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gabbyalicorn
 one year ago
https://www.dropbox.com/s/im7menys1mzphct/Screenshot%2020150610%2011.14.45.png?dl=0
gabbyalicorn
 one year ago
https://www.dropbox.com/s/im7menys1mzphct/Screenshot%2020150610%2011.14.45.png?dl=0

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gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.0Also, would this count as statistics?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I think it is the weighted average

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.0The sentence just doesn't make sense to me.

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.0I don't get what it's asking. D:

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I think that your exercise is asking for the best value of the quantity which is represented by your distribution here is the value of the weighted average: \[\frac{{2 + 3 + 2 \times 3 + 2 \times 4 + 3 \times 5 + 4 \times 6 + 3 \times 7 + 3 \times 8 + 2 \times 9 + 11}}{{22}}\]

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.0i got 65920.590909 :/

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.0Could it just be 66 (i rounded)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2no, please here are more steps: \[\begin{gathered} \frac{{2 + 3 + 2 \times 3 + 2 \times 4 + 3 \times 5 + 4 \times 6 + 3 \times 7 + 3 \times 8 + 2 \times 9 + 11}}{{22}} = \hfill \\ \hfill \\ = \frac{{5 + 6 + 8 + 15 + 24 + 21 + 24 + 18 + 11}}{{22}} = \hfill \\ \hfill \\ = \frac{{34 + 69 + 29}}{{22}} = \frac{{132}}{{22}} = ... \hfill \\ \end{gathered} \]

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.03 okay, I will try...to do this

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.01) 65920.590909 2) 6 3) 6 4) 6

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.0:D Yay! Just curious, how did you get all those numbers?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2Sorry I have made an error, in reading your values, here is the right weighted average: \[\begin{gathered} \frac{{1 + 2 + 2 \times 3 + 2 \times 4 + 3 \times 5 + 4 \times 6 + 3 \times 7 + 3 \times 8 + 2 \times 9 + 11}}{{22}} = \hfill \\ \hfill \\ = \frac{{3 + 6 + 8 + 15 + 24 + 21 + 24 + 18 + 11}}{{22}} = \hfill \\ \hfill \\ = \frac{{32 + 69 + 29}}{{22}} = \frac{{130}}{{22}} = ... \hfill \\ \end{gathered} \]

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.01) 49426.0454545 2) 5.909090 3) 5.909090 4) 5.9090 So, 5.9? or 6

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2the right result is 5.9, so we can pick 6

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2namely the right answer is 6

gabbyalicorn
 one year ago
Best ResponseYou've already chosen the best response.0oh yay! Thank you! Thank you! So much!
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