Medal goes to whoever helps

- anonymous

Medal goes to whoever helps

- Stacey Warren - Expert brainly.com

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- katieb

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- anonymous

What is the question?

- GenTorr

dont know

- anonymous

gen are you good at economics?

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## More answers

- anonymous

oops sorry i totally forgot

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- anonymous

@Marlins0412 @GenTorr

- anonymous

I alson need help with this one

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- GenTorr

what???

- anonymous

what do you mean lol cause i tagged you?

- GenTorr

noo didn't see the document you sent

- GenTorr

lol

- anonymous

which one the first?

- anonymous

can you see it know?

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- GenTorr

yes i can

- GenTorr

i would say 90

- anonymous

hmm how did you get that if you don't mind me asking?

- GenTorr

sure

- anonymous

Its 90 degrees.

- mathmate

Hint:
PQ makes 60\(^\circ\) with the horizontal, while RS is parallel to the horizontal.

- GenTorr

okay i got 90 because it said that the center of O to pqrf makes 90 degrees |dw:1433889605766:dw|

- anonymous

oh,Thanks can you help me with a couple more please?

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- GenTorr

sure

- anonymous

Wait it would be 300 degrees

- GenTorr

how??

- anonymous

@mathmate Thats what my teacher told me, but i didn't get it...

- anonymous

Because It would only take 60 degrees to make PQ Line up to RF or 300 degrees to make it happen

- GenTorr

unless you go from f to n clock wise

- mathmate

We are mapping PQ to RF, so P->R, and Q->F
so far so good?
Think of mapping OP-> OR
What is the angle needed (CCW)

- anonymous

umm you've lost me... is it 60

- mathmate

In the Cartesian plane, all angles are counter-clockwise.

- mathmate

|dw:1433889923664:dw|

- anonymous

i see that, can you kind of tell me what the translation rule is?

- GenTorr

exsactly that's what i was trying to say

- GenTorr

f to n = 300

- mathmate

I would put it as
\(R_{O,300}\)
a rotation about O of 300 degrees (understood to be CCW)

- GenTorr

true im kindergarten style lol

- anonymous

Can you help me with one last question?

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- mathmate

@GenTorr
Would you be able to work out the second problem with @MacBabe ?

- mathmate

BTW, the first problem is a rotation, not translation.

- GenTorr

sure

- mathmate

Thank you!

- GenTorr

i was looking at it right now

- anonymous

I know that but i was confused about the translation rule, my teacher was trying to explain it to me and i just... yea

- GenTorr

yup i was confused too

- anonymous

can you help? or you don't get it

- GenTorr

i can help im just figuring it out

- anonymous

@GenTorr did you give Mathmate a medal? Thanks if you did cause i also wanted to give him or her a medal but you can only give one

- GenTorr

yup i did

- GenTorr

wow this is hard to understand O_O

- anonymous

Yea it was hard for me too but if you can't help thanks anway c:

- GenTorr

yup

- anonymous

alright thanks anyway

- anonymous

i'll just open a new post and hope for the best

- anonymous

Im not sure about it either sorry. Maybe ask @mathmate.

- anonymous

@brandonford7 thanks anyway c:

- mathmate

@MacBabe any ideas?

- mathmate

Can you start by describing the question in your own words?

- anonymous

Um no cause TBH these problems confuse the heck out of me but i can try. I think the question is to find the matching translation?

- mathmate

I'll start:
A point P is transformed to P' through a glide reflection.
A glide reflection is a translation T, followed by a reflection S.
P' is given (-8,-3), but P is the point we'd like to find.
Can you continue by reading through the question and plugging in numbers for the reflection and the translation?

- anonymous

wait is it c?

- mathmate

I don't look at answers before I have mine, sorry... unless you can explain to me how you got it.

- anonymous

(-2, -3) i honestly just guessed, so i just have to plug in each answer to (x,y)->(x,y-5).. (x,y) would be (-8,3) right? so (-8,3) -> (x,y-5) i have to feel it in with the numbers that are the answers? See o know i'm wrong its just confusing to me

- mathmate

|dw:1433892913007:dw|

- mathmate

|dw:1433893125603:dw|

- mathmate

The transformation is done by reflecting P across the line x=-5 to Q. After that, the translation (x,y)->(x, y-5) brings Q to P'(-8,3).

- mathmate

Are you foollowing so far?
See if you can figure out what the coordinates of P(x,y) are.

- anonymous

yea i am

- mathmate

So starting with P(x,y), what would be the coordinates of Q, knowing that there is a reflection about x=-5 ?

- mathmate

Perhaps it's easier to work backwards.
We know that a translation of
(x,y)->(x,y-5)
brings Q to P'.
So what translation will bring P' to Q?

- anonymous

(-8,2) or was it (8,3) Geometry is my worst subject i'm barley passing with a C, sorry if i'm not doing any good theres just to many math terms that don't make since to me. I think its one of those

- mathmate

The inverse transformation of the translation
(x,y)->(x,y-5) is (x,y)->(x,y+5).
So yes,
(-8,-3) ->(-8,-3+5) or Q(-8,+2)

- mathmate

Now the reflection about x=-5 is
(x,y) -> (-5-(x-(-5)),y), or
\(\color{red}{(x,y)-> (-10-x, ~~y)}\)
and the inverse of a reflection is the reflection itself.
Can you now find P as the reflection of Q about x=-5 ?

- anonymous

wait but what would be y? or is y suppose to be p or something?

- mathmate

y->y means no change
x->-10-x means x undergoes a reflection about x=-5.
Recall we are transforming from Q to P.

- anonymous

wait
x y -3
- -
x y - 5
so is the answer (-8,2) (me attempting to get this)

- anonymous

@mathmate that must not be the answer than...

- mathmate

(-8, 2) is the correct answer for Q (the intermediate step).
You'd still do the reflection from Q to P to get the final answer.

- mathmate

Just to refresh the memory!
|dw:1433896416150:dw|

- anonymous

-8,-8?

- mathmate

the reflection about x=-5 is
i(x,y)−>(−10−x, y)

- anonymous

ok.

- mathmate

Start with Q(-8,2) and apply reflection!

- anonymous

I ended up turning it in with the answer -2, -3 it was possibly wrong, i just couldn't get it. you had a lot of patients with me so thanks for that c:

- mathmate

Well, didn't we establish that Q(-8,-2) ?

- mathmate

that was after the translation, and before the reflection, right?

- anonymous

yes.

- mathmate

To do the reflection Q->P, we apply the rule:
Q(-8,2) -> P(-10-(-8), 2)
after we simplified -10-(-8)=-10+8=-2, so
P(-2,2)
and that's your answer.

- anonymous

oh, well thanks anyway.

- mathmate

Once you understand how the rules are used, the transformations are easy.
It may be harder to figure out the rules, but with time, you'll master it.

- anonymous

yea i hope

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