## anonymous one year ago A heat engine has a hot reservoir of 680°C and a cold reservoir of 220°C. What is the efficiency of the engine

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1. anonymous

@danish071996

2. anonymous

@Australopithecus

3. Hayleymeyer

220C = 428F 680C= 1257 F

4. anonymous

a 58.3% b 75.9% c 62.3% d 72.1% e 67.6%

5. Hayleymeyer

grr lol

6. Australopithecus

$%\ efficiency\ = (1-\frac{(T_{cold}}{T_{hot}})*100$

7. anonymous

?

8. Australopithecus

This is the formula you need $efficiency\ percent = (1 - \frac{T_{cold}}{T_{hot}})*100$

9. Australopithecus

Where Temperature is in kelvin, so add 273 to each of your temperatures.