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anonymous

  • one year ago

perfect square?

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  1. anonymous
    • one year ago
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    @geerky42 do you know about perfect squares, sorry to bother you

  2. anonymous
    • one year ago
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    @texaschic101

  3. anonymous
    • one year ago
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    I'm pretty sure that to create a perfect square trinomial you divide the middle term by 2, square it, and then add it to the expression so it is the 3rd term

  4. anonymous
    • one year ago
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    @RiOT so to square 4w it would be 4w^2

  5. anonymous
    • one year ago
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    what about this did i do this right?

  6. anonymous
    • one year ago
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    sorry, just the coefficent, so it would be 4^2

  7. anonymous
    • one year ago
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    oh but why just the coefficient

  8. anonymous
    • one year ago
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    have you learned about completing the square?

  9. anonymous
    • one year ago
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    yeah sorry that was a stupid question my bad

  10. anonymous
    • one year ago
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    are you in algebra 2? i'm doing it right now and so I could be wrong but I believe that's what this is

  11. anonymous
    • one year ago
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    no, no problem

  12. anonymous
    • one year ago
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    @RiOT did i do the second one right

  13. anonymous
    • one year ago
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    I'm doing a college math but like sometimes when you just put the coefficient i get it wrong

  14. anonymous
    • one year ago
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    I'm sorry, I'm not sure about the second one

  15. anonymous
    • one year ago
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    hmm well i got 3.35078106, or 0.14921894

  16. anonymous
    • one year ago
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    so i have to round to the nearest hundredth

  17. anonymous
    • one year ago
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    so wouldn't it be 4.3

  18. anonymous
    • one year ago
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    I'm not saying you're wrong, I'm just not 100% sure how to solve that problem. I'm sorry :/

  19. anonymous
    • one year ago
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    @geerky42 any input

  20. anonymous
    • one year ago
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    @riot np

  21. anonymous
    • one year ago
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    @peachpi any input on my second question

  22. geerky42
    • one year ago
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    Check again. There is more than one solution.

  23. anonymous
    • one year ago
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    yeah 3.35078106, and 0.14921894

  24. anonymous
    • one year ago
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    so you're saying i show go for 0.14921894 @geerky42

  25. anonymous
    • one year ago
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    @geerky42 then wouldn't it be 1.1 by rounding to the nearest hundredth

  26. anonymous
    • one year ago
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    or 1.14

  27. geerky42
    • one year ago
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    Yes that one, but that's not how you rounding.

  28. geerky42
    • one year ago
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    You just rounding to nearest hundredth For example: |dw:1433958363553:dw|

  29. geerky42
    • one year ago
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    Which is \(0.15\)

  30. anonymous
    • one year ago
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    ah i see sorry well one more check please i believe it's correct @geerky42

  31. geerky42
    • one year ago
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    It's ok and you are correct.

  32. anonymous
    • one year ago
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    ok thanks and hey i remember you telling me something about the local minimum and maxima but just to double check man sorry @geerky42

  33. anonymous
    • one year ago
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    @geerky42

  34. geerky42
    • one year ago
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    |dw:1433959525927:dw|

  35. geerky42
    • one year ago
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    |dw:1433959551853:dw|

  36. geerky42
    • one year ago
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    So local minimums are|dw:1433959575568:dw| here, right?

  37. geerky42
    • one year ago
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    So for first answer, you need x-values where local minimums occur.

  38. anonymous
    • one year ago
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    so -2,-3 @geerky42

  39. anonymous
    • one year ago
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    -2 would be the x value

  40. geerky42
    • one year ago
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    Close. It's -2 and 3.

  41. anonymous
    • one year ago
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    but how is it positive 3

  42. anonymous
    • one year ago
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    and I'm assuming the second answer is ok

  43. geerky42
    • one year ago
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    |dw:1433959794678:dw|

  44. anonymous
    • one year ago
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    and i got it so what about this

  45. geerky42
    • one year ago
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    Second answer isn't 3,3. Same as last time, but y-values instead.

  46. anonymous
    • one year ago
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    wait but last time i had this right dammit this is confusing

  47. geerky42
    • one year ago
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    Seen in picture, you entered 0, 3 for second part.

  48. geerky42
    • one year ago
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    I believe it should be -3, 0

  49. anonymous
    • one year ago
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    ok for the first one its not 3,3 it -2,3 because the x values where the local minimums occur so for the y values -3,0

  50. anonymous
    • one year ago
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  51. geerky42
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Mromanos96 ok for the first one its not 3,3 it -2,3 because the x values where the local minimums occur so for the y values -3,0 \(\color{blue}{\text{End of Quote}}\) That's correct.

  52. anonymous
    • one year ago
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    i believe that is correct

  53. geerky42
    • one year ago
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    yeah this is correct.

  54. anonymous
    • one year ago
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    ah ok thanks @geerky42

  55. anonymous
    • one year ago
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    srry i just like to go over all my test answers before submitting them man

  56. geerky42
    • one year ago
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    you also are correct about \((x-4)^2\) part.

  57. anonymous
    • one year ago
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    thanks i think i have the rest right ill make another thread if i need help man

  58. geerky42
    • one year ago
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    OK no problem

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