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anonymous
 one year ago
Find P(X <= k) in each case:
a) n=20, p=0.05, k=2
b) n=15, p=0.7, k=8
c) n=10, p=0.9, k=9
Please help! I don't need the answers, I just need to know how to do the questions.
anonymous
 one year ago
Find P(X <= k) in each case: a) n=20, p=0.05, k=2 b) n=15, p=0.7, k=8 c) n=10, p=0.9, k=9 Please help! I don't need the answers, I just need to know how to do the questions.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0plug in the given values into the appropriate place

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im confused, plug them into what?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what type of calculator do you have?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay well whats the formula i would use on paper if i was to do it by hand?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what class is this for?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0statistics for the sciences

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0P(X≤k) = P(X=0) + P(X=1) + ...+ P(X=k)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0does that look familiar?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah i know how to do that but am i really supposed to do that all the way up to 20?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well im doing this on paper i guess i can show my work for the first one and write P(x=2) +>P(x=20) = ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you think that would be okay?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have no idea, depends on what your teacher wants

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not sure tbh well if theres a faster way i think it would be better to do it that way bc atleast all my work will be shown

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you have a binomcdf function on your calculator?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just a quick tip, for the last one, instead of doing P(x=0) all the way up to P(x=9), you can just do 1  P(x = 10). I think you can use a similar method for the 2nd part. Either do that or just use your calculator like you've been saying :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont know how to calculate this question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0JE so for part a can i do 1  P(x=20)? to get the answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, for part a you should just do P(x=0) + P(x=1) + P(x=2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you find for any question like this you have to sum a load of things then it might be better to do 1  the things that aren't in the sum, just to simplify calculations.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but why cant i do this for part a?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You could, but you'd be doing 1  P(x=20)  P(x=19)  P(x=18)  P(x=17)  ...  P(x=3) which is a lot of calculation. It's much easier in this case to do P(x=0) + P(x=1) + P(x=2).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0all the way up to 20?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, just up to 2. If you're calculating P(x<=k) then you sum from 0 to k, since x can only take the values 0, 1, 2, 3, ..., k if it is <=k.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Like on that other question, you can use P(x<=k) = 1P(x>k) if it makes the calculations easier, which is very useful for the last part!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so i do P(x=0) + P(x=1) + P(x=2) and then  1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You don't need the 1 but yes. Essentially you're doing P(x <= 2), so this means x can only take the values 0, 1, 2. You'd only need to do 1  (stuff) if you were trying to calculate P(x > 2).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so i just add up P(x=0) + P(x=1) + P(x=2) to get the answer for a?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay I got 0.924 for a)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how about for b and c the k values are pretty high

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For b I think you're just going to have to add up all the stuff again; but as billj5 was saying your calculator might have a function to calculate P(x<=8) for you, if you know about it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah well you may just have to do the sum :P Maybe ask someone who you can show your calculator to if it has this function?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay well thank you again JE!
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