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aminamoazzam

  • one year ago

Need Help in MCQ's see attachment .. Plzz help ..

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  1. aminamoazzam
    • one year ago
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    These are the questions Ans for 27 is D Ans for Q 28 is A and for 38 is C

  2. aminamoazzam
    • one year ago
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    @Michele_Laino

  3. aminamoazzam
    • one year ago
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    @ganeshie8

  4. Michele_Laino
    • one year ago
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    question #28 field line has to be perpendicular with respect to the surface of the conductors

  5. Michele_Laino
    • one year ago
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    @aminamoazzam

  6. Michele_Laino
    • one year ago
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    so pictures B and D can be excluded

  7. Michele_Laino
    • one year ago
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    we can exclude also picture C, since the charge density is greater when the distance between metal plates is smaller. so the right answer is option A

  8. aminamoazzam
    • one year ago
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    thanks .. can u help by explainingg the rest of questions

  9. Michele_Laino
    • one year ago
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    question #36 before removing the resistor W, your circuit is: |dw:1433879076085:dw|

  10. Michele_Laino
    • one year ago
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    and its equivalent circuit is: |dw:1433879222031:dw|

  11. Michele_Laino
    • one year ago
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    now the current is: I = V/R

  12. Michele_Laino
    • one year ago
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    |dw:1433879314684:dw|

  13. Michele_Laino
    • one year ago
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    acros each pair of resistor, there is a voltage drop of \[\frac{R}{2}I = \frac{R}{2} \times \frac{V}{R} = \frac{V}{2}\]

  14. Michele_Laino
    • one year ago
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    and the dissipated powers by the resistors are all equals each other, and they are equal to: \[P = \frac{{{V^2}}}{{4R}}\]

  15. Michele_Laino
    • one year ago
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    now after rimotion of the resistor W, your circuit becomes: |dw:1433879696882:dw| and its equivalent circuit is: |dw:1433879758406:dw|

  16. Michele_Laino
    • one year ago
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    the current is: I=2V/3R power dissipated by resistor X is: \[{P_X} = R{I^2} = R{\left( {\frac{{2V}}{{3R}}} \right)^2} = \frac{{4{V^2}}}{{9R}}\]

  17. Michele_Laino
    • one year ago
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    voltage drop across Y and Z resistors is: \[{V_{YZ}} = V - \frac{{2V}}{3} = \frac{V}{3}\]

  18. Michele_Laino
    • one year ago
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    power dissipated by each resistor Y and Z is: \[{P_Y} = {P_Z} = \frac{1}{2}\left( {\frac{{{V^2}}}{R} - \frac{{4{V^2}}}{{9R}}} \right) = \frac{5}{{18}}\frac{{{V^2}}}{R}\]

  19. Michele_Laino
    • one year ago
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    reassuming: before rimotion of X resistor we have: power dissipated by each resistor \[P = \frac{{{V^2}}}{{4R}}\]

  20. Michele_Laino
    • one year ago
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    oops. rimotion of W-resistor after rimotion of the W-resistor, we have: power dissipated by the X-resistor: \[{P_X} = \frac{{4{V^2}}}{{9R}}\] power dissipated by the Y-Z resistors, separately: \[{P_Y} = {P_Z} = \frac{5}{{18}}\frac{{{V^2}}}{R}\]

  21. Michele_Laino
    • one year ago
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    what can you conclude?

  22. Michele_Laino
    • one year ago
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    Qustion #27 I'm sorry, I'm not good with diffraction gratings

  23. aminamoazzam
    • one year ago
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    @Michele_Laino Thanks ur explanation really helped me .. i understood both of the questions u explained ..

  24. Michele_Laino
    • one year ago
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    :)

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