perfect square?

- anonymous

perfect square?

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- schrodinger

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- anonymous

@geerky42 do you know about perfect squares, sorry to bother you

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- anonymous

@texaschic101

- anonymous

I'm pretty sure that to create a perfect square trinomial you divide the middle term by 2, square it, and then add it to the expression so it is the 3rd term

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- anonymous

@RiOT so to square 4w it would be 4w^2

- anonymous

what about this did i do this right?

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- anonymous

sorry, just the coefficent, so it would be 4^2

- anonymous

oh but why just the coefficient

- anonymous

have you learned about completing the square?

- anonymous

yeah sorry that was a stupid question my bad

- anonymous

are you in algebra 2? i'm doing it right now and so I could be wrong but I believe that's what this is

- anonymous

no, no problem

- anonymous

@RiOT did i do the second one right

- anonymous

I'm doing a college math but like sometimes when you just put the coefficient i get it wrong

- anonymous

I'm sorry, I'm not sure about the second one

- anonymous

hmm well i got 3.35078106, or 0.14921894

- anonymous

so i have to round to the nearest hundredth

- anonymous

so wouldn't it be 4.3

- anonymous

I'm not saying you're wrong, I'm just not 100% sure how to solve that problem. I'm sorry :/

- anonymous

@geerky42 any input

- anonymous

@riot np

- anonymous

@peachpi any input on my second question

- geerky42

Check again. There is more than one solution.

- anonymous

yeah 3.35078106, and 0.14921894

- anonymous

so you're saying i show go for 0.14921894 @geerky42

- anonymous

@geerky42 then wouldn't it be 1.1 by rounding to the nearest hundredth

- anonymous

or 1.14

- geerky42

Yes that one, but that's not how you rounding.

- geerky42

You just rounding to nearest hundredth
For example: |dw:1433958363553:dw|

- geerky42

Which is \(0.15\)

- anonymous

ah i see sorry well one more check please i believe it's correct @geerky42

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- geerky42

It's ok and you are correct.

- anonymous

ok thanks and hey i remember you telling me something about the local minimum and maxima but just to double check man sorry @geerky42

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- anonymous

@geerky42

- geerky42

|dw:1433959525927:dw|

- geerky42

|dw:1433959551853:dw|

- geerky42

So local minimums are|dw:1433959575568:dw| here, right?

- geerky42

So for first answer, you need x-values where local minimums occur.

- anonymous

so -2,-3 @geerky42

- anonymous

-2 would be the x value

- geerky42

Close. It's -2 and 3.

- anonymous

but how is it positive 3

- anonymous

and I'm assuming the second answer is ok

- geerky42

|dw:1433959794678:dw|

- anonymous

and i got it so what about this

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- geerky42

Second answer isn't 3,3.
Same as last time, but y-values instead.

- anonymous

wait but last time i had this right dammit this is confusing

- geerky42

Seen in picture, you entered 0, 3 for second part.

- geerky42

I believe it should be -3, 0

- anonymous

ok for the first one its not 3,3 it -2,3 because the x values where the local minimums occur so for the y values -3,0

- anonymous

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- geerky42

\(\color{blue}{\text{Originally Posted by}}\) @Mromanos96
ok for the first one its not 3,3 it -2,3 because the x values where the local minimums occur so for the y values -3,0
\(\color{blue}{\text{End of Quote}}\)
That's correct.

- anonymous

i believe that is correct

- geerky42

yeah this is correct.

- anonymous

ah ok thanks @geerky42

- anonymous

srry i just like to go over all my test answers before submitting them man

- geerky42

you also are correct about \((x-4)^2\) part.

- anonymous

thanks i think i have the rest right ill make another thread if i need help man

- geerky42

OK no problem

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