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anonymous

  • one year ago

You plug a string of 100 lights in series into a 120 V power outlet, and each light has a resistance of 3.00 Ω. If each light has a power rating of 0.50 W, what will happen? A. All the lights will go out. B. Only one light will go out. C. The string will remain lit. D. You cannot predict what will happen.

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  1. Michele_Laino
    • one year ago
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    the total resistance is: 3*100=...ohms

  2. anonymous
    • one year ago
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    300!

  3. Michele_Laino
    • one year ago
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    ok! so the current is: I=120/300=...amperes

  4. anonymous
    • one year ago
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    0.4!

  5. Michele_Laino
    • one year ago
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    ok!

  6. Michele_Laino
    • one year ago
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    now the maximum current which can flow into each of the bulbs, is: I=W/R^2= 0.5/9=...amperes

  7. anonymous
    • one year ago
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    0.0555555...

  8. anonymous
    • one year ago
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    what does that mean? the lights will remain lit? :/

  9. Michele_Laino
    • one year ago
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    so, since 0.4>0.055, namely the current provided by the battery is greater than the maximum current which can flow into each bulb, wha can you conclude?

  10. anonymous
    • one year ago
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    ermm the string of lights will remain lit?

  11. anonymous
    • one year ago
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    choiceA?

  12. Michele_Laino
    • one year ago
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    sorry, I have made an error, the maximum current which can flow into each of the bulbs, is: \[I = \sqrt {\frac{W}{R}} = \sqrt {\frac{{0.5}}{3}} = ...\]

  13. anonymous
    • one year ago
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    0.408?

  14. Michele_Laino
    • one year ago
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    ok!

  15. Michele_Laino
    • one year ago
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    so, since 0.4<0.408, namely the current provided by the battery is less than the current which can flow into each bulb, what can you conclude?

  16. anonymous
    • one year ago
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    that means that all the lights will go out? choice A?

  17. Michele_Laino
    • one year ago
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    yes! that's right!

  18. anonymous
    • one year ago
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    yay!! thanks!!:D

  19. Michele_Laino
    • one year ago
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    :)

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