anonymous
  • anonymous
What is the equation of the line that passes through (5, -2) and (-3, 4)? A.) 3x - 4y - 7 = 0 B.) 3x + 4y - 7 = 0 C.) -3x + 4y - 7 = 0
Mathematics
chestercat
  • chestercat
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superhelp101
  • superhelp101
the first step is to find the slop using... Slope m is [ (y2 - y1) / (x2 -x1) ]
anonymous
  • anonymous
isnt the slope formula Y=(Mx / B) cause i cant remember
superhelp101
  • superhelp101
here is the formula [ (y2 - y1) / (x2 -x1) ] here's what we get when we plug it in |dw:1433871153981:dw|

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superhelp101
  • superhelp101
so -3/4 is the slope
superhelp101
  • superhelp101
Then you use the point-slope form of an equation for a line and solve for y : (y - y1) = m * (x - x1)
anonymous
  • anonymous
(y - y1) = (-3 / 4) * (x- x1)?
superhelp101
  • superhelp101
yes we also have y1 and x1... y1=-2 x1=5
anonymous
  • anonymous
(y - (-2)) = (-3 / 4) * (x - 5)?
superhelp101
  • superhelp101
yes! next we would simplify.. so.. y+2=[-3/4 (x-5) ]
anonymous
  • anonymous
well, i got to go, thanks for helping me this far. i will give you a medal and be on my way. have fun and good luck. :D
superhelp101
  • superhelp101
so next we need to subtract 2 y+2=[-3/4 (x-5) ] y=[-3/4 (x-5 (-2) ] y=(-3/4x) + (7/4) This right here is called slope intercept form.. but we want standard form which is Ax+By=C to get that we need to add 3/4 to the y.... we would get y+(3/4)x=(7/4)....... are you sure??
anonymous
  • anonymous
yeah, sorry mang. thanks for the help though.
superhelp101
  • superhelp101
no prob anytime!

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