nuccioreggie
  • nuccioreggie
Solve x^3 = 64 over 27
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
nuccioreggie
  • nuccioreggie
@LegendarySadist
nuccioreggie
  • nuccioreggie
@Nnesha
anonymous
  • anonymous
\[x^3=\frac{ 64 }{ 27 },27x^3-64=0\] \[\left( 3x \right)^3-3^3=0\] \[a^3-b^3=\left( a-b \right)\left( a^2+ab+b^2 \right)\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

nuccioreggie
  • nuccioreggie
So is it. C
anonymous
  • anonymous
i don;t see options.
nuccioreggie
  • nuccioreggie
Solve x3 = 64 over 27. ±8 over 3 8 over 3 ±4 over 3 4 over 3
anonymous
  • anonymous
correction \[\left( 3x \right)^3-4^3=0\]only real value is 3x-4=0 \[x=\frac{ 4 }{ 3 }\]
nuccioreggie
  • nuccioreggie
So its D right
Loser66
  • Loser66
\(64 = ?^3\)
Loser66
  • Loser66
\(27=??^3\)
Loser66
  • Loser66
\(x^3 =\dfrac{64}{27}=\dfrac{?^3}{??^3}=(\dfrac{?}{??})^3\) hence \(x= \dfrac{?}{??}\) your duty is find out what are ? and ??
nuccioreggie
  • nuccioreggie
@Loser66. D
nuccioreggie
  • nuccioreggie
So its D right @Nnesha

Looking for something else?

Not the answer you are looking for? Search for more explanations.