nuccioreggie
  • nuccioreggie
Conner and Jana are multiplying (3568)(39610). Conner's Work Jana's Work (3568)(39610) = 35 + 968 + 10 = 314618 (3568)(39610) = 35⋅968⋅10 = 345680 Is either of them correct? Explain your reasoning.
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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nuccioreggie
  • nuccioreggie
@Michele_Laino
nuccioreggie
  • nuccioreggie
Please help
anonymous
  • anonymous
I'm gonna assume this is using exponents. Am I right?

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nuccioreggie
  • nuccioreggie
Yes and here is what i got They are both incorrect. There results should be way more then in the thousands range, they should be more like in the millions.
anonymous
  • anonymous
Do you mind drawing out what the exponents look like so I can see?
nuccioreggie
  • nuccioreggie
Here it is
Nnesha
  • Nnesha
please next time type your question don't just copy&paste it's also against the COC or TAC :-) :-)
nuccioreggie
  • nuccioreggie
Ok but is my answer right
nuccioreggie
  • nuccioreggie
??
Nnesha
  • Nnesha
mhm i was waiting 4 legend reply well what's the exponent rule ? when you multiply same bases what you should do with their exponents ?
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @nuccioreggie Yes and here is what i got They are both incorrect. There results should be way more then in the thousands range, they should be more like in the millions. \(\color{blue}{\text{End of Quote}}\) nope. you don't need a calculator solve this question
Nnesha
  • Nnesha
to*
Michele_Laino
  • Michele_Laino
please use this rule: \[\Large {a^m} \times {a^n} = {a^{m + n}}\]
TheSmartOne
  • TheSmartOne
Your answer is wrong. Use the formula Michele gave and work from there.
Nnesha
  • Nnesha
write these dwn 'n ur notebook exponent rules \[\large\rm x^m \times x^n = x^{m +n}\]\[\large\rm (x^m)^n = x^{m \times n}\]\[\large\rm \frac{ x^m }{ x^n }=x^{m-n}\]

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