## anonymous one year ago One 10.0 Ω resistor is wired in series with two 10.0 Ω resistors in parallel. A 45.0 V battery supplies power to the circuit. What is the total current through the circuit? A. 3.0 A B. 1.5 A C. 0.75 A D. 0.33 A

1. Michele_Laino

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2. anonymous

equilvalent resistance is 30?

3. Michele_Laino

no, it is: $\Large {R_{EQ}} = 10 + \frac{1}{{\frac{1}{{10}} + \frac{1}{{10}}}} = ...\Omega$

4. anonymous

oh oops ! so it is 5!

5. Michele_Laino

are you sure?

6. anonymous

oh oops i did not see the 10 in front! so it is 15!

7. Michele_Laino

correct!

8. Michele_Laino

now, the requested current is: I=45/15=...amperes

9. anonymous

3! so our solution is choice A? :O

10. Michele_Laino

that's right!

11. anonymous

yay! thank you!!:D

12. Michele_Laino

:)