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anonymous

  • one year ago

Historical Feature 3HK=-p and H^3+K^3=-q solve for K in 3HK=-p and substitute into H^3+K^3=-q. Then show that H=3 sqrt -q/2+sqrtq^2/4+p^3/27

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  1. freckles
    • one year ago
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    Well it says to solve 3HK=-p for K then substitute that into H^3+K^3=-q have you done this part and if so can you show how far you have gotten with it?

  2. anonymous
    • one year ago
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    no

  3. freckles
    • one year ago
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    ok well if you do that you should end up with a quadratic in terms of H^3

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