A fertilizer sample, as received, contains 24.0% P2O5 and 5.00% H2O. The sample is oven dried and %H2O becomes 0.50%. Calculate the %P2O5 in the oven dried sample.
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
1) consider the % as a grams, then your original sample will be 24.0g of P2O5, 5.00 g H2O and the rest 71.0 g of something else that we don't know what it is and we assume that is not volatile and will evaporate at the temperature used to drie the H2o from sample.
2) after evaporation your water is going to be 0.05 g in place of the original 5.00g. Your total sample is not going to be 100g but 100g -( 5.00g - 0.05g) = 100-4.95= 95.05g
3) Since the mass of P2O5 has not changed, now you can calculate the % of P2O5 in the dried sample considering the original mass of the P2O5 (24.0g) and the new mass of the dried sample (95.05g)
100 x 24.0g /95.05 = 25.25%