anonymous
  • anonymous
the equatioj of the tangent to tje vurve y2/10 - x2/4 at the point 6,-10
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@dumbcow okey so i totualy forgot how to do these
dumbcow
  • dumbcow
ok equation for tangent line is: \[y = \frac{dy}{dx}(x - x_1) + y_1\] (x1,y1) is given point
dumbcow
  • dumbcow
does the equation = 1 by chance ? y^2/10 - x^2/4 = 1

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anonymous
  • anonymous
ohh sorry yea =1
dumbcow
  • dumbcow
to get dy/dx you need to take implicit derivative \[\rightarrow \frac{2y}{10} \frac{dy}{dx} - \frac{2x}{4} = 0\] solve for dy/dx \[\frac{dy}{dx} = \frac{(2x/4)}{(2y/10)} = \frac{x}{2}*\frac{5}{y} = \frac{5x}{2y}\]
anonymous
  • anonymous
but doesnt make any difference right
dumbcow
  • dumbcow
final answer \[y = (\frac{5x_1}{2y_1})(x - x_1) + y_1\] plug in given point
dumbcow
  • dumbcow
what do you mean?
anonymous
  • anonymous
hold on after getting dy/dx what did u do ?
dumbcow
  • dumbcow
substitute it into equation for tangent line

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