anonymous
  • anonymous
Find all solutions to the equation. sin2x + sin x = 0 @johnweldon1993
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Nnesha
  • Nnesha
take out common factor let sin x=y so y^2 +y what's the common factor ?
johnweldon1993
  • johnweldon1993
This is \(\large sin^2(x) + sin(x) = 0\) right? or \(\large sin(2x) + sin(x) = 0\) ?
anonymous
  • anonymous
no first one lol

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johnweldon1993
  • johnweldon1993
Then perfect go ahead with the process @Nnesha was showing :) Look at it as sin(x) = y so sin^2(x) = y^2 \[\large y^2 + y = 0\] What can you factor out?
xapproachesinfinity
  • xapproachesinfinity
still troubled by this or solved it
anonymous
  • anonymous
troubled @xapproachesinfinity
xapproachesinfinity
  • xapproachesinfinity
so you have no idea how to factor y^2+y=0? what is common btw y^2 and y?
xapproachesinfinity
  • xapproachesinfinity
let's us go to the basics how can you do this a(b+c)=? using distributive law?
xapproachesinfinity
  • xapproachesinfinity
i want you to interact with me otherwise i will just take my leave haha
anonymous
  • anonymous
sorry i was doing somethin away from the laptop.. but i have NO IDEA how to do this ABSOLUTELY NONE!
anonymous
  • anonymous
@Nnesha
Nnesha
  • Nnesha
yes?
xapproachesinfinity
  • xapproachesinfinity
ok back let's pick it up where i left it know of distributive law?
anonymous
  • anonymous
nope :( im so sorry im making this hell for u wish i did :/
xapproachesinfinity
  • xapproachesinfinity
realize that is the basic math? from lower grades
xapproachesinfinity
  • xapproachesinfinity
so distributive law tells us that a(b+c)=ab+ac the left hand side is the same are the right hand side any doubt that it true?
xapproachesinfinity
  • xapproachesinfinity
same as*
xapproachesinfinity
  • xapproachesinfinity
well?
anonymous
  • anonymous
wat?
xapproachesinfinity
  • xapproachesinfinity
i said do you agree that a(b+c)=ab+ac or against this arithmetic law? the problem here is we need to establish some sense first before we tackle that problem of your that deals with trig
anonymous
  • anonymous
yes
xapproachesinfinity
  • xapproachesinfinity
so you have no problem to tell what this is gonna be bd+be=? using the same law?
xapproachesinfinity
  • xapproachesinfinity
oh well! so it is gonna be bd+be=b(d+e) yes?
anonymous
  • anonymous
yes
xapproachesinfinity
  • xapproachesinfinity
now tell me what did i just do?
xapproachesinfinity
  • xapproachesinfinity
describe me what i did?
anonymous
  • anonymous
u factored y^2 and y
xapproachesinfinity
  • xapproachesinfinity
no just stay on what i did that would come later! what i'm trying to do here to show you how we can accomplish the factorization for y^2+y
anonymous
  • anonymous
oh ok got it
xapproachesinfinity
  • xapproachesinfinity
i want you to fully understand this! so you will have further problem with such exercice!
xapproachesinfinity
  • xapproachesinfinity
so here really what i did is using the that very distributive law of arithmetic to get from bd+be to b(d+e)
anonymous
  • anonymous
alright got it
xapproachesinfinity
  • xapproachesinfinity
ok let me test one more time xy+2x=?
xapproachesinfinity
  • xapproachesinfinity
again distributive law!
anonymous
  • anonymous
nvm
xapproachesinfinity
  • xapproachesinfinity
this is all for the sake of you being better at this, if that's the case then it is really fine with me we can gave you the answer, but what is the point of doing it any way
xapproachesinfinity
  • xapproachesinfinity
give*
Nnesha
  • Nnesha
one more try y^2 + y let y = chocolates exponent represents number of chocolates |dw:1433891939844:dw| how many chocolates they both people have n common ?
anonymous
  • anonymous
i just don't get it and it makes me feel really dumb :/
xapproachesinfinity
  • xapproachesinfinity
i can tell oh this and that an such then this is the answer next time you have test you stuck! who is there to give you the answer no one no you are not dumb. you are resisting this is that is all
anonymous
  • anonymous
ok explain to me step by step n slo like nnesha and i'll try my best to understand
xapproachesinfinity
  • xapproachesinfinity
ok i guess nnesha might have a better approach than me hehe
anonymous
  • anonymous
@Nnesha
Nnesha
  • Nnesha
nah you explained MUCH MUCH better than me
Nnesha
  • Nnesha
read my 2nd last comment y^2 + y what is common in these both terms ?
xapproachesinfinity
  • xapproachesinfinity
well the outcome is that she didn't understand me so perhaps some fancy art gets the idea across
xapproachesinfinity
  • xapproachesinfinity
you never know! people learn differently haha
xapproachesinfinity
  • xapproachesinfinity
for me i'm very systematic!
Nnesha
  • Nnesha
that's great!!!!
xapproachesinfinity
  • xapproachesinfinity
nah artistic is also needed for much better result in maths! math is more fun if those are combined
Nnesha
  • Nnesha
alright barbiegirl so http://prntscr.com/7f5mgb?
Nnesha
  • Nnesha
that's right but *practice* is MORE important -taking notes -solve one question more than 3 times it will help to memorize stuffff
xapproachesinfinity
  • xapproachesinfinity
yeah! practice is about everything! whether it be math or anything
xapproachesinfinity
  • xapproachesinfinity
well have to leave now sorry iambarbie :)
Nnesha
  • Nnesha
i'm still waiting for ur reply i have 10 mints
anonymous
  • anonymous
wat do u want me to do? u just drew a pic explaining it to me..
Nnesha
  • Nnesha
i asked a question how many chocolates they both people have n common ?
anonymous
  • anonymous
both have 3
Nnesha
  • Nnesha
how ?? remember exponent represent number of chocolates |dw:1433893136376:dw|
anonymous
  • anonymous
once has 2 and the other has 1
Nnesha
  • Nnesha
so common number of chocolate would be one right or you can apply exponent rule \[\huge\rm x^m \times x^n = x^{m +n}\] so that's how y times y = y^2\[\huge\rm (y \times y \color{red}{+} y)\] so what's common in thes both terms ?
anonymous
  • anonymous
will u be on an hour later or something like that?
Nnesha
  • Nnesha
alright
anonymous
  • anonymous
I know the answer!!

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