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mathmath333
 one year ago
fun question
mathmath333
 one year ago
fun question

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.2solve for \(y,\ \ y\in \mathbb{R}\) \(\large \color{black}{\begin{align} y+k=4\hspace{.33em}\\~\\ \end{align}}\) where roots of \(2x^2(5k+4)+7=0\) are equal in magnitude and opposite in sign.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5is there a "x" missing in the middle term of given quadratic equation ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5\[2x^2(5k+4)\color{red}{x}+7=0\]

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.2yes u r right x was missing

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.2solve for \(y,\ \ y\in \mathbb{R}\) \(\large \color{black}{\begin{align} y+k=4\hspace{.33em}\\~\\ \end{align}}\) where roots of \(2x^2(5k+4)x+7=0\) are equal in magnitude and opposite in sign.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5but how can absolute value be negative ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5oh trick question is it xD \[y\in \emptyset\]

alekos
 one year ago
Best ResponseYou've already chosen the best response.0that's exactly what i was wondering

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.2initially u fell for the trap

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 how old are you (exited to know)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5haha that negative symbol is too small to notice

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.2haha small little question , no real solution

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.2i hope every body understood the trick
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