A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

mathmath333

  • one year ago

Solve

  • This Question is Closed
  1. mathmath333
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \(\large \color{black}{\begin{align} &x^2+5|x|+6=0\\~\\ &x\in \mathbb{R}\hspace{.33em}\\~\\ \end{align}}\)

  2. tkhunny
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    Eyeball problem. No Solution. \(x^{2}\) is at least zero (0). \(5|x|\) is at least zero (0). The entire expression CANNOT be less than 6. Done! Sometimes, they just jump out at you. No need to fret over them.

  3. mathmath333
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is there any other way to do this

  4. TheSmartOne
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    If you graphed it, you would get: https://www.desmos.com/calculator/3bps8xaezl and you can tell that there will never be an x value that will make y=0 because the smallest value of y is 6.

  5. TheSmartOne
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    And to explain what tkhunny said for others who don't understand what he said right away like myself. We have `+ 6` in the equation. So that means `x^2 + x|5|` has to equal `-6` in order for the whole equation to be negative However, there will never be any x value that will make it -6. And since we have `x^2`, any value of x that goes into that will be positive And then there is `5|x|` any x value plugged in will also come out as positive. So thus `x^2+5|x|` will never be negative. So it can not have any solutions.

  6. ybarrap
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Here's another way. $$ x^2+5|x|+6=0 $$ means for \(x\ge0\) $$ x^2+5|x|+6=x^2+5x+6=0 $$ Which has solutions \(x=-3,x=-2\). But \(x\ge0\) so there is no solution. for \(x\le0\) $$ x^2+5|x|+6=x^2-5x+6=0 $$ Which has solutions \(x=3,x=2\). But \(x\le0\) so there is no solution.

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Hi Use following tool to solve this problem http://www.acalculator.com/log.html

  8. tkhunny
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    Another way? Why?! Shall we use the brute force of 7th grade algebra or whatever app someone wrote or shall we think and use good judgment and just be done? Note: On a GRE, LSAT, MCAT, or other significant examination, you WILL want the fast way.

  9. mathmath333
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    teacher wont give me marks

  10. tkhunny
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    Shame on that teacher. If you were my child, or a student under my tutelage, I would have words with that teacher. Logic is as valid as any other construct. Shameful. Simply shameful.

  11. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.