anonymous
  • anonymous
the figure shows a right triangle. what is r divided by p equal to?https://www.connexus.com/content/media/941080-722014-105136-AM-1405916119.jpg
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@nincompoop @ganeshie8
anonymous
  • anonymous
i really need help
anonymous
  • anonymous
@paki

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anonymous
  • anonymous
tan y , sin y, tan x, sin x
anonymous
  • anonymous
those are the options ^
anonymous
  • anonymous
@gknight
anonymous
  • anonymous
@Preetha
anonymous
  • anonymous
@IMcIntoshI
anonymous
  • anonymous
@Michele_Laino
anonymous
  • anonymous
@superhelp101
anonymous
  • anonymous
@HannahLovesYouAllot
anonymous
  • anonymous
Sorry I'm not good at math :( Im actually searching for help on a math question too
anonymous
  • anonymous
Ok thanks though
anonymous
  • anonymous
@_gusthedog_
anonymous
  • anonymous
@IMcIntoshI
anonymous
  • anonymous
@JoshKoikkara
anonymous
  • anonymous
@Ap3xPred
anonymous
  • anonymous
it say i gotta log in to see the content
anonymous
  • anonymous
to view the link?
anonymous
  • anonymous
yea
anonymous
  • anonymous
one sec
anonymous
  • anonymous
ok
anonymous
  • anonymous
anonymous
  • anonymous
there it is
anonymous
  • anonymous
none of this has any numbers to work with?
anonymous
  • anonymous
exactly ha thats why i dont get it
anonymous
  • anonymous
@superman38
anonymous
  • anonymous
its geometry and i have to learn this before i take finals
anonymous
  • anonymous
all i know is there is a 90 degree angle
anonymous
  • anonymous
yeah i dont understand the cosine and the sin and tan
anonymous
  • anonymous
neither do i I'm sorry i couldn't help
anonymous
  • anonymous
its ok thanks for trying though, ill just guess
geerky42
  • geerky42
Sine is ratio of opposite side by hypotenuse side. Cosine is ratio of adjacent sides to hypotenuse side. Tangent is ratio of opposite side to adjacent side. In other word, saying you have this triangle |dw:1433874198946:dw| Then \(\sin\theta = \dfrac{Opp}{Hyp}\) \(\cos\theta = \dfrac{Adj}{Hyp}\) \(\tan\theta = \dfrac{Opp}{Adj}\)
geerky42
  • geerky42
Here, you have ratio of p and r. ( \(\dfrac{p}{r}\) ) Since neither p nor r is hypotenuse side, then you would want tangent, right?
anonymous
  • anonymous
yes im following you so far
geerky42
  • geerky42
\[\tan\theta = \dfrac{Opp}{Adj}\] So we want \(p\) to be opposite. So what angle is opposite of side \(p\)?
anonymous
  • anonymous
hyp right?
geerky42
  • geerky42
|dw:1433874538222:dw|
geerky42
  • geerky42
Also hyp isn't angle.
anonymous
  • anonymous
sin?
geerky42
  • geerky42
I am asking you question, what angle is opposite from side p?
anonymous
  • anonymous
i am a idiot when it comes to math
geerky42
  • geerky42
You have three angles: 90 deg, y deg, and x deg. Which angle is opposite from side p?
anonymous
  • anonymous
x deg
anonymous
  • anonymous
@geerky42
geerky42
  • geerky42
Right. So we have tan and oppsite of p is x, So your answer is \(\boxed{\tan(x) = \dfrac{p}{r}}\)
anonymous
  • anonymous
THANKS ALOT!!!! :)
geerky42
  • geerky42
No problem

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