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- Nnesha

take out common factor
let sin x=y
so y^2 +y what's the common factor ?

- johnweldon1993

This is \(\large sin^2(x) + sin(x) = 0\) right?
or \(\large sin(2x) + sin(x) = 0\) ?

- anonymous

no first one lol

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## More answers

- johnweldon1993

Then perfect go ahead with the process @Nnesha was showing :)
Look at it as sin(x) = y so sin^2(x) = y^2
\[\large y^2 + y = 0\]
What can you factor out?

- xapproachesinfinity

still troubled by this or solved it

- anonymous

troubled @xapproachesinfinity

- xapproachesinfinity

so you have no idea how to factor y^2+y=0?
what is common btw y^2 and y?

- xapproachesinfinity

let's us go to the basics
how can you do this a(b+c)=?
using distributive law?

- xapproachesinfinity

i want you to interact with me otherwise i will just take my leave haha

- anonymous

sorry i was doing somethin away from the laptop.. but i have NO IDEA how to do this ABSOLUTELY NONE!

- anonymous

- Nnesha

yes?

- xapproachesinfinity

ok back let's pick it up where i left it
know of distributive law?

- anonymous

nope :( im so sorry im making this hell for u wish i did :/

- xapproachesinfinity

realize that is the basic math? from lower grades

- xapproachesinfinity

so distributive law tells us that a(b+c)=ab+ac
the left hand side is the same are the right hand side
any doubt that it true?

- xapproachesinfinity

same as*

- xapproachesinfinity

well?

- anonymous

wat?

- xapproachesinfinity

i said do you agree that a(b+c)=ab+ac
or against this arithmetic law? the problem here is we need to establish some sense
first before we tackle that problem of your that deals with trig

- anonymous

yes

- xapproachesinfinity

so you have no problem to tell what this is gonna be bd+be=? using the same law?

- xapproachesinfinity

oh well!
so it is gonna be bd+be=b(d+e) yes?

- anonymous

yes

- xapproachesinfinity

now tell me what did i just do?

- xapproachesinfinity

describe me what i did?

- anonymous

u factored y^2 and y

- xapproachesinfinity

no just stay on what i did
that would come later! what i'm trying to do here to show you how we can accomplish the factorization for y^2+y

- anonymous

oh ok got it

- xapproachesinfinity

i want you to fully understand this! so you will have further problem with such exercice!

- xapproachesinfinity

so here really what i did is using the that very distributive law of arithmetic
to get from bd+be to b(d+e)

- anonymous

alright got it

- xapproachesinfinity

ok let me test one more time
xy+2x=?

- xapproachesinfinity

again distributive law!

- anonymous

nvm

- xapproachesinfinity

this is all for the sake of you being better at this, if that's the case then
it is really fine with me
we can gave you the answer, but what is the point of doing it any way

- xapproachesinfinity

give*

- Nnesha

one more try
y^2 + y
let y = chocolates
exponent represents number of chocolates |dw:1433891939844:dw|
how many chocolates they both people have n common ?

- anonymous

i just don't get it and it makes me feel really dumb :/

- xapproachesinfinity

i can tell oh this and that an such then this is the answer
next time you have test you stuck! who is there to give you the answer no one
no you are not dumb. you are resisting this is that is all

- anonymous

ok explain to me step by step n slo like nnesha and i'll try my best to understand

- xapproachesinfinity

ok i guess nnesha might have a better approach than me hehe

- anonymous

- Nnesha

nah you explained MUCH MUCH better than me

- Nnesha

read my 2nd last comment
y^2 + y what is common in these both terms ?

- xapproachesinfinity

well the outcome is that she didn't understand me
so perhaps some fancy art gets the idea across

- xapproachesinfinity

you never know! people learn differently haha

- xapproachesinfinity

for me i'm very systematic!

- Nnesha

that's great!!!!

- xapproachesinfinity

nah artistic is also needed for much better result in maths!
math is more fun if those are combined

- Nnesha

alright barbiegirl so http://prntscr.com/7f5mgb?

- Nnesha

that's right but *practice* is MORE important
-taking notes
-solve one question more than 3 times
it will help to memorize stuffff

- xapproachesinfinity

yeah! practice is about everything! whether it be math or anything

- xapproachesinfinity

well have to leave now sorry iambarbie :)

- Nnesha

i'm still waiting for ur reply
i have 10 mints

- anonymous

wat do u want me to do? u just drew a pic explaining it to me..

- Nnesha

i asked a question
how many chocolates they both people have n common ?

- anonymous

both have 3

- Nnesha

how ??
remember exponent represent number of chocolates |dw:1433893136376:dw|

- anonymous

once has 2 and the other has 1

- Nnesha

so common number of chocolate would be one right
or you can apply exponent rule \[\huge\rm x^m \times x^n = x^{m +n}\]
so that's how y times y = y^2\[\huge\rm (y \times y \color{red}{+} y)\]
so what's common in thes both terms ?

- anonymous

will u be on an hour later or something like that?

- Nnesha

alright

- anonymous

I know the answer!!

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