anonymous
  • anonymous
The length of a rectangle is 3 feet more than twice its width. The area is 65 square feet. Find the dimensions of the rectangle using the quadratic formula.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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amilapsn
  • amilapsn
can you put what is said in the question into equations?
anonymous
  • anonymous
|dw:1433905214940:dw| right?
amilapsn
  • amilapsn
yep

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More answers

anonymous
  • anonymous
ok
anonymous
  • anonymous
\[2x ^{2} + 3w - 65 =0?\]
amilapsn
  • amilapsn
\(*2w^2\) ok?
anonymous
  • anonymous
thats what i meant
amilapsn
  • amilapsn
not \(2x^2\)
amilapsn
  • amilapsn
Now you've to solve \(2w^2+3w-65=0\)
anonymous
  • anonymous
\[-3\pm \sqrt{511} > divided by 4 ...\right?\]
anonymous
  • anonymous
\[-3\pm \sqrt{511} divided by 4\]
anonymous
  • anonymous
righ?
amilapsn
  • amilapsn
check b^2-4ac
anonymous
  • anonymous
-511?
amilapsn
  • amilapsn
what's b?
anonymous
  • anonymous
3
anonymous
  • anonymous
ohh
anonymous
  • anonymous
711?
amilapsn
  • amilapsn
b=3,a=2 and c= (-65), right?
anonymous
  • anonymous
hm oh
anonymous
  • anonymous
i got -511
amilapsn
  • amilapsn
plus or minus?
anonymous
  • anonymous
minus
anonymous
  • anonymous
waot
amilapsn
  • amilapsn
b^2-4ac=3^2-4x2x(-65),ok?
anonymous
  • anonymous
789?
anonymous
  • anonymous
ok?
amilapsn
  • amilapsn
then what would be the value?
anonymous
  • anonymous
hmmm
anonymous
  • anonymous
sstill gpt -511
anonymous
  • anonymous
got
amilapsn
  • amilapsn
have you got a cal?
anonymous
  • anonymous
yes
anonymous
  • anonymous
i did 9 - (4)(2)(-65)
amilapsn
  • amilapsn
you did right then... https://www.google.com/search?q=3^2-4*2*%28-65%29&ie=utf-8&oe=utf-8
anonymous
  • anonymous
oh
anonymous
  • anonymous
ok ill go with 529 then, dont no what went wrong
amilapsn
  • amilapsn
I think you've forgotten to put minus sign to 65.... Am I right?
anonymous
  • anonymous
added nine instead of subtracted 9 or something
anonymous
  • anonymous
no
anonymous
  • anonymous
anyway thx

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