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anonymous

  • one year ago

Medal goes to whoever helps

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  1. anonymous
    • one year ago
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    What is the question?

  2. GenTorr
    • one year ago
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    dont know

  3. anonymous
    • one year ago
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    gen are you good at economics?

  4. anonymous
    • one year ago
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    oops sorry i totally forgot

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  5. anonymous
    • one year ago
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    @Marlins0412 @GenTorr

  6. anonymous
    • one year ago
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    I alson need help with this one

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  7. GenTorr
    • one year ago
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    what???

  8. anonymous
    • one year ago
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    what do you mean lol cause i tagged you?

  9. GenTorr
    • one year ago
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    noo didn't see the document you sent

  10. GenTorr
    • one year ago
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    lol

  11. anonymous
    • one year ago
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    which one the first?

  12. anonymous
    • one year ago
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    can you see it know?

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  13. GenTorr
    • one year ago
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    yes i can

  14. GenTorr
    • one year ago
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    i would say 90

  15. anonymous
    • one year ago
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    hmm how did you get that if you don't mind me asking?

  16. GenTorr
    • one year ago
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    sure

  17. anonymous
    • one year ago
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    Its 90 degrees.

  18. mathmate
    • one year ago
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    Hint: PQ makes 60\(^\circ\) with the horizontal, while RS is parallel to the horizontal.

  19. GenTorr
    • one year ago
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    okay i got 90 because it said that the center of O to pqrf makes 90 degrees |dw:1433889605766:dw|

  20. anonymous
    • one year ago
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    oh,Thanks can you help me with a couple more please?

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  21. GenTorr
    • one year ago
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    sure

  22. anonymous
    • one year ago
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    Wait it would be 300 degrees

  23. GenTorr
    • one year ago
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    how??

  24. anonymous
    • one year ago
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    @mathmate Thats what my teacher told me, but i didn't get it...

  25. anonymous
    • one year ago
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    Because It would only take 60 degrees to make PQ Line up to RF or 300 degrees to make it happen

  26. GenTorr
    • one year ago
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    unless you go from f to n clock wise

  27. mathmate
    • one year ago
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    We are mapping PQ to RF, so P->R, and Q->F so far so good? Think of mapping OP-> OR What is the angle needed (CCW)

  28. anonymous
    • one year ago
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    umm you've lost me... is it 60

  29. mathmate
    • one year ago
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    In the Cartesian plane, all angles are counter-clockwise.

  30. mathmate
    • one year ago
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    |dw:1433889923664:dw|

  31. anonymous
    • one year ago
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    i see that, can you kind of tell me what the translation rule is?

  32. GenTorr
    • one year ago
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    exsactly that's what i was trying to say

  33. GenTorr
    • one year ago
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    f to n = 300

  34. mathmate
    • one year ago
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    I would put it as \(R_{O,300}\) a rotation about O of 300 degrees (understood to be CCW)

  35. GenTorr
    • one year ago
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    true im kindergarten style lol

  36. anonymous
    • one year ago
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    Can you help me with one last question?

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  37. mathmate
    • one year ago
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    @GenTorr Would you be able to work out the second problem with @MacBabe ?

  38. mathmate
    • one year ago
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    BTW, the first problem is a rotation, not translation.

  39. GenTorr
    • one year ago
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    sure

  40. mathmate
    • one year ago
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    Thank you!

  41. GenTorr
    • one year ago
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    i was looking at it right now

  42. anonymous
    • one year ago
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    I know that but i was confused about the translation rule, my teacher was trying to explain it to me and i just... yea

  43. GenTorr
    • one year ago
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    yup i was confused too

  44. anonymous
    • one year ago
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    can you help? or you don't get it

  45. GenTorr
    • one year ago
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    i can help im just figuring it out

  46. anonymous
    • one year ago
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    @GenTorr did you give Mathmate a medal? Thanks if you did cause i also wanted to give him or her a medal but you can only give one

  47. GenTorr
    • one year ago
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    yup i did

  48. GenTorr
    • one year ago
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    wow this is hard to understand O_O

  49. anonymous
    • one year ago
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    Yea it was hard for me too but if you can't help thanks anway c:

  50. GenTorr
    • one year ago
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    yup

  51. anonymous
    • one year ago
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    alright thanks anyway

  52. anonymous
    • one year ago
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    i'll just open a new post and hope for the best

  53. anonymous
    • one year ago
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    Im not sure about it either sorry. Maybe ask @mathmate.

  54. anonymous
    • one year ago
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    @brandonford7 thanks anyway c:

  55. mathmate
    • one year ago
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    @MacBabe any ideas?

