anonymous
  • anonymous
The Jones family attends a movie for $47.00 with two adults and three kids. The Smith family attends when some friends are in town for $74.75 with three adults and five kids. How much does the Ramirez family have to pay with adults and four kids
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
set up some equations
anonymous
  • anonymous
what kind??
anonymous
  • anonymous
Jones family: 2*adults + 3*kids = $47 total 2*a + 3*k = 47 2a + 3k = 47

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More answers

anonymous
  • anonymous
all three of those equations represent the same thing
anonymous
  • anonymous
can you set up an equation for the Smith family now?
anonymous
  • anonymous
3a+5k=74.75 whats next?? @bi
anonymous
  • anonymous
perfect now you have two equations and two unknowns, can you solve this system for a and k? 2a + 3k = 47 3a + 5k = 74.75
anonymous
  • anonymous
how do you do that? sorry
anonymous
  • anonymous
are you allowed to use a calculator on tests?
anonymous
  • anonymous
no
anonymous
  • anonymous
hmm ok, the easiest way would be either elimination or substitution, which do you prefer?
anonymous
  • anonymous
substitution
anonymous
  • anonymous
what is the last sentence supposed to say? "How much does the Ramirez family have to pay with adults and four kids"
anonymous
  • anonymous
its missing the number of adults
anonymous
  • anonymous
with four adults and four kids
anonymous
  • anonymous
a. y=45+3k?
anonymous
  • anonymous
ok solve one of those 2 equations for either a or k, you choose
anonymous
  • anonymous
hmm close but not quite
anonymous
  • anonymous
2a + 3k = 47, lets solve for a, so first subtract 3k from both sides
anonymous
  • anonymous
2a = 47 - 3k, now divide both sides by 2
anonymous
  • anonymous
22
anonymous
  • anonymous
no, a = (47 - 3k) / 2
anonymous
  • anonymous
do you understand?
anonymous
  • anonymous
and what will be the answer
anonymous
  • anonymous
to the whole problem?
anonymous
  • anonymous
just to the first one
anonymous
  • anonymous
we are working on it
anonymous
  • anonymous
do you understand how we got a = (47 - 3k) / 2
anonymous
  • anonymous
yes
anonymous
  • anonymous
ok so now you know the value of a, we cannot plug it back into the same equation because we will not get any new information, so lets plug it into the other equation
anonymous
  • anonymous
can you please plug what we found for a, into the other equation?
anonymous
  • anonymous
3a=74.75-5k
anonymous
  • anonymous
thats true but you need to plug what we found for a into that equation
anonymous
  • anonymous
so that we can solve for k
anonymous
  • anonymous
can u plug it in.. I'm kinda lost
anonymous
  • anonymous
ok lets start again, because me doing it for you wont help anyone
anonymous
  • anonymous
we have these two equations that we came up with 2a + 3k = 47 3a + 5k = 74.75
anonymous
  • anonymous
we looked at the first equation and solved for a 2a + 3k = 47 2a = 47 - 3k a = (47 - 3k) / 2
anonymous
  • anonymous
now we plug that value for a, into the second equation 3a + 5k = 74.75 3(plug in here) + 5k = 74.75
anonymous
  • anonymous
go for it
anonymous
  • anonymous
3(47-3k)+5k=74.75
anonymous
  • anonymous
thats very close but you left out the divide by 2, i will put it in for you 3((47-3k)/2)+5k=74.75
anonymous
  • anonymous
$$3*\frac{47-3k}{2} + 5k = 74.75$$
anonymous
  • anonymous
now you need to solve that for k
anonymous
  • anonymous
by the way elimination method would have been much easier, but thats ok this is good practice
anonymous
  • anonymous
so solve that for k and what do you get for k?
anonymous
  • anonymous
im not sure how you do it
anonymous
  • anonymous
maybe it will help to write (47 - 3k) / 2 as separate fractions, can you do that?

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