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mathmath333

  • one year ago

fun question

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  1. anonymous
    • one year ago
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    ?

  2. mathmath333
    • one year ago
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    solve for \(y,\ \ y\in \mathbb{R}\) \(\large \color{black}{\begin{align} |y+k|=-4\hspace{.33em}\\~\\ \end{align}}\) where roots of \(2x^2-(5k+4)+7=0\) are equal in magnitude and opposite in sign.

  3. Elsa213
    • one year ago
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    how is this fun? ;~;

  4. ganeshie8
    • one year ago
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    is there a "x" missing in the middle term of given quadratic equation ?

  5. ganeshie8
    • one year ago
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    \[2x^2-(5k+4)\color{red}{x}+7=0\]

  6. mathmath333
    • one year ago
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    let me see ,wait

  7. mathmath333
    • one year ago
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    yes u r right x was missing

  8. mathmath333
    • one year ago
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    solve for \(y,\ \ y\in \mathbb{R}\) \(\large \color{black}{\begin{align} |y+k|=-4\hspace{.33em}\\~\\ \end{align}}\) where roots of \(2x^2-(5k+4)x+7=0\) are equal in magnitude and opposite in sign.

  9. ganeshie8
    • one year ago
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    but how can absolute value be negative ?

  10. mathmath333
    • one year ago
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    :)

  11. ganeshie8
    • one year ago
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    oh trick question is it xD \[y\in \emptyset\]

  12. alekos
    • one year ago
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    that's exactly what i was wondering

  13. mathmath333
    • one year ago
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    initially u fell for the trap

  14. anonymous
    • one year ago
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    @ganeshie8 how old are you (exited to know)

  15. ganeshie8
    • one year ago
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    haha that negative symbol is too small to notice

  16. mathmath333
    • one year ago
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    haha small little question , no real solution

  17. mathmath333
    • one year ago
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    i hope every body understood the trick

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spraguer (Moderator)
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