The Jones family attends a movie for $47.00 with two adults and three kids. The Smith family attends when some friends are in town for $74.75 with three adults and five kids. How much does the Ramirez family have to pay with adults and four kids

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The Jones family attends a movie for $47.00 with two adults and three kids. The Smith family attends when some friends are in town for $74.75 with three adults and five kids. How much does the Ramirez family have to pay with adults and four kids

Mathematics
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set up some equations
what kind??
Jones family: 2*adults + 3*kids = $47 total 2*a + 3*k = 47 2a + 3k = 47

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Other answers:

all three of those equations represent the same thing
can you set up an equation for the Smith family now?
3a+5k=74.75 whats next?? @bi
perfect now you have two equations and two unknowns, can you solve this system for a and k? 2a + 3k = 47 3a + 5k = 74.75
how do you do that? sorry
are you allowed to use a calculator on tests?
no
hmm ok, the easiest way would be either elimination or substitution, which do you prefer?
substitution
what is the last sentence supposed to say? "How much does the Ramirez family have to pay with adults and four kids"
its missing the number of adults
with four adults and four kids
a. y=45+3k?
ok solve one of those 2 equations for either a or k, you choose
hmm close but not quite
2a + 3k = 47, lets solve for a, so first subtract 3k from both sides
2a = 47 - 3k, now divide both sides by 2
22
no, a = (47 - 3k) / 2
do you understand?
and what will be the answer
to the whole problem?
just to the first one
we are working on it
do you understand how we got a = (47 - 3k) / 2
yes
ok so now you know the value of a, we cannot plug it back into the same equation because we will not get any new information, so lets plug it into the other equation
can you please plug what we found for a, into the other equation?
3a=74.75-5k
thats true but you need to plug what we found for a into that equation
so that we can solve for k
can u plug it in.. I'm kinda lost
ok lets start again, because me doing it for you wont help anyone
we have these two equations that we came up with 2a + 3k = 47 3a + 5k = 74.75
we looked at the first equation and solved for a 2a + 3k = 47 2a = 47 - 3k a = (47 - 3k) / 2
now we plug that value for a, into the second equation 3a + 5k = 74.75 3(plug in here) + 5k = 74.75
go for it
3(47-3k)+5k=74.75
thats very close but you left out the divide by 2, i will put it in for you 3((47-3k)/2)+5k=74.75
$$3*\frac{47-3k}{2} + 5k = 74.75$$
now you need to solve that for k
by the way elimination method would have been much easier, but thats ok this is good practice
so solve that for k and what do you get for k?
im not sure how you do it
maybe it will help to write (47 - 3k) / 2 as separate fractions, can you do that?

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