## anonymous one year ago the equatioj of the tangent to tje vurve y2/10 - x2/4 at the point 6,-10

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1. anonymous

@dumbcow okey so i totualy forgot how to do these

2. anonymous

ok equation for tangent line is: $y = \frac{dy}{dx}(x - x_1) + y_1$ (x1,y1) is given point

3. anonymous

does the equation = 1 by chance ? y^2/10 - x^2/4 = 1

4. anonymous

ohh sorry yea =1

5. anonymous

to get dy/dx you need to take implicit derivative $\rightarrow \frac{2y}{10} \frac{dy}{dx} - \frac{2x}{4} = 0$ solve for dy/dx $\frac{dy}{dx} = \frac{(2x/4)}{(2y/10)} = \frac{x}{2}*\frac{5}{y} = \frac{5x}{2y}$

6. anonymous

but doesnt make any difference right

7. anonymous

final answer $y = (\frac{5x_1}{2y_1})(x - x_1) + y_1$ plug in given point

8. anonymous

what do you mean?

9. anonymous

hold on after getting dy/dx what did u do ?

10. anonymous

substitute it into equation for tangent line