  56. mathmate
    • one year ago
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    Can you start by describing the question in your own words?

  57. anonymous
    • one year ago
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    Um no cause TBH these problems confuse the heck out of me but i can try. I think the question is to find the matching translation?

  58. mathmate
    • one year ago
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    I'll start: A point P is transformed to P' through a glide reflection. A glide reflection is a translation T, followed by a reflection S. P' is given (-8,-3), but P is the point we'd like to find. Can you continue by reading through the question and plugging in numbers for the reflection and the translation?

  59. anonymous
    • one year ago
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    wait is it c?

  60. mathmate
    • one year ago
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    I don't look at answers before I have mine, sorry... unless you can explain to me how you got it.

  61. anonymous
    • one year ago
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    (-2, -3) i honestly just guessed, so i just have to plug in each answer to (x,y)->(x,y-5).. (x,y) would be (-8,3) right? so (-8,3) -> (x,y-5) i have to feel it in with the numbers that are the answers? See o know i'm wrong its just confusing to me

  62. mathmate
    • one year ago
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    |dw:1433892913007:dw|

  63. mathmate
    • one year ago
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    |dw:1433893125603:dw|

  64. mathmate
    • one year ago
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    The transformation is done by reflecting P across the line x=-5 to Q. After that, the translation (x,y)->(x, y-5) brings Q to P'(-8,3).

  65. mathmate
    • one year ago
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    Are you foollowing so far? See if you can figure out what the coordinates of P(x,y) are.

  66. anonymous
    • one year ago
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    yea i am

  67. mathmate
    • one year ago
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    So starting with P(x,y), what would be the coordinates of Q, knowing that there is a reflection about x=-5 ?

  68. mathmate
    • one year ago
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    Perhaps it's easier to work backwards. We know that a translation of (x,y)->(x,y-5) brings Q to P'. So what translation will bring P' to Q?

  69. anonymous
    • one year ago
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    (-8,2) or was it (8,3) Geometry is my worst subject i'm barley passing with a C, sorry if i'm not doing any good theres just to many math terms that don't make since to me. I think its one of those

  70. mathmate
    • one year ago
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    The inverse transformation of the translation (x,y)->(x,y-5) is (x,y)->(x,y+5). So yes, (-8,-3) ->(-8,-3+5) or Q(-8,+2)

  71. mathmate
    • one year ago
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    Now the reflection about x=-5 is (x,y) -> (-5-(x-(-5)),y), or \(\color{red}{(x,y)-> (-10-x, ~~y)}\) and the inverse of a reflection is the reflection itself. Can you now find P as the reflection of Q about x=-5 ?

  72. anonymous
    • one year ago
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    wait but what would be y? or is y suppose to be p or something?

  73. mathmate
    • one year ago
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    y->y means no change x->-10-x means x undergoes a reflection about x=-5. Recall we are transforming from Q to P.

  74. anonymous
    • one year ago
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    wait x y -3 - - x y - 5 so is the answer (-8,2) (me attempting to get this)

  75. anonymous
    • one year ago
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    @mathmate that must not be the answer than...

  76. mathmate
    • one year ago
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    (-8, 2) is the correct answer for Q (the intermediate step). You'd still do the reflection from Q to P to get the final answer.

  77. mathmate
    • one year ago
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    Just to refresh the memory! |dw:1433896416150:dw|

  78. anonymous
    • one year ago
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    -8,-8?

  79. mathmate
    • one year ago
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    the reflection about x=-5 is i(x,y)−>(−10−x, y)

  80. anonymous
    • one year ago
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    ok.

  81. mathmate
    • one year ago
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    Start with Q(-8,2) and apply reflection!

  82. anonymous
    • one year ago
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    I ended up turning it in with the answer -2, -3 it was possibly wrong, i just couldn't get it. you had a lot of patients with me so thanks for that c:

  83. mathmate
    • one year ago
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    Well, didn't we establish that Q(-8,-2) ?

  84. mathmate
    • one year ago
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    that was after the translation, and before the reflection, right?

  85. anonymous
    • one year ago
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    yes.

  86. mathmate
    • one year ago
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    To do the reflection Q->P, we apply the rule: Q(-8,2) -> P(-10-(-8), 2) after we simplified -10-(-8)=-10+8=-2, so P(-2,2) and that's your answer.

  87. anonymous
    • one year ago
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    oh, well thanks anyway.

  88. mathmate
    • one year ago
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    Once you understand how the rules are used, the transformations are easy. It may be harder to figure out the rules, but with time, you'll master it.

  89. anonymous
    • one year ago
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    yea i hope

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