gabbyalicorn one year ago https://www.dropbox.com/s/im7menys1mzphct/Screenshot%202015-06-10%2011.14.45.png?dl=0

1. gabbyalicorn

@Michele_Laino

2. gabbyalicorn

3. gabbyalicorn

Also, would this count as statistics?

4. Michele_Laino

I think it is the weighted average

5. gabbyalicorn

oh.

6. gabbyalicorn

The sentence just doesn't make sense to me.

7. gabbyalicorn

I don't get what it's asking. D:

8. Michele_Laino

I think that your exercise is asking for the best value of the quantity which is represented by your distribution here is the value of the weighted average: $\frac{{2 + 3 + 2 \times 3 + 2 \times 4 + 3 \times 5 + 4 \times 6 + 3 \times 7 + 3 \times 8 + 2 \times 9 + 11}}{{22}}$

9. gabbyalicorn

i got 65920.590909 :/

10. gabbyalicorn

Could it just be 66 (i rounded)

11. Michele_Laino

no, please here are more steps: $\begin{gathered} \frac{{2 + 3 + 2 \times 3 + 2 \times 4 + 3 \times 5 + 4 \times 6 + 3 \times 7 + 3 \times 8 + 2 \times 9 + 11}}{{22}} = \hfill \\ \hfill \\ = \frac{{5 + 6 + 8 + 15 + 24 + 21 + 24 + 18 + 11}}{{22}} = \hfill \\ \hfill \\ = \frac{{34 + 69 + 29}}{{22}} = \frac{{132}}{{22}} = ... \hfill \\ \end{gathered}$

12. gabbyalicorn

-3- okay, I will try...to do this

13. gabbyalicorn

1) 65920.590909 2) 6 3) 6 4) 6

14. Michele_Laino

it is 6

15. gabbyalicorn

:D Yay! Just curious, how did you get all those numbers?

16. Michele_Laino

Sorry I have made an error, in reading your values, here is the right weighted average: $\begin{gathered} \frac{{1 + 2 + 2 \times 3 + 2 \times 4 + 3 \times 5 + 4 \times 6 + 3 \times 7 + 3 \times 8 + 2 \times 9 + 11}}{{22}} = \hfill \\ \hfill \\ = \frac{{3 + 6 + 8 + 15 + 24 + 21 + 24 + 18 + 11}}{{22}} = \hfill \\ \hfill \\ = \frac{{32 + 69 + 29}}{{22}} = \frac{{130}}{{22}} = ... \hfill \\ \end{gathered}$

17. gabbyalicorn

1) 49426.0454545 2) 5.909090 3) 5.909090 4) 5.9090 So, 5.9? or 6

18. Michele_Laino

the right result is 5.9, so we can pick 6

19. Michele_Laino

namely the right answer is 6

20. gabbyalicorn

oh yay! Thank you! Thank you! So much!

21. Michele_Laino

:)