## anonymous one year ago You are making poster board boundary markers in the shape of square pyramids for a relay race. If you are including a ten -inch square as the bottom and you want the slant height to be twelve inches, how much poster board do you need?

1. anonymous

three hundred forty square inches three hundred sixty square inches three hundred eighty-four square inches four hundred square inches

2. anonymous

3. anonymous

In other words, we're finding the surface area of a square pyramid, right?

4. anonymous

here i think not sure but here is an image that may be that or not if it is not then yea your right sorry get confuse with shapeshttp ://learn.flvs.net/webdav/assessment_images/educator_math2/v9/07_TB_39_240.jpg

5. anonymous
6. anonymous

I got a cookie error for the image /:

7. anonymous

really okay give me a second

8. anonymous

this is from a different test question but just to give an idea if that the shape we think it is

9. anonymous

Well anyways. With the info we have, we can put it into the formula $\huge (a^{2})+(4*\frac{1}{2}*sh*a)$ with a being the side of the square and sh being the slant height

10. anonymous

You there?

11. anonymous

yea just calculating and i also went to make coffee for my mom :D

12. anonymous

250 is that it

13. anonymous

What did you use for a and what did you use for sh?

14. anonymous

10 for the area and 12 for the slant height

15. anonymous

So $\large 10^{2}=~?$

16. anonymous

20

17. anonymous

100

18. anonymous

i am dummy its 100

19. anonymous

Ok yeah, 100. So $\large 4*\frac{1}{2}*12*10=~?$

20. anonymous

240 + 100 = 340

21. anonymous

Right! So 340 is gonna be our answer :)

22. anonymous

yay thank you so much i keep that formula in mind

23. anonymous

$\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile$

24. anonymous

cool how did you do that

25. anonymous

Latex writing, see the code-like writing in my bio?

26. anonymous

cool okay thanks for the help