What is the equation of the line that passes through (5, -2) and (-3, 4)?
A.) 3x - 4y - 7 = 0
B.) 3x + 4y - 7 = 0
C.) -3x + 4y - 7 = 0
Stacey Warren - Expert brainly.com
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the first step is to find the slop using... Slope m is [ (y2 - y1) / (x2 -x1) ]
isnt the slope formula Y=(Mx / B) cause i cant remember
here is the formula
[ (y2 - y1) / (x2 -x1) ]
here's what we get when we plug it in |dw:1433871153981:dw|
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so -3/4 is the slope
Then you use the point-slope form of an equation for a line and solve for y :
(y - y1) = m * (x - x1)
(y - y1) = (-3 / 4) * (x- x1)?
yes we also have y1 and x1...
(y - (-2)) = (-3 / 4) * (x - 5)?
yes! next we would simplify.. so.. y+2=[-3/4 (x-5) ]
well, i got to go, thanks for helping me this far. i will give you a medal and be on my way. have fun and good luck. :D
so next we need to subtract 2
y+2=[-3/4 (x-5) ]
y=[-3/4 (x-5 (-2) ]
y=(-3/4x) + (7/4) This right here is called slope intercept form.. but we want standard form which is Ax+By=C
to get that we need to add 3/4 to the y.... we would get
are you sure??