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bry856

  • one year ago

If f(x)=x^3−x, what is the average rate of change of f(x) over the interval [1, 5]? a)29.5 b)30 c)43 d)120

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  1. geerky42
    • one year ago
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    Generally, average rate of change of f(x) in interval [a, b] is \[\large \dfrac{f(b)-f(a)}{b-a}\]

  2. geerky42
    • one year ago
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    So here you just have \(\dfrac{f(5)-f(1)}{5-1}=~\cdots~?\)

  3. bry856
    • one year ago
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    what, i dont know how to solve that im sorry

  4. anonymous
    • one year ago
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    @geerky42 did a good work

  5. Rhystic
    • one year ago
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    you just plug in the 5 value into the equation you have subtract it by the equation with 1 plugged in and then put it over 5-1 which is 4.

  6. anonymous
    • one year ago
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    nothing left just put the numbers

  7. Rhystic
    • one year ago
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    you're solving wrong. what did you get for 5^3-5 ?

  8. Rhystic
    • one year ago
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    it should be ->( (5^3-5)-(1^3-1))/4

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