laino
  • Michele_Laino
ok!
Michele_Laino
  • Michele_Laino
so, since 0.4<0.408, namely the current provided by the battery is less than the current which can flow into each bulb, what can you conclude?
anonymous
  • anonymous
that means that all the lights will go out? choice A?
Michele_Laino
  • Michele_Laino
yes! that's right!
anonymous
  • anonymous
yay!! thanks!!:D
Michele_Laino
  • Michele_Laino
:)

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