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korosh23
 one year ago
Physics questions!
korosh23
 one year ago
Physics questions!

This Question is Closed

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0Please answer the orange questions which there is a question mark. Each question in a different page. So three medals.

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0Ok #36 please! I have my answer. I will send it in a sec!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I got this: dw:1433908300305:dw so I can write this: \[\Large {m_1}{v_1}  {m_2}{v_2} = \left( {{m_1} + {m_2}} \right)v\] from which I got: v= +4 m/sec

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2using my reference system, we can write: \[\Large \begin{gathered} {{\mathbf{v}}_{\mathbf{1}}} = \left( {{v_1},0} \right) \hfill \\ {{\mathbf{v}}_{\mathbf{2}}} = \left( {  {v_2},0} \right) \hfill \\ \end{gathered} \]

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0Are you sure that is m1v1  m2v2 or m1v1 + m2v2?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2no, since what is conserved is the vector which represents the total momentum, actually our equation is: \[\Large {m_1}{{\mathbf{v}}_{\mathbf{1}}} + {m_2}{{\mathbf{v}}_{\mathbf{2}}} = \left( {{m_1} + {m_2}} \right){\mathbf{v}}\]

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0Exactly, it is a closed system. Energy is conserved. Now lets plug in the numbers.

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2now we have to go from vectors to components, and as I wrote before, we can write: \[\begin{gathered} {{\mathbf{v}}_{\mathbf{1}}} = \left( {{v_1},0} \right) \hfill \\ {{\mathbf{v}}_{\mathbf{2}}} = \left( {  {v_2},0} \right) \hfill \\ \end{gathered} \]

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0what is v2? Motor or truck?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2v_2 is the motor

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2furthermore: \[\Large {v_1} = \left {{{\mathbf{v}}_{\mathbf{1}}}} \right,\quad {v_2} = \left {{{\mathbf{v}}_{\mathbf{2}}}} \right\]

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0In the question it says the truck is going west. West is the negative direction. Motorist is going opposite of west which is east! It is postive velocity. Truck should have ve velocity.

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2ok! Then our correct drawing is: dw:1433908946956:dw and the previous equation will become: \[\Large \begin{gathered}  {m_1}{v_1} + {m_2}{v_2} = \left( {{m_1} + {m_2}} \right)v \hfill \\ {{\mathbf{v}}_{\mathbf{1}}} = \left( {  {v_1},0} \right) \hfill \\ {{\mathbf{v}}_{\mathbf{2}}} = \left( { + {v_2},0} \right) \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2and the answer is: v= 4 m/sec

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0That means I was right? I got 4 m/s

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0Ok great, thank you! I have to go, I will ask my other questions later.

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0Just wondering are you here in openstudy tomorrow. On Thursday I have a physics exam. I was wondering if I have few quick question, Is it ok I ask you?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2yes! I will stay in OpenStudy tomorrow, and I can help you

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0At what time are you in openstudy, and when you leave?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I will be here in OpenStudy at 6:00 am (Italy Time zone)

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0Ok I will manage mt time. Thank you, you are a very supportive tutor.
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