A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

For the circuit drawn inside, what will be the voltage drop across R_2? A. 9.47 V B. 14.2 V C. 21.3 V D. 45.0 V

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1433873690686:dw|

  2. johnweldon1993
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    When you combine all of the resistors...what do you get for the equivalent resistance?

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    95?

  4. johnweldon1993
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Correct... so if we were to redraw our circuit now... |dw:1433874008656:dw| What would be the total current going through the resistor?

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    45?

  6. johnweldon1993
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Current, not Voltage :) \[\large I = \frac{V}{R}\]

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh oops! so 45/95? = 0.47? :/

  8. johnweldon1993
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Right...that is our current that goes through our entire circuit here Now that we know that, we break apart our circuit again to the original with the current drawn in |dw:1433874182301:dw|

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ooh so what happens next?

  10. johnweldon1993
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    So now focus on R_2 |dw:1433874327033:dw| The voltage across R_2 would be \[\large V_{R_2} = I_{R_2}\times R_2\] \[\large V_{R_2} = 0.47A \times 30\Omega = ? \]

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    14.1? so choice B (14.2 V) is our solution?

  12. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that's right!

  13. johnweldon1993
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Indeed! Sorry walked away for a minute! lol

  14. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    haha yay! thanks!! :D

  15. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    :)

  16. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.