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anonymous

  • one year ago

Pleaseeeeeeee help i'm drowning in confusionnnnnnn

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  1. Bella2112
    • one year ago
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    whats your question?

  2. anonymous
    • one year ago
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    \[(\frac{ 2 }{ 3 }^{-n}) (\frac{ 3 }{ 2 }^{-n}) = \frac{ 1 }{ 36 }\]

  3. Nnesha
    • one year ago
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    2^-n or (2/3)^-n ?

  4. Nnesha
    • one year ago
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    2 to the -n power or 2/3 to the -n which one is it ?

  5. anonymous
    • one year ago
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    it's inside the parantheses

  6. anonymous
    • one year ago
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    2 to the -n

  7. Nnesha
    • one year ago
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    oh alright so \[\huge\rm (\frac{ 2 }{ 3 }^{-n}) (\frac{ 3 }{ 2 }^{-n}) = \frac{ 1 }{ 36 }\] there are negative exponent so apply exponent rule \[\huge\rm x^{-m} = \frac{ 1 }{ x^m }\] flip the fraction

  8. anonymous
    • one year ago
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    i cant do |dw:1433890169161:dw|

  9. Nnesha
    • one year ago
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    how did you get 6?

  10. anonymous
    • one year ago
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    |dw:1433890211719:dw|

  11. Nnesha
    • one year ago
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    yep right

  12. anonymous
    • one year ago
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    because|dw:1433890257414:dw|

  13. anonymous
    • one year ago
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    so i did it right?

  14. Nnesha
    • one year ago
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    mh mwait a sec

  15. Nnesha
    • one year ago
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    yep that's right 6^-2 = 1/36 how did you get 6 from this equation \[\huge\rm (\frac{ 2 }{ 3 }^{-n}) (\frac{ 3 }{ 2 }^{-n}) = \frac{ 1 }{ 36 }\]

  16. anonymous
    • one year ago
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    because |dw:1433890791264:dw|

  17. anonymous
    • one year ago
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    is this right? |dw:1433890889470:dw|

  18. Nnesha
    • one year ago
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    yes right

  19. anonymous
    • one year ago
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    okay got it thanks <333

  20. Nnesha
    • one year ago
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    okay i assume just 2 to the -n power and 3 to the -n power

  21. anonymous
    • one year ago
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    yes

  22. Nnesha
    • one year ago
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    yep multiply denominator by den and numerator by numerator and u used that exponent rule (ab)^n \[\frac{ (2 \times 3)^{-n} }{ 6 } = \frac{ 6^{-n} }{6 }\] let n = 1 \[ \huge\rm \frac{ 6^{-1} }{6 }\] \[\large 6^{-1-1} \] add flip the fraction you got it right!

  23. Nnesha
    • one year ago
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    GREAT JOB!!!!\(\Huge \color{gold}{\star^{ \star^{\star:)}}}\Huge \color{green}{\star^{ \star^{\star:)}}}\)

  24. anonymous
    • one year ago
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    awesome thanks!!!

  25. Nnesha
    • one year ago
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    :-)

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