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anonymous

  • one year ago

Find all solutions to the equation. sin2x + sin x = 0 @johnweldon1993

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  1. Nnesha
    • one year ago
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    take out common factor let sin x=y so y^2 +y what's the common factor ?

  2. johnweldon1993
    • one year ago
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    This is \(\large sin^2(x) + sin(x) = 0\) right? or \(\large sin(2x) + sin(x) = 0\) ?

  3. anonymous
    • one year ago
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    no first one lol

  4. johnweldon1993
    • one year ago
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    Then perfect go ahead with the process @Nnesha was showing :) Look at it as sin(x) = y so sin^2(x) = y^2 \[\large y^2 + y = 0\] What can you factor out?

  5. xapproachesinfinity
    • one year ago
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    still troubled by this or solved it

  6. anonymous
    • one year ago
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    troubled @xapproachesinfinity

  7. xapproachesinfinity
    • one year ago
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    so you have no idea how to factor y^2+y=0? what is common btw y^2 and y?

  8. xapproachesinfinity
    • one year ago
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    let's us go to the basics how can you do this a(b+c)=? using distributive law?

  9. xapproachesinfinity
    • one year ago
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    i want you to interact with me otherwise i will just take my leave haha

  10. anonymous
    • one year ago
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    sorry i was doing somethin away from the laptop.. but i have NO IDEA how to do this ABSOLUTELY NONE!

  11. anonymous
    • one year ago
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    @Nnesha

  12. Nnesha
    • one year ago
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    yes?

  13. xapproachesinfinity
    • one year ago
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    ok back let's pick it up where i left it know of distributive law?

  14. anonymous
    • one year ago
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    nope :( im so sorry im making this hell for u wish i did :/

  15. xapproachesinfinity
    • one year ago
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    realize that is the basic math? from lower grades

  16. xapproachesinfinity
    • one year ago
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    so distributive law tells us that a(b+c)=ab+ac the left hand side is the same are the right hand side any doubt that it true?

  17. xapproachesinfinity
    • one year ago
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    same as*

  18. xapproachesinfinity
    • one year ago
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    well?

  19. anonymous
    • one year ago
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    wat?

  20. xapproachesinfinity
    • one year ago
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    i said do you agree that a(b+c)=ab+ac or against this arithmetic law? the problem here is we need to establish some sense first before we tackle that problem of your that deals with trig

  21. anonymous
    • one year ago
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    yes

  22. xapproachesinfinity
    • one year ago
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    so you have no problem to tell what this is gonna be bd+be=? using the same law?

  23. xapproachesinfinity
    • one year ago
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    oh well! so it is gonna be bd+be=b(d+e) yes?

  24. anonymous
    • one year ago
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    yes

  25. xapproachesinfinity
    • one year ago
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    now tell me what did i just do?

  26. xapproachesinfinity
    • one year ago
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    describe me what i did?

  27. anonymous
    • one year ago
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    u factored y^2 and y

  28. xapproachesinfinity
    • one year ago
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    no just stay on what i did that would come later! what i'm trying to do here to show you how we can accomplish the factorization for y^2+y

  29. anonymous
    • one year ago
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    oh ok got it

  30. xapproachesinfinity
    • one year ago
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    i want you to fully understand this! so you will have further problem with such exercice!

  31. xapproachesinfinity
    • one year ago
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    so here really what i did is using the that very distributive law of arithmetic to get from bd+be to b(d+e)

  32. anonymous
    • one year ago
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    alright got it

  33. xapproachesinfinity
    • one year ago
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    ok let me test one more time xy+2x=?

  34. xapproachesinfinity
    • one year ago
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    again distributive law!

  35. anonymous
    • one year ago
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    nvm

  36. xapproachesinfinity
    • one year ago
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    this is all for the sake of you being better at this, if that's the case then it is really fine with me we can gave you the answer, but what is the point of doing it any way

  37. xapproachesinfinity
    • one year ago
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    give*

  38. Nnesha
    • one year ago
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    one more try y^2 + y let y = chocolates exponent represents number of chocolates |dw:1433891939844:dw| how many chocolates they both people have n common ?

  39. anonymous
    • one year ago
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    i just don't get it and it makes me feel really dumb :/

  40. xapproachesinfinity
    • one year ago
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    i can tell oh this and that an such then this is the answer next time you have test you stuck! who is there to give you the answer no one no you are not dumb. you are resisting this is that is all

  41. anonymous
    • one year ago
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    ok explain to me step by step n slo like nnesha and i'll try my best to understand

  42. xapproachesinfinity
    • one year ago
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    ok i guess nnesha might have a better approach than me hehe

  43. anonymous
    • one year ago
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    @Nnesha

  44. Nnesha
    • one year ago
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    nah you explained MUCH MUCH better than me

  45. Nnesha
    • one year ago
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    read my 2nd last comment y^2 + y what is common in these both terms ?

  46. xapproachesinfinity
    • one year ago
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    well the outcome is that she didn't understand me so perhaps some fancy art gets the idea across

  47. xapproachesinfinity
    • one year ago
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    you never know! people learn differently haha

  48. xapproachesinfinity
    • one year ago
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    for me i'm very systematic!

  49. Nnesha
    • one year ago
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    that's great!!!!

  50. xapproachesinfinity
    • one year ago
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    nah artistic is also needed for much better result in maths! math is more fun if those are combined

  51. Nnesha
    • one year ago
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    alright barbiegirl so http://prntscr.com/7f5mgb?

  52. Nnesha
    • one year ago
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    that's right but *practice* is MORE important -taking notes -solve one question more than 3 times it will help to memorize stuffff

  53. xapproachesinfinity
    • one year ago
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    yeah! practice is about everything! whether it be math or anything

  54. xapproachesinfinity
    • one year ago
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    well have to leave now sorry iambarbie :)

  55. Nnesha
    • one year ago
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    i'm still waiting for ur reply i have 10 mints

  56. anonymous
    • one year ago
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    wat do u want me to do? u just drew a pic explaining it to me..

  57. Nnesha
    • one year ago
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    i asked a question how many chocolates they both people have n common ?

  58. anonymous
    • one year ago
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    both have 3

  59. Nnesha
    • one year ago
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    how ?? remember exponent represent number of chocolates |dw:1433893136376:dw|

  60. anonymous
    • one year ago
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    once has 2 and the other has 1

  61. Nnesha
    • one year ago
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    so common number of chocolate would be one right or you can apply exponent rule \[\huge\rm x^m \times x^n = x^{m +n}\] so that's how y times y = y^2\[\huge\rm (y \times y \color{red}{+} y)\] so what's common in thes both terms ?

  62. anonymous
    • one year ago
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    will u be on an hour later or something like that?

  63. Nnesha
    • one year ago
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    alright

  64. anonymous
    • one year ago
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    I know the answer!!

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