• anonymous
What is the total number of N, H, and O atoms in 0.956 mol of ammonium nitrate, NH4NO3, an important fertilizer? anyone able to help please?
  • Stacey Warren - Expert
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
  • schrodinger
I got my questions answered at in under 10 minutes. Go to now for free help!
  • hpfan101
There's 6.022 x 10^23 molecules in one mole. So since there's 0.956 moles of ammonium nitrate, we want to find the number of molecules. So multiply 0.956 by avagodro's # (6.022 x 10^23). After you get the number of molecules, to find the total # of N, H, and O atoms, just multiply that number by how many of the elements there are. So since there's 2 nitrogen in ammonium nitrate, you would multiply 2 by the answer you got previously. And you do the same thing to find for hydrogen and oxygen.

Looking for something else?

Not the answer you are looking for? Search for more explanations.