anonymous
  • anonymous
plz help!
Mathematics
chestercat
  • chestercat
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SanjanaP
  • SanjanaP
What's up!
Hayleymeyer
  • Hayleymeyer
alrighttty <3
anonymous
  • anonymous
\[\left(\begin{matrix}5x ^{-2}y ^{5} \\ 4x ^{6}y ^{3}\end{matrix}\right)\]

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anonymous
  • anonymous
to the \[^{-2}\]
anonymous
  • anonymous
Division? Matrix?
anonymous
  • anonymous
division
anonymous
  • anonymous
So \[\huge( \large \frac{5x^{-2}y^{5}}{4x^{6}y^{3}} \huge )^{\large -2}~\large ?\]
anonymous
  • anonymous
yes
anonymous
  • anonymous
Well first let's apply the exponent outside of the parentheses. We're gonna use two properties to do this. The first is \[\large (\frac{x}{y})^{2}=(\frac{x^{2}}{y^{2}})\] and the second is \[\large (a^{x})^{x}=(a)^{x \times x}\] Do you know how these will be applied?
anonymous
  • anonymous
no
anonymous
  • anonymous
It means that the -2 outside the parentheses will be multiplied by the exponents of both the numerator and denominators.
anonymous
  • anonymous
oh
anonymous
  • anonymous
thank you
anonymous
  • anonymous
Do you think you will be able to take it from there?
anonymous
  • anonymous
yes

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