anonymous
  • anonymous
The area of a rectangle is 120 cm2. The length of the rectangle is eight less than the twice of the width. Find the dimensions of the rectangle.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
so far i got....\[(2x - 8) *w=120 \right?\]
anonymous
  • anonymous
x=w
anonymous
  • anonymous
let width=x length=2x-8 x(2x-8)=120

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More answers

anonymous
  • anonymous
ok so i was right
anonymous
  • anonymous
yes
anonymous
  • anonymous
so... \[2x ^{2} - 8x -120=0\]
anonymous
  • anonymous
carry on
anonymous
  • anonymous
hmnmmmm
anonymous
  • anonymous
divide by 2
anonymous
  • anonymous
solve further
anonymous
  • anonymous
ok
anonymous
  • anonymous
what can i add to get 4 that i can multiply to get 60? hmm
anonymous
  • anonymous
10 and 6
anonymous
  • anonymous
x-6, and x-10?
anonymous
  • anonymous
1*- 60=-60 10-6=4 10*-6=-60
anonymous
  • anonymous
x-6, and x-10? ?
anonymous
  • anonymous
\[x^2-\left( 10-6 \right)x-60=0\] \[x^2-10x+6x-60=0\]
anonymous
  • anonymous
thats what i got
anonymous
  • anonymous
\[x(x-10) 6(x-10)\]
anonymous
  • anonymous
good
anonymous
  • anonymous
6 cm and 20 cm 10 cm and 12 cm 40 cm and 30 cm 5 cm and 24 cm
anonymous
  • anonymous
oh multiply by 2
anonymous
  • anonymous
right?
anonymous
  • anonymous
12 and 20?
anonymous
  • anonymous
x(x-10)+6(x-10)=0 (x-10)(x+6)=0 x+6=0,x=-6 rejected x-10=0,x=10 width=10 length=2*10-8=20-8=12
anonymous
  • anonymous
where does 8 come from?
anonymous
  • anonymous
oh i see
anonymous
  • anonymous
kinda?
anonymous
  • anonymous
in the statement length is 8 less than twice width

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