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anonymous
 one year ago
Medal + fan
Simplify the expression.
x times the square root of the quantity 8 x cubed, plus x times the square root of 2, plus four times the square root of the quantity 2x
anonymous
 one year ago
Medal + fan Simplify the expression. x times the square root of the quantity 8 x cubed, plus x times the square root of 2, plus four times the square root of the quantity 2x

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x \sqrt{8x ^{3}} + x \sqrt{2} + 4\sqrt{2x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm usually good at math but this question is a little confusing.... So far I think the answer is 2 because yo can simplify it to get 2x^2sqrt(2x)... and so on

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[2\sqrt{2} \times x \times x ^{3/2} + x \times \sqrt{2} + 4 \sqrt{2} \times x^{1/2} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0To write it into its raw exponential form.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why did you put fractions in the radical?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0By putting the exponents in their fraction forms, you can clearly see their combined values.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This will allow you to factor out an exponential of x, through subtraction of the exponent.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0As you can see in this question, the lowest "factorable" term is \[\sqrt{x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm only in ninth grade, I don't think this is necessary.. besides, I haven't learned this yet.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not looking for the lowest factorable term.... I'm looking for the leading coefficient when it's in simplified form

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But it's factored form looks something like this: \[\sqrt{2} \sqrt{x} (4+\sqrt{x}+2 x^2)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0To do that, you need write out the terms in full and subtract the exponents when factoring.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think we're looking for the simplified form not the factored form... \[2x^2 \sqrt{2x} + x \sqrt{2} + 4 \sqrt{2x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is this fully simplified?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, I suppose you can't go any further to "simplify" it without factoring.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, so we agree that the leading coefficient is 2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, thanks, I got it right!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The leading coefficient of the entire term is not 2, its \[2\sqrt{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0100% on my quiz! woot!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, I guess it was the answer they were looking for!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0As promised... medal and fan....
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