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anonymous
 one year ago
Find the perimeter of the following shape:
Shape ABCD is shown. Point A is at 7, 5. Point B is at 6, 3. Point C is at 3, 2. Point D is at 4, 4.
10.8
11
11.4
11.6
anonymous
 one year ago
Find the perimeter of the following shape: Shape ABCD is shown. Point A is at 7, 5. Point B is at 6, 3. Point C is at 3, 2. Point D is at 4, 4. 10.8 11 11.4 11.6

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://learn.flvs.net/webdav/assessment_images/educator_geometry/v15/module06/0600_g12_q4.jpg

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0I um failed but @johnweldon1993 it the best user in OS hes the recommendation i was talking about lol

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Lol I appreciate that @Here_to_Help15 So sadly the link wont load for me however let me draw a rough sketch dw:1433883395422:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh crap dude im sorry i coul have screen shotted it for you. sorry u had to draw it out

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Let me label it with the ABCD lol dw:1433883546238:dw

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Lol no worries...at least there weren't like decimals or crap like that lol

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Okay...so we need the distance between all these points Lets work with just points A and B for now Point A is at (7,5) Point B is at (6,3) How far down and how far over from point A do you have to go to get to point B? You have to go down 2 units...and over to the left 1 unit right?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Okay...so now dw:1433883752245:dw Look familiar?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2It's a right triangle Which means we can use the Pythagorean Theorem to solve for that missing length \[\large a^2 + b^2 = c^2\] we need 'c' so \[\large c = \sqrt{a^2 + b^2}\] which here would be \[\large c = \sqrt{1^2 + 2^2} = \sqrt{1 + 4} = \sqrt{5}\] That is the distance between A and B...did that process make sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes that makes sence

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Okay good...so we just do that for each of these points... Distance from A to B 2 down, 1 over ...then just \(\large c = \sqrt{2^2 + 1^2} = \sqrt{5}\) Distance from B to C 1 down, 3 over so \(\large c = \sqrt{1^2 + 3^3} = \sqrt{10}\) Distance from C to D 2 up, 1 over so \(\large c = \sqrt{2^2 + 1^2} = \sqrt{5}\) and Distance from D to A 1 up, 3 over so \(\large c = \sqrt{1^2 + 3^2} = \sqrt{10}\) SO! Now that we have all those distances.. dw:1433884295940:dw We just add them all together to get the perimeter

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2So \[\large Perimeter = \sqrt{5} + \sqrt{5} + \sqrt{10} + \sqrt{10}\] \[\large Perimeter = 2\sqrt{5} + 2\sqrt{10} = ?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got 10.79 so it would be 10.8? SO A??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yess thank you so much!!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can u help me with another?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Maybe...not very good in math :P lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha umm what? r u crazy? u r really good at math

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Okay so Arc length can be found using the formula \[\large s = r\theta\]

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Told ya he was good lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha i know @Here_to_Help15 thank you alos very very much

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2BUT! 1 thing that may trip you up is we need the angle in radiens to convert the angle to radiens we need to do \(\large \theta \times \frac{\pi}{180}\) so here \(\large 30 \times \frac{\pi}{180} = \frac{30\pi}{180} = \frac{\pi}{6}\) So all we need to do is \[\large s = r\theta = 6ft \times \frac{\pi}{6} = ?\]

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Dont thank me thank him ^ lol

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0and pfft not good at math thats a good one lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hold on i think i did this wrong... im trying to get this into my calculator but its being dumb

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Not quite :) Want an easier hint? \[\large \cancel{6}\times \frac{\pi}{\cancel{6}} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh haha wow i am dumb i got it now thank you.....

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2No you're not...you absolutely can go through the calculator...but why go through all that when there are shortcuts :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha yes u just set it up in a way that i understand the second time!! thank you soooooo freaking much u have no idea how much of a help u are!!!!

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0\(\Huge\tt\color{#f9bec7}{He's~Right~ lol }\)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Well that's what I'm here for :) if you need anything else feel free to message me or tag me in a question :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is the last one i need help with!!!

