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aminamoazzam
 one year ago
Need Help in MCQ's
see attachment .. Plzz help ..
aminamoazzam
 one year ago
Need Help in MCQ's see attachment .. Plzz help ..

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aminamoazzam
 one year ago
Best ResponseYou've already chosen the best response.0These are the questions Ans for 27 is D Ans for Q 28 is A and for 38 is C

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1question #28 field line has to be perpendicular with respect to the surface of the conductors

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so pictures B and D can be excluded

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we can exclude also picture C, since the charge density is greater when the distance between metal plates is smaller. so the right answer is option A

aminamoazzam
 one year ago
Best ResponseYou've already chosen the best response.0thanks .. can u help by explainingg the rest of questions

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1question #36 before removing the resistor W, your circuit is: dw:1433879076085:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1and its equivalent circuit is: dw:1433879222031:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now the current is: I = V/R

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433879314684:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1acros each pair of resistor, there is a voltage drop of \[\frac{R}{2}I = \frac{R}{2} \times \frac{V}{R} = \frac{V}{2}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1and the dissipated powers by the resistors are all equals each other, and they are equal to: \[P = \frac{{{V^2}}}{{4R}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now after rimotion of the resistor W, your circuit becomes: dw:1433879696882:dw and its equivalent circuit is: dw:1433879758406:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1the current is: I=2V/3R power dissipated by resistor X is: \[{P_X} = R{I^2} = R{\left( {\frac{{2V}}{{3R}}} \right)^2} = \frac{{4{V^2}}}{{9R}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1voltage drop across Y and Z resistors is: \[{V_{YZ}} = V  \frac{{2V}}{3} = \frac{V}{3}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1power dissipated by each resistor Y and Z is: \[{P_Y} = {P_Z} = \frac{1}{2}\left( {\frac{{{V^2}}}{R}  \frac{{4{V^2}}}{{9R}}} \right) = \frac{5}{{18}}\frac{{{V^2}}}{R}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1reassuming: before rimotion of X resistor we have: power dissipated by each resistor \[P = \frac{{{V^2}}}{{4R}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1oops. rimotion of Wresistor after rimotion of the Wresistor, we have: power dissipated by the Xresistor: \[{P_X} = \frac{{4{V^2}}}{{9R}}\] power dissipated by the YZ resistors, separately: \[{P_Y} = {P_Z} = \frac{5}{{18}}\frac{{{V^2}}}{R}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1what can you conclude?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1Qustion #27 I'm sorry, I'm not good with diffraction gratings

aminamoazzam
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino Thanks ur explanation really helped me .. i understood both of the questions u explained ..
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