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So do i have to do the same thing i did for part a but repeat it for x = 0 and x = 1?

okay and for part c i do tht for x = 3 all the way up to 9? that would take forever...

Otherwise you're right, it is a bunch of boring calculation :P

I dont understand

Im sorry I still dont get it

yeah

btw i think i solved part b is it 0.196?

It is :) So do you agree that P(x > 2) = 1 - P(x <= 2)?

I dont understand that formula

It comes from what I said above combined with the fact that is x is not > 2, then it is <= 2.

okay that makes sense

Alright. So can you find P(x <= 2)?

i did c9,1(0.3)^2(0.7)^9-1 and the same this for 0 to get 0.196

i used an online calculator to solve it because i dont know how to do it on my calclator

0.196 is P(x < 2), but you need P(x <= 2)

no part b says just less than 2
and i found out how to do it on my calculator had to use the nCr key

I mean for part C, since we know that P(x > 2) = 1 - P(x <= 2)

so would P(x <=2) be 0.267 + 0.196?

Yes. Then you can find the answer to C

so c would be 1 - (0.267+0.196)?

Yep!

Wow! thank you I actually understand what you were trying to say earlier

okay so how would i go about doing part d?

is it asking to find x = 3?

Well if 2 <= x <= 4 then that means x can be 2, 3, or 4.

right so how can i approach this?

would i have to solve for x = 2,3,4?

:( okay well atleast I know how to do these srot of questions thank you so much JE!

No worries, glad I could help! :)