korosh23
  • korosh23
Physics questions!
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
korosh23
  • korosh23
korosh23
  • korosh23
Please answer the orange questions which there is a question mark. Each question in a different page. So three medals.
korosh23
  • korosh23
Ok #36 please! I have my answer. I will send it in a sec!

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korosh23
  • korosh23
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Michele_Laino
  • Michele_Laino
I got this: |dw:1433908300305:dw| so I can write this: \[\Large {m_1}{v_1} - {m_2}{v_2} = \left( {{m_1} + {m_2}} \right)v\] from which I got: v= +4 m/sec
korosh23
  • korosh23
How !?
Michele_Laino
  • Michele_Laino
using my reference system, we can write: \[\Large \begin{gathered} {{\mathbf{v}}_{\mathbf{1}}} = \left( {{v_1},0} \right) \hfill \\ {{\mathbf{v}}_{\mathbf{2}}} = \left( { - {v_2},0} \right) \hfill \\ \end{gathered} \]
korosh23
  • korosh23
Are you sure that is m1v1 - m2v2 or m1v1 + m2v2?
Michele_Laino
  • Michele_Laino
no, since what is conserved is the vector which represents the total momentum, actually our equation is: \[\Large {m_1}{{\mathbf{v}}_{\mathbf{1}}} + {m_2}{{\mathbf{v}}_{\mathbf{2}}} = \left( {{m_1} + {m_2}} \right){\mathbf{v}}\]
korosh23
  • korosh23
Exactly, it is a closed system. Energy is conserved. Now lets plug in the numbers.
Michele_Laino
  • Michele_Laino
now we have to go from vectors to components, and as I wrote before, we can write: \[\begin{gathered} {{\mathbf{v}}_{\mathbf{1}}} = \left( {{v_1},0} \right) \hfill \\ {{\mathbf{v}}_{\mathbf{2}}} = \left( { - {v_2},0} \right) \hfill \\ \end{gathered} \]
korosh23
  • korosh23
what is v2? Motor or truck?
Michele_Laino
  • Michele_Laino
v_2 is the motor
Michele_Laino
  • Michele_Laino
furthermore: \[\Large {v_1} = \left| {{{\mathbf{v}}_{\mathbf{1}}}} \right|,\quad {v_2} = \left| {{{\mathbf{v}}_{\mathbf{2}}}} \right|\]
korosh23
  • korosh23
Wait a moment.
korosh23
  • korosh23
In the question it says the truck is going west. West is the negative direction. Motorist is going opposite of west which is east! It is postive velocity. Truck should have -ve velocity.
Michele_Laino
  • Michele_Laino
ok! Then our correct drawing is: |dw:1433908946956:dw| and the previous equation will become: \[\Large \begin{gathered} - {m_1}{v_1} + {m_2}{v_2} = \left( {{m_1} + {m_2}} \right)v \hfill \\ {{\mathbf{v}}_{\mathbf{1}}} = \left( { - {v_1},0} \right) \hfill \\ {{\mathbf{v}}_{\mathbf{2}}} = \left( { + {v_2},0} \right) \hfill \\ \end{gathered} \]
Michele_Laino
  • Michele_Laino
and the answer is: v= -4 m/sec
korosh23
  • korosh23
That means I was right? I got -4 m/s
Michele_Laino
  • Michele_Laino
yes!
korosh23
  • korosh23
Ok great, thank you! I have to go, I will ask my other questions later.
Michele_Laino
  • Michele_Laino
ok!
korosh23
  • korosh23
Just wondering are you here in openstudy tomorrow. On Thursday I have a physics exam. I was wondering if I have few quick question, Is it ok I ask you?
Michele_Laino
  • Michele_Laino
yes! I will stay in OpenStudy tomorrow, and I can help you
korosh23
  • korosh23
At what time are you in openstudy, and when you leave?
Michele_Laino
  • Michele_Laino
I will be here in OpenStudy at 6:00 am (Italy Time zone)
korosh23
  • korosh23
Ok I will manage mt time. Thank you, you are a very supportive tutor.
Michele_Laino
  • Michele_Laino
:)

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