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anonymous

  • one year ago

Historical Feature 3HK=-p and H^3+K^3=-q solve for K in 3HK=-p and substitute into H^3+K^3=-q. Then show that H=3 sqrt -q/2+sqrtq^2/4+p^3/27

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  1. anonymous
    • one year ago
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    Did you have any luck with this?

  2. anonymous
    • one year ago
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    solve for K K = -p / (3H) substitute into H^3 + K^3 = -q H^3 + (-p / (3H))^3 = -q Can you continue from here?

  3. freckles
    • one year ago
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    @concad I have noticed you have done this with previous problems. Close questions and then make a new question with the same question. Is this because you don't want to do the problem and you want us to? This isn't how OpenStudy is suppose to work. We are suppose to be here to help, not do your homework for you.

  4. freckles
    • one year ago
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    @jayzdd has actually did exactly what the problem has asked up till the solving for H part he solved that one equation for K and plugged in that result into the other equation I gave you another hint on the previous thread...I said you should expect a quadratic in terms of H^3.

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