3HK=-p and H^3+K^3=-q
solve for K in 3HK=-p and substitute into H^3+K^3=-q. Then show that
H=3 sqrt -q/2+sqrtq^2/4+p^3/27
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Did you have any luck with this?
solve for K
K = -p / (3H)
substitute into H^3 + K^3 = -q
H^3 + (-p / (3H))^3 = -q
Can you continue from here?
@concad I have noticed you have done this with previous problems. Close questions and then make a new question with the same question. Is this because you don't want to do the problem and you want us to? This isn't how OpenStudy is suppose to work. We are suppose to be here to help, not do your homework for you.
Not the answer you are looking for? Search for more explanations.
@jayzdd has actually did exactly what the problem has asked up till the solving for H part
he solved that one equation for K
and plugged in that result into the other equation
I gave you another hint on the previous thread...I said you should expect a quadratic in terms of H^3.