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set up some equations

what kind??

Jones family:
2*adults + 3*kids = $47 total
2*a + 3*k = 47
2a + 3k = 47

all three of those equations represent the same thing

can you set up an equation for the Smith family now?

how do you do that? sorry

are you allowed to use a calculator on tests?

no

hmm ok, the easiest way would be either elimination or substitution, which do you prefer?

substitution

its missing the number of adults

with four adults and four kids

a. y=45+3k?

ok solve one of those 2 equations for either a or k, you choose

hmm close but not quite

2a + 3k = 47, lets solve for a, so first subtract 3k from both sides

2a = 47 - 3k, now divide both sides by 2

22

no, a = (47 - 3k) / 2

do you understand?

and what will be the answer

to the whole problem?

just to the first one

we are working on it

do you understand how we got a = (47 - 3k) / 2

yes

can you please plug what we found for a, into the other equation?

3a=74.75-5k

thats true but you need to plug what we found for a into that equation

so that we can solve for k

can u plug it in.. I'm kinda lost

ok lets start again, because me doing it for you wont help anyone

we have these two equations that we came up with
2a + 3k = 47
3a + 5k = 74.75

we looked at the first equation and solved for a
2a + 3k = 47
2a = 47 - 3k
a = (47 - 3k) / 2

now we plug that value for a, into the second equation
3a + 5k = 74.75
3(plug in here) + 5k = 74.75

go for it

3(47-3k)+5k=74.75

thats very close but you left out the divide by 2, i will put it in for you
3((47-3k)/2)+5k=74.75

$$3*\frac{47-3k}{2} + 5k = 74.75$$

now you need to solve that for k

by the way elimination method would have been much easier, but thats ok this is good practice

so solve that for k and what do you get for k?

im not sure how you do it

maybe it will help to write (47 - 3k) / 2 as separate fractions, can you do that?