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anonymous

  • one year ago

If each resistor in the circuit drawn inside is 10.0 ohms, and the battery is 60.0 V, what does the first ammeter (A1) read? A. 0.6 A B. 1.2 A C. 2.4 A D. 3.6 A

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  1. anonymous
    • one year ago
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    |dw:1433875564463:dw|

  2. Michele_Laino
    • one year ago
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    your circuit is equivalent to this one: |dw:1433875598502:dw|

  3. Michele_Laino
    • one year ago
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    am I right?

  4. anonymous
    • one year ago
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    ohh !

  5. Michele_Laino
    • one year ago
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    two resistances of 10 ohm each, in parallel are equivalent to a single resistance of 5 ohm

  6. Michele_Laino
    • one year ago
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    now, the current is: I=60/(10+5+10)=...amperes

  7. anonymous
    • one year ago
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    60/25=2.4! so choice C is our solution?

  8. Michele_Laino
    • one year ago
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    yes! that's right! |dw:1433875809088:dw|

  9. anonymous
    • one year ago
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    yay!! thank you!:D

  10. Michele_Laino
    • one year ago
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    :)

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