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0\(\Huge\tt\color{#3c0808}{Can~i ~Borrow~you~now~Lol !}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0u can help @Here_to_Help15 fist though

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0\(\Huge\tt\color{#f9bec7}{Ladies~ First :) }\)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Oh geez another one!? ;D haha just kidding Okay... dw:1433885518952:dw

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2With a right triangle...what do we know about sin and cos?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha im sorry last one i promis :p

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Can i join this post i am also learning this :)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Lol you already are part of the post :P but just work along and then we can work with yours :D

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Sine Function: sin(θ) = Opposite / Hypotenuse Cosine Function: cos(θ) = Adjacent / Hypotenuse Tangent Function: tan(θ) = Opposite / Adjacent

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sin = opposite over hypotenuse cos= adjacent over hypotenuse

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0I might as well throw tangent in the mix as well lol

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Perfect @CayleeS23 Okay...so in your question...it asks for sin(x) So we look at your triangle...go to the 'x' degree....and look what is opposite that angle...and look at what the hypotenuse is so dw:1433885706708:dw So that would mean \[\large sin(x) = \frac{opposite}{hypotenuse} = \frac{3}{5}\]

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2clearly I cannot spell _ lol

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0haha my teacher just literally did a livelesson on this at 12 pm

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0So then that means you need a calculator

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2No not at all (here anyways) this question only wants the ratios....which that is :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait wouldnt it be A?

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Oh lol i thought it was going more further

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2So that is the process to find the sin(x) @CayleeS23 now you show me how to find cos(y) *or just answer it correctly..pfft okay >.< XD Yes A is correct :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha sorry!! i got it once u posted how to find sin i just did the same with cos using its rule then looked back at the answers :p i would draw it out like u but i have no idea how

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Yeah it takes some pretty advanced drawing skills ;) XD But either way awesome job! See you didnt even need my help :P

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0\(\Huge\tt\color{#82ffd6}{Oh~I~See!}\)

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0sorry guys i love doing latex lol

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2\[\Huge\tt\color{#82ffd6}{OIC!}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha yes i did need your help :p your drawing skills uff ya know they pef hahahaha

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0\(\large\tt\color{#99d3f0}{LIKE~IK~RIGHT! }\)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2XD lol mmhmm we're gonna be good friends @CayleeS23 :P

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0\(\Huge\tt\color{#f9bec7}{Hahaha!}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0think* damn i cant type either

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2As long as you dont.. <.< >.> Stalk me :O XD no jk that's invited too XDDD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hahahha oh my!! imma dm you

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0\(\Huge\tt\color{#f9bec7}{Im~so~lonely~got~nobody~*cries* }\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whattt nooo u got me @Here_to_Help15 your chill man!

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0\(\Huge\tt\color{#f9bec7}{*Heart~Breaks </3* !}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0brb i have like 2 questions then i can turn this in and then i can chat with yall!!

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2\[\bbox [10pt, black, border:5pt solid blue]{\Huge\cal\color{red}{\bigstar}\color{orange}{I}\color{yellow}{T}\space \color{green}{W}\color{blue}{I}\color{indigo}{L}\color{violet}{L}\space\color {red}{B}\color{orange}{E}\space \color{yellow}{O}\color{green}{K}\color{blue}{A}\color{indigo}{Y}\space \color{violet}{H}\color{red}{A}\color{orange}{H}\color{yellow}{A}\color{red}{\bigstar}}\]

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0OMG LOOK WHAT SOMEONE SENT ME please help me our else i will go to the open study board and say your name that you didn't help.So please help me in english please right now.

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0How do you that one lol @johnweldon1993

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Argh i tend to discover them lol

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Out of the blue question but john do you play clash of clans ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0omg poeple on here r crazy af.. report that person

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0lol i told him "is that a virtual threat because im loving it :)"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hahha yess thats great

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Lol and no I dont play clash of clans @Here_to_Help15

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0John you happen to speak french?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2I took 3 years of French in High school but other than introducing myself I would die quickly in France XD
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