anonymous
  • anonymous
Pleaseeeeeeee help i'm drowning in confusionnnnnnn
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Bella2112
  • Bella2112
whats your question?
anonymous
  • anonymous
\[(\frac{ 2 }{ 3 }^{-n}) (\frac{ 3 }{ 2 }^{-n}) = \frac{ 1 }{ 36 }\]
Nnesha
  • Nnesha
2^-n or (2/3)^-n ?

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Nnesha
  • Nnesha
2 to the -n power or 2/3 to the -n which one is it ?
anonymous
  • anonymous
it's inside the parantheses
anonymous
  • anonymous
2 to the -n
Nnesha
  • Nnesha
oh alright so \[\huge\rm (\frac{ 2 }{ 3 }^{-n}) (\frac{ 3 }{ 2 }^{-n}) = \frac{ 1 }{ 36 }\] there are negative exponent so apply exponent rule \[\huge\rm x^{-m} = \frac{ 1 }{ x^m }\] flip the fraction
anonymous
  • anonymous
i cant do |dw:1433890169161:dw|
Nnesha
  • Nnesha
how did you get 6?
anonymous
  • anonymous
|dw:1433890211719:dw|
Nnesha
  • Nnesha
yep right
anonymous
  • anonymous
because|dw:1433890257414:dw|
anonymous
  • anonymous
so i did it right?
Nnesha
  • Nnesha
mh mwait a sec
Nnesha
  • Nnesha
yep that's right 6^-2 = 1/36 how did you get 6 from this equation \[\huge\rm (\frac{ 2 }{ 3 }^{-n}) (\frac{ 3 }{ 2 }^{-n}) = \frac{ 1 }{ 36 }\]
anonymous
  • anonymous
because |dw:1433890791264:dw|
anonymous
  • anonymous
is this right? |dw:1433890889470:dw|
Nnesha
  • Nnesha
yes right
anonymous
  • anonymous
okay got it thanks <333
Nnesha
  • Nnesha
okay i assume just 2 to the -n power and 3 to the -n power
anonymous
  • anonymous
yes
Nnesha
  • Nnesha
yep multiply denominator by den and numerator by numerator and u used that exponent rule (ab)^n \[\frac{ (2 \times 3)^{-n} }{ 6 } = \frac{ 6^{-n} }{6 }\] let n = 1 \[ \huge\rm \frac{ 6^{-1} }{6 }\] \[\large 6^{-1-1} \] add flip the fraction you got it right!
Nnesha
  • Nnesha
GREAT JOB!!!!\(\Huge \color{gold}{\star^{ \star^{\star:)}}}\Huge \color{green}{\star^{ \star^{\star:)}}}\)
anonymous
  • anonymous
awesome thanks!!!
Nnesha
  • Nnesha
:-)

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