anonymous
  • anonymous
For the circuit drawn inside, what will be the voltage drop across R_2? A. 9.47 V B. 14.2 V C. 21.3 V D. 45.0 V
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1433873690686:dw|
johnweldon1993
  • johnweldon1993
When you combine all of the resistors...what do you get for the equivalent resistance?
anonymous
  • anonymous
95?

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johnweldon1993
  • johnweldon1993
Correct... so if we were to redraw our circuit now... |dw:1433874008656:dw| What would be the total current going through the resistor?
anonymous
  • anonymous
45?
johnweldon1993
  • johnweldon1993
Current, not Voltage :) \[\large I = \frac{V}{R}\]
anonymous
  • anonymous
oh oops! so 45/95? = 0.47? :/
johnweldon1993
  • johnweldon1993
Right...that is our current that goes through our entire circuit here Now that we know that, we break apart our circuit again to the original with the current drawn in |dw:1433874182301:dw|
anonymous
  • anonymous
ooh so what happens next?
johnweldon1993
  • johnweldon1993
So now focus on R_2 |dw:1433874327033:dw| The voltage across R_2 would be \[\large V_{R_2} = I_{R_2}\times R_2\] \[\large V_{R_2} = 0.47A \times 30\Omega = ? \]
anonymous
  • anonymous
14.1? so choice B (14.2 V) is our solution?
Michele_Laino
  • Michele_Laino
that's right!
johnweldon1993
  • johnweldon1993
Indeed! Sorry walked away for a minute! lol
anonymous
  • anonymous
haha yay! thanks!! :D
Michele_Laino
  • Michele_Laino
:)

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