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anonymous

  • one year ago

A 10.0 Ω resistor is in parallel with a 20.0 Ω resistor and supplied by a 9.00 V battery. What is the total current passing through the circuit? A. 0.38 A B. 1.35 A C. 1.13 A D. 6.00 A

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  1. Michele_Laino
    • one year ago
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    the total or equivalent resistance is: \[\Large {R_{EQ}} = \frac{1}{{\frac{1}{{10}} + \frac{1}{{20}}}} = ...\Omega \]

  2. anonymous
    • one year ago
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    6.6666666?

  3. Michele_Laino
    • one year ago
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    ok!

  4. Michele_Laino
    • one year ago
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    so the total current is: I=90/6.67=...amperes

  5. anonymous
    • one year ago
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    13.49?

  6. Michele_Laino
    • one year ago
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    ok! More precisely it is 13.5 amperes

  7. anonymous
    • one year ago
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    ohh my choices gives me 1.35 A.. would that be the solutoin?

  8. Michele_Laino
    • one year ago
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    sorry, it is: 9/6.67 which is equal to 1.35 amperes

  9. anonymous
    • one year ago
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    oh okay! yay! thanks!!:D

  10. Michele_Laino
    • one year ago
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    :)

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