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nuccioreggie
 one year ago
If (44)x = 432, what is the value of x?
4
7
8
28
nuccioreggie
 one year ago
If (44)x = 432, what is the value of x? 4 7 8 28

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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1is that \(\large\color{black}{ \displaystyle (44)^x=432 }\) or \(\large\color{black}{ \displaystyle (44)\times x=432 }\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1and no the answer isn't a whole numb.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1the quickest step for (44)^x is take log base 44, and use a calculator for the left side. for (44) times x, just divide as welshfella has told you too

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2it's \[\huge\rm (4^4)^x =4^{32}\] right ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2which one is it ? is this ur question ??\[\huge\rm (4^4)^x =4^{32}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2alright so now YOU tell me the answer remember we did this yesterday ?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Nnesha, that is the question ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2what exponent rule you should apply ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2http://openstudy.com/users/nuccioreggie#/updates/5575d9bce4b03f31cab2d56b

nuccioreggie
 one year ago
Best ResponseYou've already chosen the best response.0Ok can u do wat u did yester day wen u asked me what do i multiply to get this number,so it will be much eisier

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2you already know ^^^ it's a same method but with different numbers

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1ok... next time use an equation editor or denote an exponent using a caret, the ^ (Shift+6)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm x^m \times x^n = x^{m \times n}\] m=4 n=x m times n = 32 substitute 4 and then solve for n

nuccioreggie
 one year ago
Best ResponseYou've already chosen the best response.0Ok can u do wat u did yester day wen u asked me what do i multiply to get this number,so it will be much eisier

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @nuccioreggie Ok can u do wat u did yester day wen u asked me what do i multiply to get this number,so it will be much eisier \(\color{blue}{\text{End of Quote}}\) \(\color{blue}{\text{Originally Posted by}}\) @Nnesha \[\huge\rm x^m \times x^n = x^{m \times n}\] m=4 n=x m times n = 32 substitute 4 and then solve for n \(\color{blue}{\text{End of Quote}}\)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2check ur answer \[\huge\rm (4^4)^8 = 4^{ 4 \times 8} = 4^{?}\]

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1u don't accept messages, so I will say this right here. you maid a mistake when you quoted the poster. The law of multiplying x^n times x^m gives x^(m+n)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\Large\color{black}{ \displaystyle \rm x^m\times x^n=x^{m+n} }\)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @SolomonZelman u don't accept messages, so I will say this right here. you maid a mistake when you quoted the poster. The law of multiplying x^n times x^m gives x^(m+n) \(\color{blue}{\text{End of Quote}}\) i posted the wrong one facepalm >.<

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm (x^m)^n = x^{m \times n}\]

nuccioreggie
 one year ago
Best ResponseYou've already chosen the best response.0Im so confused the answer is B right??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @Nnesha \[\huge\rm x^m \times x^n = x^{m \times n}\] m=4 n=x m times n = 32 substitute 4 and then solve for n \(\color{blue}{\text{End of Quote}}\) i mean to post this exponent rule \[\huge\rm (x^m)^n = x^{m \times n}\] \[(4^4)^x =4^32 \]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2check your answer \[\huge\rm (4^4)^7 = 4^{32}\] is this right 4 times 7 =32? \[\large\rm (4^4)^8 =4^{32}\] both sides are equal ?? 4 times 8=32 ?? \[\huge\rm (4^4)^4 = 4^{32}\] 4 times 4 = 32 ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2when you multiply both exponents you should get 32 got it ? :)

nuccioreggie
 one year ago
Best ResponseYou've already chosen the best response.0Wow thats not even an answer choice thats the wrong answer

nuccioreggie
 one year ago
Best ResponseYou've already chosen the best response.0If (44)x = 432, what is the value of x? 4 7 8 28

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2i'm saying if you u don't know exponent rules then you can substitute all answer choices for x to check your answer

nuccioreggie
 one year ago
Best ResponseYou've already chosen the best response.0What is the answer to this question

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2you already know \[\huge\rm (4^4)^x =4^{32}\] 4 times x = 32 you got it right!

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yeah i got the same answer 4 times 8 =32
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