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anonymous

  • one year ago

The Jones family attends a movie for $47.00 with two adults and three kids. The Smith family attends when some friends are in town for $74.75 with three adults and five kids. How much does the Ramirez family have to pay with adults and four kids

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  1. anonymous
    • one year ago
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    set up some equations

  2. anonymous
    • one year ago
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    what kind??

  3. anonymous
    • one year ago
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    Jones family: 2*adults + 3*kids = $47 total 2*a + 3*k = 47 2a + 3k = 47

  4. anonymous
    • one year ago
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    all three of those equations represent the same thing

  5. anonymous
    • one year ago
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    can you set up an equation for the Smith family now?

  6. anonymous
    • one year ago
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    3a+5k=74.75 whats next?? @bi

  7. anonymous
    • one year ago
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    perfect now you have two equations and two unknowns, can you solve this system for a and k? 2a + 3k = 47 3a + 5k = 74.75

  8. anonymous
    • one year ago
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    how do you do that? sorry

  9. anonymous
    • one year ago
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    are you allowed to use a calculator on tests?

  10. anonymous
    • one year ago
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    no

  11. anonymous
    • one year ago
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    hmm ok, the easiest way would be either elimination or substitution, which do you prefer?

  12. anonymous
    • one year ago
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    substitution

  13. anonymous
    • one year ago
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    what is the last sentence supposed to say? "How much does the Ramirez family have to pay with adults and four kids"

  14. anonymous
    • one year ago
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    its missing the number of adults

  15. anonymous
    • one year ago
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    with four adults and four kids

  16. anonymous
    • one year ago
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    a. y=45+3k?

  17. anonymous
    • one year ago
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    ok solve one of those 2 equations for either a or k, you choose

  18. anonymous
    • one year ago
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    hmm close but not quite

  19. anonymous
    • one year ago
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    2a + 3k = 47, lets solve for a, so first subtract 3k from both sides

  20. anonymous
    • one year ago
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    2a = 47 - 3k, now divide both sides by 2

  21. anonymous
    • one year ago
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    22

  22. anonymous
    • one year ago
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    no, a = (47 - 3k) / 2

  23. anonymous
    • one year ago
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    do you understand?

  24. anonymous
    • one year ago
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    and what will be the answer

  25. anonymous
    • one year ago
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    to the whole problem?

  26. anonymous
    • one year ago
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    just to the first one

  27. anonymous
    • one year ago
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    we are working on it

  28. anonymous
    • one year ago
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    do you understand how we got a = (47 - 3k) / 2

  29. anonymous
    • one year ago
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    yes

  30. anonymous
    • one year ago
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    ok so now you know the value of a, we cannot plug it back into the same equation because we will not get any new information, so lets plug it into the other equation

  31. anonymous
    • one year ago
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    can you please plug what we found for a, into the other equation?

  32. anonymous
    • one year ago
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    3a=74.75-5k

  33. anonymous
    • one year ago
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    thats true but you need to plug what we found for a into that equation

  34. anonymous
    • one year ago
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    so that we can solve for k

  35. anonymous
    • one year ago
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    can u plug it in.. I'm kinda lost

  36. anonymous
    • one year ago
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    ok lets start again, because me doing it for you wont help anyone

  37. anonymous
    • one year ago
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    we have these two equations that we came up with 2a + 3k = 47 3a + 5k = 74.75

  38. anonymous
    • one year ago
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    we looked at the first equation and solved for a 2a + 3k = 47 2a = 47 - 3k a = (47 - 3k) / 2

  39. anonymous
    • one year ago
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    now we plug that value for a, into the second equation 3a + 5k = 74.75 3(plug in here) + 5k = 74.75

  40. anonymous
    • one year ago
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    go for it

  41. anonymous
    • one year ago
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    3(47-3k)+5k=74.75

  42. anonymous
    • one year ago
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    thats very close but you left out the divide by 2, i will put it in for you 3((47-3k)/2)+5k=74.75

  43. anonymous
    • one year ago
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    $$3*\frac{47-3k}{2} + 5k = 74.75$$

  44. anonymous
    • one year ago
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    now you need to solve that for k

  45. anonymous
    • one year ago
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    by the way elimination method would have been much easier, but thats ok this is good practice

  46. anonymous
    • one year ago
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    so solve that for k and what do you get for k?

  47. anonymous
    • one year ago
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    im not sure how you do it

  48. anonymous
    • one year ago
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    maybe it will help to write (47 - 3k) / 2 as separate fractions, can you do that?

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