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anonymous
 one year ago
Sand is falling on a pile , having shape pf a cone, at the rate 1.5 m3/min. assime diameter of base is 3 times the altitiude, at what rate is the altitude increasing when the altitude is 2m?
anonymous
 one year ago
Sand is falling on a pile , having shape pf a cone, at the rate 1.5 m3/min. assime diameter of base is 3 times the altitiude, at what rate is the altitude increasing when the altitude is 2m?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 @ParthKohli @Loser66

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whats is "r" equal too ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the question says 3d=h

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0radius is half so 2/3r=h?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0other way around. d = 3h

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and V = πr²h/3, so make the substitution for r then take the derivative

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okey i did eberyhing i am getting 1/9pi and u ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i did somthing wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah I got something different? What was your derivative?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0If you mean \[\Large \frac{1}{6\pi}\] then you are correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh, that's what I thought you meant

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0what did you get for dV/dt ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my der was 9/12pih3 dh/dt?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0after putiing in 3/2h

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0the h^3 part is incorrect

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0you will have h^3 in the V volume formula but after you derive, it turns into 3h^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the formula for cone is x=1/3r2h

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0when 3/2h goes in it become h2 then h3 by timising the outside h

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433903048615:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433903137752:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok what are the steps take the derv fist then sub?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sub for r first because we don't have a value for dr/dt, then take the derivative

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait so (3h/2) doesnt equal 9h2/4? it eiqls 9h/4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh wait i think i get it now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hold on the 1/3 is gone beacuse of derv right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well the 1/3 was gone before the derivative. It was 3/4 after the substitution, and 9/4 after the derivative

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0damn i am going to take 5 min brake

dumbcow
 one year ago
Best ResponseYou've already chosen the best response.0\[V = \frac{1}{3} \pi r^2 h\] \[r = \frac{3}{2} h\] \[\rightarrow V = \frac{1}{3} \pi (\frac{3}{2}h)^2 h = \frac{3}{4} \pi h^3\] Take derivative with respect to time \[\frac{dV}{dt}= \frac{9}{4} \pi h^2 \frac{dh}{dt}\] plug in dV = 1.5, h =2 , then solve for dh/dt \[\frac{dh}{dt} = \frac{1.5}{9 \pi}\]
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