Which expression is equivalent to 73 ⋅ 7−5? 72 77 1 over 7 to the 2nd power 1 over 7 to the 7th power

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Which expression is equivalent to 73 ⋅ 7−5? 72 77 1 over 7 to the 2nd power 1 over 7 to the 7th power

Mathematics
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Show your work. Don't forget your Order of Operations.
So \[\large7^3*\large7^{-5}\]?

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Other answers:

Ok 1sec
Yea thats the question
\[\Large7^3*\Large7^{-5}=\Large7^{3-5}\]
I think the answer is B
And why do you think that?
Idk
To multiply powers with the same base, give the same base and add the exponents. Examples: \(\large 5^8 \cdot 5^7 = 5^{8 + 7} = 5^{15} \) \(\large 3^{-5} \cdot 3^4 = 3^{-5 + 4} = 3^{-1} \)
Also, after you multiply the powers together using the rule above, you need to know what to do with a negative exponent. For that use this rule: \(\large a^{-n} = \dfrac{1}{a^n} \) Example: \(\large 5^{-3} = \dfrac{1}{5^3} = \dfrac{1}{125} \)
Ok i just did that and i got the answer choice
A
First, multiply the powers together. The base is 7. What do you get for the exponent?
What is 3 + (-5) = ?
-2
Sorry if i typee the same thing twice its not moe its my computer
Good. So far you are correct. |dw:1433878869336:dw|
Now you need to deal with the negative exponent. See my example above. A negative exponent ends up as a fraction.
Ohhhhh ok so its C
Correct! |dw:1433878981234:dw|
Ok thanks can you help me with 2 more only please
And let's work on that notation. 73 ⋅ 7−5 = 73*7 - 5 = 511 - 5 = 506 Find SOME way to indicate an exponent. 7^3 * 7^(-5) Perhaps.

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