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anonymous
 one year ago
Let f(x,y) = 6(1y) where 0 < x < y < 1 be a possible joint distribution.
Demonstrate that this is a viable distribution (show your work)
The 0 < x < y < 1 is throwing me off. What domains should I be using when integrating with respect to x and with respect to y?
anonymous
 one year ago
Let f(x,y) = 6(1y) where 0 < x < y < 1 be a possible joint distribution. Demonstrate that this is a viable distribution (show your work) The 0 < x < y < 1 is throwing me off. What domains should I be using when integrating with respect to x and with respect to y?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I've tried 0 to y for x and x to 1 for y, but I am unsure of this answer. To prove a viable distribution, I need to show that the volume of f(x,y) with respect to x and y is equal to one. I need a definite integral to equal 1.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2the volume of f(x,y) with respect to x and y is the double integral of f(x,y). and your f(x,y) is the plane \(0x + 6y +z = 6\) your limit \(0<x<y<1\) seems to be looking at the \(x = 1, \ y= 1\) square but above the y = x line itself. so you could try \(\int_{y=0}^{1} \ \int_{x=0}^{y} (6  6y) \ dx \ dy\)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2notice the order of integration.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wow. You are the best. I've integrated and received the correct answer of 1. I'm ecstatic. Thanks!
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