If (44)x = 432, what is the value of x? 4 7 8 28

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If (44)x = 432, what is the value of x? 4 7 8 28

Mathematics
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I think its 8
divide 432 by 44

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is that \(\large\color{black}{ \displaystyle (44)^x=432 }\) or \(\large\color{black}{ \displaystyle (44)\times x=432 }\)
and no the answer isn't a whole numb.
the quickest step for (44)^x is take log base 44, and use a calculator for the left side. for (44) times x, just divide as welshfella has told you too
to*
it's \[\huge\rm (4^4)^x =4^{32}\] right ?
So A
which one is it ? is this ur question ??\[\huge\rm (4^4)^x =4^{32}\]
Yea
alright so now YOU tell me the answer remember we did this yesterday ?
I think its B
why ???
Nnesha, that is the question ?
Yea it is
yeah i guess^
what exponent rule you should apply ?
Ok can u do wat u did yester day wen u asked me what do i multiply to get this number,so it will be much eisier
you already know ^^^ it's a same method but with different numbers
ok... next time use an equation editor or denote an exponent using a caret, the ^ (Shift+6)
\[\huge\rm x^m \times x^n = x^{m \times n}\] m=4 n=x m times n = 32 substitute 4 and then solve for n
Ok can u do wat u did yester day wen u asked me what do i multiply to get this number,so it will be much eisier
\(\color{blue}{\text{Originally Posted by}}\) @nuccioreggie Ok can u do wat u did yester day wen u asked me what do i multiply to get this number,so it will be much eisier \(\color{blue}{\text{End of Quote}}\) \(\color{blue}{\text{Originally Posted by}}\) @Nnesha \[\huge\rm x^m \times x^n = x^{m \times n}\] m=4 n=x m times n = 32 substitute 4 and then solve for n \(\color{blue}{\text{End of Quote}}\)
8
check ur answer \[\huge\rm (4^4)^8 = 4^{ 4 \times 8} = 4^{?}\]
8 ?
Im thinking
u don't accept messages, so I will say this right here. you maid a mistake when you quoted the poster. The law of multiplying x^n times x^m gives x^(m+n)
\(\Large\color{black}{ \displaystyle \rm x^m\times x^n=x^{m+n} }\)
\(\color{blue}{\text{Originally Posted by}}\) @SolomonZelman u don't accept messages, so I will say this right here. you maid a mistake when you quoted the poster. The law of multiplying x^n times x^m gives x^(m+n) \(\color{blue}{\text{End of Quote}}\) i posted the wrong one facepalm >.<
\[\huge\rm (x^m)^n = x^{m \times n}\]
Im so confused the answer is B right??
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha \[\huge\rm x^m \times x^n = x^{m \times n}\] m=4 n=x m times n = 32 substitute 4 and then solve for n \(\color{blue}{\text{End of Quote}}\) i mean to post this exponent rule \[\huge\rm (x^m)^n = x^{m \times n}\] \[(4^4)^x =4^32 \]
4^{32}**
check your answer \[\huge\rm (4^4)^7 = 4^{32}\] is this right 4 times 7 =32? \[\large\rm (4^4)^8 =4^{32}\] both sides are equal ?? 4 times 8=32 ?? \[\huge\rm (4^4)^4 = 4^{32}\] 4 times 4 = 32 ?
when you multiply both exponents you should get 32 got it ? :-)
Wow thats not even an answer choice thats the wrong answer
huh?? which one ??
If (44)x = 432, what is the value of x? 4 7 8 28
That question
i'm saying if you u don't know exponent rules then you can substitute all answer choices for x to check your answer
What is the answer to this question
you already know \[\huge\rm (4^4)^x =4^{32}\] 4 times x = 32 you got it right!
4 times what =32 ?
is the answer 8
yeah i got the same answer 4 times 8 =32

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