anonymous
  • anonymous
One 10.0 Ω resistor is wired in series with two 10.0 Ω resistors in parallel. A 45.0 V battery supplies power to the circuit. What is the total current through the circuit? A. 3.0 A B. 1.5 A C. 0.75 A D. 0.33 A
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Michele_Laino
  • Michele_Laino
|dw:1433875036891:dw|
anonymous
  • anonymous
equilvalent resistance is 30?
Michele_Laino
  • Michele_Laino
no, it is: \[\Large {R_{EQ}} = 10 + \frac{1}{{\frac{1}{{10}} + \frac{1}{{10}}}} = ...\Omega \]

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anonymous
  • anonymous
oh oops ! so it is 5!
Michele_Laino
  • Michele_Laino
are you sure?
anonymous
  • anonymous
oh oops i did not see the 10 in front! so it is 15!
Michele_Laino
  • Michele_Laino
correct!
Michele_Laino
  • Michele_Laino
now, the requested current is: I=45/15=...amperes
anonymous
  • anonymous
3! so our solution is choice A? :O
Michele_Laino
  • Michele_Laino
that's right!
anonymous
  • anonymous
yay! thank you!!:D
Michele_Laino
  • Michele_Laino
:)

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