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anonymous

  • one year ago

What is the equation of the line that passes through (5, -2) and (-3, 4)? A.) 3x - 4y - 7 = 0 B.) 3x + 4y - 7 = 0 C.) -3x + 4y - 7 = 0

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  1. superhelp101
    • one year ago
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    the first step is to find the slop using... Slope m is [ (y2 - y1) / (x2 -x1) ]

  2. anonymous
    • one year ago
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    isnt the slope formula Y=(Mx / B) cause i cant remember

  3. superhelp101
    • one year ago
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    here is the formula [ (y2 - y1) / (x2 -x1) ] here's what we get when we plug it in |dw:1433871153981:dw|

  4. superhelp101
    • one year ago
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    so -3/4 is the slope

  5. superhelp101
    • one year ago
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    Then you use the point-slope form of an equation for a line and solve for y : (y - y1) = m * (x - x1)

  6. anonymous
    • one year ago
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    (y - y1) = (-3 / 4) * (x- x1)?

  7. superhelp101
    • one year ago
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    yes we also have y1 and x1... y1=-2 x1=5

  8. anonymous
    • one year ago
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    (y - (-2)) = (-3 / 4) * (x - 5)?

  9. superhelp101
    • one year ago
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    yes! next we would simplify.. so.. y+2=[-3/4 (x-5) ]

  10. anonymous
    • one year ago
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    well, i got to go, thanks for helping me this far. i will give you a medal and be on my way. have fun and good luck. :D

  11. superhelp101
    • one year ago
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    so next we need to subtract 2 y+2=[-3/4 (x-5) ] y=[-3/4 (x-5 (-2) ] y=(-3/4x) + (7/4) This right here is called slope intercept form.. but we want standard form which is Ax+By=C to get that we need to add 3/4 to the y.... we would get y+(3/4)x=(7/4)....... are you sure??

  12. anonymous
    • one year ago
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    yeah, sorry mang. thanks for the help though.

  13. superhelp101
    • one year ago
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    no prob anytime!

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